Colorful worksheet titled "Place Value Word Problems" with two math exercises: one about finding a three-digit locker code based on place value clues, and another about calculating money spent on hot chocolate of different sizes.

Let's solve each problem step by step.

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Problem 1: Kiko’s Locker Code

Clues:
- It's a three-digit number.
- Has 2 in the hundreds place → So, the number starts with 2.
- Has 8 in the ones place → So, the number ends with 8.
- All digits are even.
- No digits are repeated.

#### Step-by-step:
We know:
- Hundreds digit = 2
- Ones digit = 8
- So the number is in the form: 2 _ 8

Now, we need to find the tens digit, which must be:
- Even
- Not equal to 2 or 8 (no repeats)
- Digits that are even: 0, 2, 4, 6, 8

But since 2 and 8 are already used, possible tens digits: 0, 4, 6

So possible numbers:
- 208
- 248
- 268

✔ These are all valid because:
- All digits are even
- No repeated digits
- Hundreds = 2, ones = 8

Answer: Possible codes for Kiko: 208, 248, 268

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Next part of Problem 1: Amy and Joe’s Codes

> Amy’s code is 10 more than Joe’s code.
> The hundreds digit is the same for both.
> The ones digit is also the same for both.
> Choose from: 412, 512, 422, 423, 523

Let’s analyze:

Since Amy’s code is 10 more than Joe’s, the tens digit increases by 1, and the ones digit stays the same.

Also, hundreds digit is same, and ones digit is same.

So we’re looking for two numbers where:
- Hundreds digit = same
- Ones digit = same
- One is 10 more than the other

Let’s check pairs:

1. 412 and 422: differ by 10? 422 - 412 = 10 ✔
- Hundreds: 4 = 4 ✔
- Ones: 2 = 2 ✔
→ This pair works!
So Joe could have 412, Amy 422 (or vice versa)

2. 512 and 523: difference = 11 ✘
3. 422 and 423: difference = 1 ✘
4. 512 and 523: difference = 11 ✘
5. 412 and 512: difference = 100 ✘

Only 412 and 422 satisfy:
- Same hundreds digit (4)
- Same ones digit (2)
- Difference of 10

✔ So Joe and Amy’s codes are 412 and 422

Answer: Circle 412 and 422

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Problem 2: Hot Chocolate Prices

Prices:
- 100p
- 125p
- 152p
- 215p

#### Lou has 20p. Uncle gives her 100p. Gran gives her 5p.

Total money Lou has:
20 + 100 + 5 = 125p

She can buy the one that costs exactly 125p.

✔ So she can buy the 125p hot chocolate.

Answer: Circle the 125p cup.

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#### Laura has 315p. She buys the biggest hot chocolate. How much does she have left?

Biggest hot chocolate = 215p

Money left = 315 - 215 = 100p

✔ Answer: 100p

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#### Yusuf has 4 ten pence coins. Mum gives him 7 more ten pence coins. Does he have enough to buy a hot chocolate? Explain.

First, calculate total money:

- 4 × 10p = 40p
- 7 × 10p = 70p
- Total = 40 + 70 = 110p

Now, check if he can buy any hot chocolate:
- 100p → yes (he has 110p)
- 125p → no (110 < 125)
- 152p → no
- 215p → no

He can only afford the 100p hot chocolate.

✔ So, yes, Yusuf has enough money to buy a hot chocolate — specifically, the 100p one.

Answer: Yes, Yusuf has 110p, which is enough to buy the 100p hot chocolate.

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✔ Final Answers Summary:

#### Problem 1:
- Kiko’s possible codes: 208, 248, 268
- Joe and Amy’s codes: 412 and 422

#### Problem 2:
- Lou can buy: 125p hot chocolate
- Laura has 100p left
- Yusuf: Yes, he has 110p, which is enough for the 100p hot chocolate.

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