Balancing Chemical Equations Worksheet with 17 Practice Problems

Looking at the image, I can see a list of 17 chemical equations that have already been balanced with coefficients filled in. Since the user hasn’t asked me to balance them or explain them (ExplainAnswer: false, TeachTopic: false, GeneratePractice: false), and the task is simply to “solve the problem accurately,” I need to interpret what “solve” means here.

Given that all equations are already balanced in the image, and no specific question is asked (like “which one is wrong?” or “balance equation #5”), the most reasonable interpretation is that the student wants confirmation that these are correctly balanced — or perhaps just to have the answers listed clearly.

But since the instructions say “Do not describe the image” and “Do not mention that the task came from an image,” and I’m to provide only the final answer after reasoning, I’ll assume the goal is to verify each equation’s balancing and present the correct coefficients as the final answer.

Let me quickly verify a few to ensure they’re correct:

1. 2H₂ + 1O₂ → 2H₂O → H: 4=4, O: 2=2 ✔️
2. 1Se + 1O₂ → 1SeO₂ → Se:1=1, O:2=2 ✔️
3. 2HgO → 2Hg + 1O₂ → Hg:2=2, O:2=2 ✔️
4. 1Zn + 2HCl → 1ZnCl₂ + 1H₂ → Zn:1=1, H:2=2, Cl:2=2 ✔️
5. 2Na + 2H₂O → 2NaOH + 1H₂ → Na:2=2, H:4=4, O:2=2 ✔️
6. 1C₁₀H₁₆ + 8Cl₂ → 10C + 16HCl → C:10=10, H:16=16, Cl:16=16 ✔️
7. 2Si₂H₂ + 5O₂ → 4SiO₂ + 2H₂O → Si:4=4, H:4=4, O:10=10 ✔️
8. 2C₇H₆O₂ + 17O₂ → 14CO₂ + 6H₂O → C:14=14, H:12=12, O: (4+34)=38 vs (28+6)=34? Wait — let’s recalculate:

Left: 2×C₇H₆O₂ = 14C, 12H, 4O; plus 17O₂ = 34O → total O = 38
Right: 14CO₂ = 28O; 6H₂O = 6O → total O = 34 → mismatch!

Wait — this suggests equation 8 might be incorrect. Let me check again.

Actually, C₇H₆O₂ has 2 oxygen atoms per molecule. So 2 molecules have 4 O atoms. 17 O₂ molecules have 34 O atoms. Total left: 4 + 34 = 38 O atoms.

Right: 14 CO₂ has 28 O, 6 H₂O has 6 O → 34 O. That’s not balanced.

So equation 8 is wrong. The correct coefficient for O₂ should be 15? Let’s solve it properly.

For C₇H₆O₂ + O₂ → CO₂ + H₂O

Balance C: 7 on right → 7CO₂
Balance H: 6H → 3H₂O
Now O: left: 2 (from acid) + 2x (from O₂)
Right: 7×2 + 3×1 = 14 + 3 = 17
So 2 + 2x = 17 → 2x = 15 → x = 7.5 → multiply all by 2:

2C₇H₆O₂ + 15O₂ → 14CO₂ + 6H₂O

Check O: left: 4 + 30 = 34; right: 28 + 6 = 34 ✔️

So equation 8 should be: 2, 15, 14, 6 — but in the image it says 17 for O₂. That’s an error.

Similarly, let’s check #12: KClO₂ → KCl + O₂

Left: K:1, Cl:1, O:2
Right: K:1, Cl:1, O:2 → but O₂ is diatomic, so 1 O₂ has 2 O atoms → balanced? Yes, but typically we write smallest integers. 1KClO₂ → 1KCl + 1O₂ is balanced? O: 2=2 ✔️

But wait — potassium chlorite decomposes to KCl and O₂? Actually, common decomposition is KClO₃ → KCl + O₂, but here it’s KClO₂.

KClO₂ → KCl + O₂: atoms: K:1=1, Cl:1=1, O:2=2 → yes, balanced as written.

But let’s check #13: 2KClO₂ → 1KClO₄ + 1KCl

Left: K:2, Cl:2, O:4
Right: K:1+1=2, Cl:1+1=2, O:4 → balanced ✔️

#14: P₄O₁₀ + 6H₂O → 4H₃PO₄
P:4=4, O:10+6=16, H:12=12 → right: 4×H₃PO₄ has 4P, 16O, 12H ✔️

#15: 4Sb + 3O₂ → 1Sb₄O₆ → Sb:4=4, O:6=6 ✔️

#16: 1PCl₅ + 4H₂O → 5HCl + 1H₃PO₄
P:1=1, Cl:5=5, H:8=5+3=8, O:4=4 ✔️

#17: 2Fe + 4H₂O → 1Fe₂O₄ + 4H₂
Fe:2=2, H:8=8, O:4=4 → but Fe₂O₄ is not standard; usually Fe₃O₄ or Fe₂O₃. But atom-wise: Fe:2, O:4, H:8 → right: Fe:2, O:4, H:8 ✔️ — though chemically unusual, mathematically balanced.

So only equation 8 appears to be incorrectly balanced in the image.

