Math worksheet for practicing square roots of perfect squares.

Let's solve each of the square roots of perfect squares step by step. A perfect square is a number that is the square of an integer, so its square root is also an integer.

We will evaluate each expression:

---

1. $ \sqrt{9} = 3 $
Because $ 3^2 = 9 $

2. $ \sqrt{100} = 10 $
Because $ 10^2 = 100 $

3. $ \sqrt{16} = 4 $
Because $ 4^2 = 16 $

4. $ \sqrt{16} = 4 $
Same as #3

5. $ \sqrt{1} = 1 $
Because $ 1^2 = 1 $

6. $ \sqrt{25} = 5 $
Because $ 5^2 = 25 $

7. $ \sqrt{144} = 12 $
Because $ 12^2 = 144 $

8. $ \sqrt{81} = 9 $
Because $ 9^2 = 81 $

9. $ \sqrt{64} = 8 $
Because $ 8^2 = 64 $

10. $ \sqrt{400} = 20 $
Because $ 20^2 = 400 $

11. $ \sqrt{121} = 11 $
Because $ 11^2 = 121 $

12. $ \sqrt{225} = 15 $
Because $ 15^2 = 225 $

13. $ \sqrt{900} = 30 $
Because $ 30^2 = 900 $

14. $ \sqrt{196} = 14 $
Because $ 14^2 = 196 $

15. $ \sqrt{49} = 7 $
Because $ 7^2 = 49 $

16. $ \sqrt{289} = 17 $
Because $ 17^2 = 289 $

17. $ \sqrt{625} = 25 $
Because $ 25^2 = 625 $

18. $ \sqrt{524} = ? $
Wait — 524 is not a perfect square.

Let’s check:
$ 22^2 = 484 $, $ 23^2 = 529 $ → So $ \sqrt{524} $ is not an integer, and since it's listed in a "perfect squares" exercise, this might be a typo.

But wait — let's double-check: Is 524 a perfect square?

No. $ 22^2 = 484 $, $ 23^2 = 529 $, so 524 is between them and not a perfect square.

However, looking at the list again: maybe it's supposed to be 529? That would make sense because $ \sqrt{529} = 23 $. Or possibly 484?

But as written: $ \sqrt{524} $ is not a perfect square.

So either:
- It's a typo (likely meant to be 529), or
- The problem includes non-perfect squares (but the title says "perfect squares").

Given the context, it's likely a typo.

Assuming it's 529, then:

18. $ \sqrt{529} = 23 $

Alternatively, if it's truly 524, then it's not a perfect square, but since the worksheet is titled “Square Roots of Perfect Squares,” we can assume it should be a perfect square.

Let’s suppose it was intended to be 529, which is $ 23^2 $.

---

Final Answers:

| Problem | Answer |
|--------|--------|
| 1. $ \sqrt{9} $ | 3 |
| 2. $ \sqrt{100} $ | 10 |
| 3. $ \sqrt{16} $ | 4 |
| 4. $ \sqrt{16} $ | 4 |
| 5. $ \sqrt{1} $ | 1 |
| 6. $ \sqrt{25} $ | 5 |
| 7. $ \sqrt{144} $ | 12 |
| 8. $ \sqrt{81} $ | 9 |
| 9. $ \sqrt{64} $ | 8 |
| 10. $ \sqrt{400} $ | 20 |
| 11. $ \sqrt{121} $ | 11 |
| 12. $ \sqrt{225} $ | 15 |
| 13. $ \sqrt{900} $ | 30 |
| 14. $ \sqrt{196} $ | 14 |
| 15. $ \sqrt{49} $ | 7 |
| 16. $ \sqrt{289} $ | 17 |
| 17. $ \sqrt{625} $ | 25 |
| 18. $ \sqrt{524} $ | ✘ Not a perfect square (likely typo; probably meant 529) → $ \boxed{23} $ |

---

✔ Note: If #18 is indeed 524, then it's not a perfect square and the square root is irrational (~22.89). But given the context, it's almost certainly a typo for 529.

So, assuming typo:

Answer for #18: $ \sqrt{529} = 23 $

---

✔ Final Answer Sheet (corrected):

1. 3
2. 10
3. 4
4. 4
5. 1
6. 5
7. 12
8. 9
9. 8
10. 20
11. 11
12. 15
13. 30
14. 14
15. 7
16. 17
17. 25
18. 23 *(assuming 529 instead of 524)*

Let me know if you'd like the image corrected or want help with any specific one!