To solve the problems on the "Perimeter Sheet 4," we need to calculate the perimeter of each given shape. The
perimeter is the total length of the boundary of a shape, which is found by adding up the lengths of all its sides.
Let's solve each problem step by step:
---
Problem 1: Rectangle
-
Dimensions: Length = 7 cm, Width = 2 cm
-
Formula for Perimeter of a Rectangle: \( P = 2 \times (\text{Length} + \text{Width}) \)
-
Calculation:
\[
P = 2 \times (7 + 2) = 2 \times 9 = 18 \, \text{cm}
\]
-
Answer: Perimeter = \( \boxed{18} \) cm
---
Problem 2: Triangle
-
Sides: 4 in, 6 in, 3 in
-
Formula for Perimeter of a Triangle: Add all three sides.
-
Calculation:
\[
P = 4 + 6 + 3 = 13 \, \text{in}
\]
-
Answer: Perimeter = \( \boxed{13} \) in
---
Problem 3: Irregular Quadrilateral
-
Sides: 7 cm, 5 cm, 6 cm, 2 cm
-
Formula for Perimeter: Add all four sides.
-
Calculation:
\[
P = 7 + 5 + 6 + 2 = 20 \, \text{cm}
\]
-
Answer: Perimeter = \( \boxed{20} \) cm
---
Problem 4: Triangle
-
Sides: 7 m, 10 m, 11 m
-
Formula for Perimeter of a Triangle: Add all three sides.
-
Calculation:
\[
P = 7 + 10 + 11 = 28 \, \text{m}
\]
-
Answer: Perimeter = \( \boxed{28} \) m
---
Problem 5: Pentagon
-
Sides: 6 ft, 6 ft, 4 ft, 4 ft, 7 ft
-
Formula for Perimeter: Add all five sides.
-
Calculation:
\[
P = 6 + 6 + 4 + 4 + 7 = 27 \, \text{ft}
\]
-
Answer: Perimeter = \( \boxed{27} \) ft
---
Problem 6: Irregular Hexagon
-
Sides: 6½ cm, 2½ cm, 4 cm, 6½ cm, 2½ cm, 4 cm
-
Formula for Perimeter: Add all six sides.
-
Calculation:
\[
P = 6.5 + 2.5 + 4 + 6.5 + 2.5 + 4 = 26 \, \text{cm}
\]
-
Answer: Perimeter = \( \boxed{26} \) cm
---
Final Answers
1. Perimeter = \( \boxed{18} \) cm
2. Perimeter = \( \boxed{13} \) in
3. Perimeter = \( \boxed{20} \) cm
4. Perimeter = \( \boxed{28} \) m
5. Perimeter = \( \boxed{27} \) ft
6. Perimeter = \( \boxed{26} \) cm
---
Boxed Final Answer:
\[
\boxed{18, 13, 20, 28, 27, 26}
\]
Parent Tip: Review the logic above to help your child master the concept of perimeter worksheets.
