To solve the problem of finding the perimeter of each triangle, we need to add up the lengths of all three sides of each triangle. The formula for the perimeter \( P \) of a triangle is:
\[
P = \text{side}_1 + \text{side}_2 + \text{side}_3
\]
Let's go through each triangle step by step.
---
Triangle 1:
- Sides: \( 9 \, \text{yd} \), \( 4 \, \text{yd} \), \( 4 \, \text{yd} \)
- Perimeter:
\[
P = 9 + 4 + 4 = 17 \, \text{yd}
\]
---
Triangle 2:
- Sides: \( 9 \, \text{in} \), \( 6 \, \text{in} \), \( 6 \, \text{in} \)
- Perimeter:
\[
P = 9 + 6 + 6 = 21 \, \text{in}
\]
---
Triangle 3:
- Sides: \( 15.6 \, \text{ft} \), \( 9 \, \text{ft} \), \( 12 \, \text{ft} \)
- Perimeter:
\[
P = 15.6 + 9 + 12 = 36.6 \, \text{ft}
\]
---
Triangle 4:
- Sides: \( 6 \, \text{ft} \), \( 8 \, \text{ft} \), \( 4 \, \text{ft} \)
- Perimeter:
\[
P = 6 + 8 + 4 = 18 \, \text{ft}
\]
---
Triangle 5:
- Sides: \( 10 \, \text{yd} \), \( 6 \, \text{yd} \), \( 7 \, \text{yd} \)
- Perimeter:
\[
P = 10 + 6 + 7 = 23 \, \text{yd}
\]
---
Triangle 6:
- Sides: \( 12 \, \text{in} \), \( 12 \, \text{in} \), \( 12 \, \text{in} \) (Equilateral triangle)
- Perimeter:
\[
P = 12 + 12 + 12 = 36 \, \text{in}
\]
---
Triangle 7:
- Sides: \( 5 \, \text{in} \), \( 7 \, \text{in} \), \( 8 \, \text{in} \)
- Perimeter:
\[
P = 5 + 7 + 8 = 20 \, \text{in}
\]
---
Triangle 8:
- Sides: \( 16 \, \text{ft} \), \( 16 \, \text{ft} \), \( 16 \, \text{ft} \) (Equilateral triangle)
- Perimeter:
\[
P = 16 + 16 + 16 = 48 \, \text{ft}
\]
---
Triangle 9:
- Sides: \( 70 \, \text{yd} \), \( 20 \, \text{yd} \), \( 14 \, \text{yd} \)
- Perimeter:
\[
P = 70 + 20 + 14 = 104 \, \text{yd}
\]
---
Final Answers:
1. \( 17 \, \text{yd} \)
2. \( 21 \, \text{in} \)
3. \( 36.6 \, \text{ft} \)
4. \( 18 \, \text{ft} \)
5. \( 23 \, \text{yd} \)
6. \( 36 \, \text{in} \)
7. \( 20 \, \text{in} \)
8. \( 48 \, \text{ft} \)
9. \( 104 \, \text{yd} \)
\boxed{17, 21, 36.6, 18, 23, 36, 20, 48, 104}
Parent Tip: Review the logic above to help your child master the concept of perimeter of triangle worksheet.
