Problem Explanation:
The task involves breaking down each given number into its
tens and
ones place values. This is a fundamental concept in understanding place value in mathematics. For any two-digit number:
- The
tens place represents how many groups of 10 are in the number.
- The
ones place represents the remaining units.
For example, in the number
53:
- There are
5 tens (which is \(5 \times 10 = 50\)).
- There are
3 ones (which is \(3 \times 1 = 3\)).
Thus, \(53 = 5\) tens + \(3\) ones.
Solution:
We will break down each number step by step:
1.
21:
- Tens: \(2\) (because \(2 \times 10 = 20\))
- Ones: \(1\) (because \(1 \times 1 = 1\))
- So, \(21 = 2\) tens + \(1\) ones.
2.
49:
- Tens: \(4\) (because \(4 \times 10 = 40\))
- Ones: \(9\) (because \(9 \times 1 = 9\))
- So, \(49 = 4\) tens + \(9\) ones.
3.
72:
- Tens: \(7\) (because \(7 \times 10 = 70\))
- Ones: \(2\) (because \(2 \times 1 = 2\))
- So, \(72 = 7\) tens + \(2\) ones.
4.
86:
- Tens: \(8\) (because \(8 \times 10 = 80\))
- Ones: \(6\) (because \(6 \times 1 = 6\))
- So, \(86 = 8\) tens + \(6\) ones.
5.
50:
- Tens: \(5\) (because \(5 \times 10 = 50\))
- Ones: \(0\) (because \(0 \times 1 = 0\))
- So, \(50 = 5\) tens + \(0\) ones.
6.
18:
- Tens: \(1\) (because \(1 \times 10 = 10\))
- Ones: \(8\) (because \(8 \times 1 = 8\))
- So, \(18 = 1\) tens + \(8\) ones.
Final Answer:
\[
\begin{aligned}
21 &= 2 \text{ tens} + 1 \text{ ones} \\
49 &= 4 \text{ tens} + 9 \text{ ones} \\
72 &= 7 \text{ tens} + 2 \text{ ones} \\
86 &= 8 \text{ tens} + 6 \text{ ones} \\
50 &= 5 \text{ tens} + 0 \text{ ones} \\
18 &= 1 \text{ tens} + 8 \text{ ones}
\end{aligned}
\]
\[
\boxed{
\begin{array}{r|c|c}
21 & 2 \text{ tens} & 1 \text{ ones} \\
49 & 4 \text{ tens} & 9 \text{ ones} \\
72 & 7 \text{ tens} & 2 \text{ ones} \\
86 & 8 \text{ tens} & 6 \text{ ones} \\
50 & 5 \text{ tens} & 0 \text{ ones} \\
18 & 1 \text{ tens} & 8 \text{ ones} \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of place value worksheet 2nd grade tens ones.
