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Worksheet with four math word problems related to area, perimeter, and cost calculations.

Math word problems involving area, perimeter, and cost calculations for flooring, base molding, farm, and banner.

Math word problems involving area, perimeter, and cost calculations for flooring, base molding, farm, and banner.

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Show Answer Key & Explanations Step-by-step solution for: 4TH GRADE MATH - AREA & PERIMETER WORD PROBLEMS — Steemit
Let's solve each problem step by step.

---

Problem 4:


Betty's bedroom is 16 ft. long and 15 ft. wide. She wants to install hardwood flooring. The cost is \$6.00 per square foot. How much is the total cost for the room flooring?

#### Solution:
1. Calculate the area of the bedroom:
\[
\text{Area} = \text{Length} \times \text{Width} = 16 \, \text{ft} \times 15 \, \text{ft} = 240 \, \text{square feet}
\]

2. Calculate the total cost:
\[
\text{Total Cost} = \text{Area} \times \text{Cost per Square Foot} = 240 \, \text{square feet} \times 6 \, \text{\$/square foot} = 1440 \, \text{\$}
\]

#### Answer:
\[
\boxed{1440}
\]

---

Problem 5:


Betty wants to install base molding in the room. The cost is \$3.00 per foot. How much will it cost her?

#### Solution:
1. Calculate the perimeter of the bedroom:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width}) = 2 \times (16 \, \text{ft} + 15 \, \text{ft}) = 2 \times 31 \, \text{ft} = 62 \, \text{ft}
\]

2. Calculate the total cost for the base molding:
\[
\text{Total Cost} = \text{Perimeter} \times \text{Cost per Foot} = 62 \, \text{ft} \times 3 \, \text{\$/foot} = 186 \, \text{\$}
\]

#### Answer:
\[
\boxed{186}
\]

---

Problem 6:


Rosy had a farm with a perimeter of 84 meters. The length of the farm is 12 meters. Find the area of the farm.

#### Solution:
1. Recall the formula for the perimeter of a rectangle:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width})
\]

2. Substitute the given values into the formula:
\[
84 = 2 \times (12 + \text{Width})
\]

3. Solve for the width:
\[
84 = 2 \times (12 + \text{Width})
\]
\[
84 = 24 + 2 \times \text{Width}
\]
\[
84 - 24 = 2 \times \text{Width}
\]
\[
60 = 2 \times \text{Width}
\]
\[
\text{Width} = \frac{60}{2} = 30 \, \text{meters}
\]

4. Calculate the area of the farm:
\[
\text{Area} = \text{Length} \times \text{Width} = 12 \, \text{m} \times 30 \, \text{m} = 360 \, \text{square meters}
\]

#### Answer:
\[
\boxed{360}
\]

---

Problem 7:


Tina and Tony are working on a banner for their school exhibition. The banner is 12 ft by 9 ft. The cloth costs \$3.00 per square foot. Find the total cost of the banner.

#### Solution:
1. Calculate the area of the banner:
\[
\text{Area} = \text{Length} \times \text{Width} = 12 \, \text{ft} \times 9 \, \text{ft} = 108 \, \text{square feet}
\]

2. Calculate the total cost:
\[
\text{Total Cost} = \text{Area} \times \text{Cost per Square Foot} = 108 \, \text{square feet} \times 3 \, \text{\$/square foot} = 324 \, \text{\$}
\]

#### Answer:
\[
\boxed{324}
\]

---

Final Answers:


1. Problem 4: \(\boxed{1440}\)
2. Problem 5: \(\boxed{186}\)
3. Problem 6: \(\boxed{360}\)
4. Problem 7: \(\boxed{324}\)
Parent Tip: Review the logic above to help your child master the concept of perimeter and area word problems worksheet.
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