To solve the problem of finding the perimeter of each rectangle, we use the formula for the perimeter of a rectangle:
\[
\text{Perimeter} = 2 \times (\text{Length} + \text{Width})
\]
Let's calculate the perimeter for each rectangle step by step.
---
Rectangle 1:
- Length = 13 cm
- Width = 5 cm
\[
\text{Perimeter} = 2 \times (13 + 5) = 2 \times 18 = 36 \, \text{cm}
\]
Answer: Perimeter = 36 cm
---
Rectangle 2:
- Length = 9.5 m
- Width = 3 m
\[
\text{Perimeter} = 2 \times (9.5 + 3) = 2 \times 12.5 = 25 \, \text{m}
\]
Answer: Perimeter = 25 m
---
Rectangle 3:
- Length = 22 ft
- Width = 7 ft
\[
\text{Perimeter} = 2 \times (22 + 7) = 2 \times 29 = 58 \, \text{ft}
\]
Answer: Perimeter = 58 ft
---
Rectangle 4:
- Length = 16 mm
- Width = 9.5 mm
\[
\text{Perimeter} = 2 \times (16 + 9.5) = 2 \times 25.5 = 51 \, \text{mm}
\]
Answer: Perimeter = 51 mm
---
Rectangle 5:
- Length = 11.5 yd
- Width = 6.2 yd
\[
\text{Perimeter} = 2 \times (11.5 + 6.2) = 2 \times 17.7 = 35.4 \, \text{yd}
\]
Answer: Perimeter = 35.4 yd
---
Rectangle 6:
- Length = 19.5 ft
- Width = 10 ft
\[
\text{Perimeter} = 2 \times (19.5 + 10) = 2 \times 29.5 = 59 \, \text{ft}
\]
Answer: Perimeter = 59 ft
---
Rectangle 7:
- Length = 6.5 m
- Width = 1.5 m
\[
\text{Perimeter} = 2 \times (6.5 + 1.5) = 2 \times 8 = 16 \, \text{m}
\]
Answer: Perimeter = 16 m
---
Rectangle 8:
- Length = 22.7 cm
- Width = 9.5 cm
\[
\text{Perimeter} = 2 \times (22.7 + 9.5) = 2 \times 32.2 = 64.4 \, \text{cm}
\]
Answer: Perimeter = 64.4 cm
---
Final Answers:
1. Perimeter = 36 cm
2. Perimeter = 25 m
3. Perimeter = 58 ft
4. Perimeter = 51 mm
5. Perimeter = 35.4 yd
6. Perimeter = 59 ft
7. Perimeter = 16 m
8. Perimeter = 64.4 cm
\boxed{36 \, \text{cm}, 25 \, \text{m}, 58 \, \text{ft}, 51 \, \text{mm}, 35.4 \, \text{yd}, 59 \, \text{ft}, 16 \, \text{m}, 64.4 \, \text{cm}}
Parent Tip: Review the logic above to help your child master the concept of perimeter of rectangle worksheet.
