Problem Overview:
The task involves calculating the
perimeter of various geometric shapes. The perimeter is defined as the total distance around the outside of a figure, which is found by adding up the lengths of all its sides.
Solution Approach:
For each shape, we will:
1. Identify the lengths of all sides.
2. Add up these side lengths to find the perimeter.
Let's solve each problem step by step.
---
Problem 1:
Shape: Equilateral Triangle
Side lengths: 5 in, 5 in, 5 in
Perimeter = \( 5 + 5 + 5 = 15 \) in
Answer: \( \boxed{15} \)
---
Problem 2:
Shape: Square
Side lengths: 4 in, 4 in, 4 in, 4 in
Perimeter = \( 4 + 4 + 4 + 4 = 16 \) in
Answer: \( \boxed{16} \)
---
Problem 3:
Shape: Rectangle
Side lengths: 7 in, 9 in, 7 in, 9 in
Perimeter = \( 7 + 9 + 7 + 9 = 32 \) in
Answer: \( \boxed{32} \)
---
Problem 4:
Shape: Rhombus
Side lengths: 4 in, 4 in, 4 in, 4 in
Perimeter = \( 4 + 4 + 4 + 4 = 16 \) in
Answer: \( \boxed{16} \)
---
Problem 5:
Shape: Regular Hexagon
Side lengths: 3 in, 3 in, 3 in, 3 in, 3 in, 3 in
Perimeter = \( 3 + 3 + 3 + 3 + 3 + 3 = 18 \) in
Answer: \( \boxed{18} \)
---
Problem 6:
Shape: Irregular Pentagon
Side lengths: 4 in, 3 in, 2 in, 4 in, 3 in
Perimeter = \( 4 + 3 + 2 + 4 + 3 = 16 \) in
Answer: \( \boxed{16} \)
---
Problem 7:
Shape: Right Triangle
Side lengths: 3 in, 3 in, 8 in
Perimeter = \( 3 + 3 + 8 = 14 \) in
Answer: \( \boxed{14} \)
---
Problem 8:
Shape: Isosceles Trapezoid
Side lengths: 5 in, 5 in, 3 in, 7 in
Perimeter = \( 5 + 5 + 3 + 7 = 20 \) in
Answer: \( \boxed{20} \)
---
Problem 9:
Shape: Rectangle
Side lengths: 9 in, 3 in, 9 in, 3 in
Perimeter = \( 9 + 3 + 9 + 3 = 24 \) in
Answer: \( \boxed{24} \)
---
Problem 10:
Shape: Irregular Pentagon
Side lengths: 2 in, 2 in, 2 in, 2 in, 2 in
Perimeter = \( 2 + 2 + 2 + 2 + 2 = 10 \) in
Answer: \( \boxed{10} \)
---
Problem 11:
Shape: Irregular Shape (Combination of Rectangles)
Side lengths: 3 in, 8 in, 3 in, 6 in, 4 in, 2 in
Perimeter = \( 3 + 8 + 3 + 6 + 4 + 2 = 26 \) in
Answer: \( \boxed{26} \)
---
Problem 12:
Shape: Irregular Shape (Combination of Triangles and Rectangles)
Side lengths: 3 in, 3 in, 3 in, 4 in, 6 in
Perimeter = \( 3 + 3 + 3 + 4 + 6 = 19 \) in
Answer: \( \boxed{19} \)
---
Final Answers:
1. \( \boxed{15} \)
2. \( \boxed{16} \)
3. \( \boxed{32} \)
4. \( \boxed{16} \)
5. \( \boxed{18} \)
6. \( \boxed{16} \)
7. \( \boxed{14} \)
8. \( \boxed{20} \)
9. \( \boxed{24} \)
10. \( \boxed{10} \)
11. \( \boxed{26} \)
12. \( \boxed{19} \)
Final Answer Boxed Set:
\[
\boxed{15, 16, 32, 16, 18, 16, 14, 20, 24, 10, 26, 19}
\]
Parent Tip: Review the logic above to help your child master the concept of perimeter worksheets.
