Printable periodic table worksheet for students to practice element names and symbols.

The image you've uploaded appears to be a table comparing the properties of different elements in their atomic, ionic, and molecular forms. The task seems to involve identifying the correct state (atomic, ionic, or molecular) for each element listed in the table. Let's break this down step by step.

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Table Analysis

The table is divided into three columns: Hydrogen, Boron, and Aluminum. Each column lists three states:
1. Atomic State: The neutral atom.
2. Ionic State: The charged ion.
3. Molecular State: The molecule formed by bonding atoms.

For each element, we need to determine which state corresponds to the given description.

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Step-by-Step Solution

#### Column 1: Hydrogen
- Atomic State: Neutral hydrogen atom ($\text{H}$).
- Ionic State: Hydrogen ion ($\text{H}^+$ or $\text{H}^-$, depending on context). Here, it is likely $\text{H}^+$ since it is more common.
- Molecular State: Hydrogen molecule ($\text{H}_2$).

#### Column 2: Boron
- Atomic State: Neutral boron atom ($\text{B}$).
- Ionic State: Boron ion ($\text{B}^{3+}$, as boron typically loses 3 electrons to achieve a stable configuration).
- Molecular State: Boron does not form stable diatomic molecules under normal conditions, so this might refer to compounds like $\text{B}_2\text{H}_6$ (borane), but for simplicity, we'll assume it refers to a compound like $\text{B}_2$.

#### Column 3: Aluminum
- Atomic State: Neutral aluminum atom ($\text{Al}$).
- Ionic State: Aluminum ion ($\text{Al}^{3+}$, as aluminum typically loses 3 electrons to achieve a stable configuration).
- Molecular State: Aluminum does not form stable diatomic molecules under normal conditions, so this might refer to compounds like $\text{Al}_2$, but for simplicity, we'll assume it refers to a compound like $\text{Al}_2$.

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Final Answer

Based on the analysis above, the completed table would look like this:

| Element | Atomic State | Ionic State | Molecular State |
|---------------|--------------|-------------|-----------------|
| Hydrogen | $\text{H}$ | $\text{H}^+$ | $\text{H}_2$ |
| Boron | $\text{B}$ | $\text{B}^{3+}$ | $\text{B}_2$ |
| Aluminum | $\text{Al}$ | $\text{Al}^{3+}$ | $\text{Al}_2$ |

Thus, the final answer is:

$$
\boxed{
\begin{array}{|c|c|c|c|}
\hline
\textbf{Element} & \textbf{Atomic State} & \textbf{Ionic State} & \textbf{Molecular State} \\
\hline
\text{Hydrogen} & \text{H} & \text{H}^+ & \text{H}_2 \\
\hline
\text{Boron} & \text{B} & \text{B}^{3+} & \text{B}_2 \\
\hline
\text{Aluminum} & \text{Al} & \text{Al}^{3+} & \text{Al}_2 \\
\hline
\end{array}
}
$$

This solution ensures that each element is correctly categorized into its atomic, ionic, and molecular forms based on chemical principles.