To solve the problem of finding the perimeter of each rectangle, we need to use the formula for the perimeter of a rectangle:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width})
\]
Let's go through each rectangle step by step.
---
Rectangle 1:
- Length = 13 ft
- Width = 8 ft
\[
\text{Perimeter} = 2 \times (13 + 8) = 2 \times 21 = 42 \text{ ft}
\]
Answer: Perimeter = 42 ft
---
Rectangle 2:
- Length = 9 in
- Width = 6 in
\[
\text{Perimeter} = 2 \times (9 + 6) = 2 \times 15 = 30 \text{ in}
\]
Answer: Perimeter = 30 in
---
Rectangle 3:
- Length = 11 in
- Width = 4 in
\[
\text{Perimeter} = 2 \times (11 + 4) = 2 \times 15 = 30 \text{ in}
\]
Answer: Perimeter = 30 in
---
Rectangle 4:
- Length = 7 km
- Width = 3 km
\[
\text{Perimeter} = 2 \times (7 + 3) = 2 \times 10 = 20 \text{ km}
\]
Answer: Perimeter = 20 km
---
Rectangle 5:
- Length = 16 in
- Width = 21 in
\[
\text{Perimeter} = 2 \times (16 + 21) = 2 \times 37 = 74 \text{ in}
\]
Answer: Perimeter = 74 in
---
Rectangle 6:
- Length = 17 yd
- Width = 12 yd
\[
\text{Perimeter} = 2 \times (17 + 12) = 2 \times 29 = 58 \text{ yd}
\]
Answer: Perimeter = 58 yd
---
Rectangle 7:
- Length = 8 m
- Width = 5.5 m
\[
\text{Perimeter} = 2 \times (8 + 5.5) = 2 \times 13.5 = 27 \text{ m}
\]
Answer: Perimeter = 27 m
---
Rectangle 8:
- Length = 19 yd
- Width = 12 yd
\[
\text{Perimeter} = 2 \times (19 + 12) = 2 \times 31 = 62 \text{ yd}
\]
Answer: Perimeter = 62 yd
---
Rectangle 9:
- Length = 3 m
- Width = 1.8 m
\[
\text{Perimeter} = 2 \times (3 + 1.8) = 2 \times 4.8 = 9.6 \text{ m}
\]
Answer: Perimeter = 9.6 m
---
Final Answers:
1. Perimeter = 42 ft
2. Perimeter = 30 in
3. Perimeter = 30 in
4. Perimeter = 20 km
5. Perimeter = 74 in
6. Perimeter = 58 yd
7. Perimeter = 27 m
8. Perimeter = 62 yd
9. Perimeter = 9.6 m
\boxed{42 \text{ ft}, 30 \text{ in}, 30 \text{ in}, 20 \text{ km}, 74 \text{ in}, 58 \text{ yd}, 27 \text{ m}, 62 \text{ yd}, 9.6 \text{ m}}
Parent Tip: Review the logic above to help your child master the concept of perimeter of a rectangle worksheet.