To solve the problem of finding the area of each parallelogram, we will use the formula for the area of a parallelogram:
\[
\text{Area} = \text{base} \times \text{height}
\]
We will apply this formula to each given parallelogram and provide the solution step by step.
---
1. Parallelogram 1
-
Base: 5 cm
-
Height: 11 cm
#### Formula:
\[
\text{Area} = \text{base} \times \text{height}
\]
#### Equation:
\[
\text{Area} = 5 \, \text{cm} \times 11 \, \text{cm}
\]
#### Solution:
\[
\text{Area} = 55 \, \text{cm}^2
\]
---
2. Parallelogram 2
-
Base: 3 m
-
Height: 7 m
#### Formula:
\[
\text{Area} = \text{base} \times \text{height}
\]
#### Equation:
\[
\text{Area} = 3 \, \text{m} \times 7 \, \text{m}
\]
#### Solution:
\[
\text{Area} = 21 \, \text{m}^2
\]
---
3. Parallelogram 3
-
Base: 8.5 cm
-
Height: 9 cm
#### Formula:
\[
\text{Area} = \text{base} \times \text{height}
\]
#### Equation:
\[
\text{Area} = 8.5 \, \text{cm} \times 9 \, \text{cm}
\]
#### Solution:
\[
\text{Area} = 76.5 \, \text{cm}^2
\]
---
4. Parallelogram 4
-
Base: 13 ft
-
Height: 4 ft
#### Formula:
\[
\text{Area} = \text{base} \times \text{height}
\]
#### Equation:
\[
\text{Area} = 13 \, \text{ft} \times 4 \, \text{ft}
\]
#### Solution:
\[
\text{Area} = 52 \, \text{ft}^2
\]
---
5. Parallelogram 5
-
Base: 7 mm
-
Height: 3 mm
#### Formula:
\[
\text{Area} = \text{base} \times \text{height}
\]
#### Equation:
\[
\text{Area} = 7 \, \text{mm} \times 3 \, \text{mm}
\]
#### Solution:
\[
\text{Area} = 21 \, \text{mm}^2
\]
---
6. Parallelogram 6
-
Base: 15 in
-
Height: 5 in
#### Formula:
\[
\text{Area} = \text{base} \times \text{height}
\]
#### Equation:
\[
\text{Area} = 15 \, \text{in} \times 5 \, \text{in}
\]
#### Solution:
\[
\text{Area} = 75 \, \text{in}^2
\]
---
Final Answers
\[
\boxed{
\begin{array}{ll}
1. & 55 \, \text{cm}^2 \\
2. & 21 \, \text{m}^2 \\
3. & 76.5 \, \text{cm}^2 \\
4. & 52 \, \text{ft}^2 \\
5. & 21 \, \text{mm}^2 \\
6. & 75 \, \text{in}^2 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of plane figure worksheet.