To solve the problem of finding the perimeter of each polygon, we need to add up the lengths of all the sides of each shape. Let's go through each shape step by step.
Shape a: Triangle
- Sides: 4 cm, 5 cm, 6 cm
- Perimeter = 4 cm + 5 cm + 6 cm = 15 cm
Shape b: Rhombus
- All sides are equal: 9 ft
- Perimeter = 9 ft + 9 ft + 9 ft + 9 ft = 36 ft
Shape c: Pentagon
- Sides: 7 in, 8 in, 7 in, 8 in, 5 in
- Perimeter = 7 in + 8 in + 7 in + 8 in + 5 in = 35 in
Shape d: Parallelogram
- Opposite sides are equal: 12 mm and 10 mm
- Perimeter = 12 mm + 10 mm + 12 mm + 10 mm = 44 mm
Shape e: Trapezoid
- Sides: 4 km, 3 km, 4 km, 2 km
- Perimeter = 4 km + 3 km + 4 km + 2 km = 13 km
Shape f: Irregular Pentagon
- Sides: 6 ft, 3 ft, 4 ft, 4 ft, 8 ft
- Perimeter = 6 ft + 3 ft + 4 ft + 4 ft + 8 ft = 25 ft
Shape g: Triangle
- Sides: 7 cm, 15 cm, 10 cm
- Perimeter = 7 cm + 15 cm + 10 cm = 32 cm
Shape h: Rectangle
- Opposite sides are equal: 11 in and 9 in
- Perimeter = 11 in + 9 in + 11 in + 9 in = 40 in
Shape i: Hexagon
- All sides are equal: 2 m
- Perimeter = 2 m + 2 m + 2 m + 2 m + 2 m + 2 m = 12 m
Final Answers:
-
a: 15 cm
-
b: 36 ft
-
c: 35 in
-
d: 44 mm
-
e: 13 km
-
f: 25 ft
-
g: 32 cm
-
h: 40 in
-
i: 12 m
Boxed Final Answer:
\[
\boxed{15 \text{ cm}, 36 \text{ ft}, 35 \text{ in}, 44 \text{ mm}, 13 \text{ km}, 25 \text{ ft}, 32 \text{ cm}, 40 \text{ in}, 12 \text{ m}}
\]
Parent Tip: Review the logic above to help your child master the concept of perimeter of a polygon worksheet.
