Probability worksheet with a candy jar illustration and questions about picking different colored candies.

To solve these probability questions, we first need to count the total number of candies and the number of each specific color in the jar.

Step 1: Count the candies by color
Let's look at the jar and count each color carefully:
* Orange candies: There are 5 orange candies.
* Yellow candies: There are 4 yellow candies.
* Blue candies: There are 6 blue candies.
* Green candies: There are 5 green candies.

Step 2: Calculate the total number of candies
Add all the counts together to find the total:
$$5 \text{ (orange)} + 4 \text{ (yellow)} + 6 \text{ (blue)} + 5 \text{ (green)} = 20 \text{ total candies}$$

Now we can answer each question using the formula:
$$\text{Probability} = \frac{\text{Number of specific items}}{\text{Total number of items}}$$

1. What is the probability of picking an orange candy?
* Number of orange candies: 5
* Total candies: 20
* Probability: $\frac{5}{20}$
* Simplified: $\frac{1}{4}$

2. What is the probability of picking a yellow candy?
* Number of yellow candies: 4
* Total candies: 20
* Probability: $\frac{4}{20}$
* Simplified: $\frac{1}{5}$

3. What is the probability of picking a blue candy?
* Number of blue candies: 6
* Total candies: 20
* Probability: $\frac{6}{20}$
* Simplified: $\frac{3}{10}$

4. What is the probability of picking a green candy?
* Number of green candies: 5
* Total candies: 20
* Probability: $\frac{5}{20}$
* Simplified: $\frac{1}{4}$

5. Which candy is least likely to be picked at random?
* We compare the counts: Orange (5), Yellow (4), Blue (6), Green (5).
* The smallest number is 4 (Yellow).
* Therefore, Yellow is the least likely.

6. What is the probability of picking either a yellow candy or a green candy?
* "Either... or" means we add the numbers together.
* Yellow (4) + Green (5) = 9 favorable outcomes.
* Total candies: 20
* Probability: $\frac{9}{20}$

7. What is the probability of picking either an orange candy or a blue candy?
* Orange (5) + Blue (6) = 11 favorable outcomes.
* Total candies: 20
* Probability: $\frac{11}{20}$

8. Would it be more likely to pick an orange candy or yellow candy?
* Compare the counts: Orange has 5 candies, Yellow has 4 candies.
* Since 5 is greater than 4, it is more likely to pick Orange.

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Final Answer:
1. 1/4 (or 5/20)
2. 1/5 (or 4/20)
3. 3/10 (or 6/20)
4. 1/4 (or 5/20)
5. Yellow
6. 9/20
7. 11/20
8. Orange