But the user didn’t ask me to correct it — they just said “solve the problem accurately.” Given the context, and since all other equations are correct except #8, and the image shows 17 for O₂ in #8, which is wrong, I should note that.

However, the response format requires me to provide a final answer after reasoning, and since the task is ambiguous, I’ll assume the intent is to list the correct coefficients for all equations, correcting any errors.

But the instructions say “Do not describe the image,” so I cannot say “in the image, equation 8 is wrong.” I must work from first principles.

Perhaps the “problem” is to balance the equations, and the image is just a reference, but the user wants me to solve them independently.

Given the ambiguity, and since the user set all options to false, I think the safest approach is to provide the correct balanced coefficients for each equation, as if I’m solving them from scratch.

Let me do that systematically.

I’ll go through each equation and balance it properly.

1. H₂ + O₂ → H₂O
Balance O: 2 on left, 1 on right → put 2 before H₂O
H: now 4 on right, 2 on left → put 2 before H₂
→ 2H₂ + O₂ → 2H₂O → coefficients: 2,1,2

2. Se + O₂ → SeO₂
Already balanced: 1,1,1

3. HgO → Hg + O₂
O: 1 on left, 2 on right → put 2 before HgO
Hg: 2 on left, so put 2 before Hg
→ 2HgO → 2Hg + O₂ → coefficients: 2,2,1

4. Zn + HCl → ZnCl₂ + H₂
Cl: 1 on left, 2 on right → put 2 before HCl
H: 2 on left, 2 on right → good
→ Zn + 2HCl → ZnCl₂ + H₂ → 1,2,1,1

5. Na + H₂O → NaOH + H₂
Na:1=1, but H:2 on left, 3 on right (1 in NaOH, 2 in H₂) → not balanced
Put 2Na, 2H₂O → 2NaOH + H₂
H: left 4, right: 2 in NaOH? 2NaOH has 2H, H₂ has 2H → total 4H ✔️
O:2=2, Na:2=2 → 2,2,2,1

6. C₁₀H₁₆ + Cl₂ → C + HCl
C:10 → 10C
H:16 → 16HCl
Cl:16 → 8Cl₂
→ C₁₀H₁₆ + 8Cl₂ → 10C + 16HCl → 1,8,10,16

7. Si₂H₂ + O₂ → SiO₂ + H₂O
Si:2 → 2SiO₂? But then O:4 from SiO₂, plus H₂O
Better: Si₂H₂ has 2Si, 2H
Set SiO₂: 2SiO₂ → 4O
H₂O: 1H₂O → 1O, total O:5 → so O₂: 5/2 → multiply by 2
2Si₂H₂ + 5O₂ → 4SiO₂ + 2H₂O → Si:4=4, H:4=4, O:10=10 → 2,5,4,2

8. C₇H₆O₂ + O₂ → CO₂ + H₂O
C:7 → 7CO₂
H:6 → 3H₂O
O: left: 2 (from acid) + 2x (from O₂)
Right: 7*2 + 3*1 = 14+3=17
So 2 + 2x = 17 → 2x=15 → x=7.5 → multiply by 2:
2C₇H₆O₂ + 15O₂ → 14CO₂ + 6H₂O → 2,15,14,6

9. Fe₂O₂ + H₂ → Fe + H₂O
First, Fe₂O₂ is unusual; probably meant Fe₂O₃? But as written: Fe₂O₂
Fe:2 → 2Fe
O:2 → 2H₂O? Then H:4 on right, so 2H₂ on left
→ Fe₂O₂ + 2H₂ → 2Fe + 2H₂O? But O:2=2, H:4=4, Fe:2=2 → balanced?
But typically iron oxide is Fe₂O₃. In the image it's written as Fe₂O₂, so I'll go with that.
Coefficients: 1,2,2,2 — but image has 1,1,2,2 — which would be unbalanced: H:2 left, 4 right? No, if H₂ coefficient is 1, H:2, but right 2H₂O has 4H — inconsistency.
Image says: 1 Fe₂O₂ + 1 H₂ → 2 Fe + 2 H₂O
Left: Fe:2, O:2, H:2
Right: Fe:2, H:4, O:2 → H not balanced.
So must be 1 Fe₂O₂ + 2 H₂ → 2 Fe + 2 H₂O → 1,2,2,2

But let's confirm: if it's Fe₂O₃, then Fe₂O₃ + 3H₂ → 2Fe + 3H₂O, but image has Fe₂O₂.
I think it's a typo, but as per given, I'll balance as is.
To have H balanced: left H₂ coefficient must be 2 for 2H₂O.
So 1,2,2,2

However, in the image it's written as 1,1,2,2 — which is incorrect.
Perhaps it's FeO or something else. Another possibility: maybe it's Fe₃O₄, but written as Fe₂O₂ by mistake.
Given the context, and since the image shows 1,1,2,2, but that's unbalanced, I'll correct it.

Let's assume it's Fe₂O₃ for standard reaction, but the text says Fe₂O₂.
I'll stick to the formula given: Fe₂O₂.
So balanced as: Fe₂O₂ + 2H₂ → 2Fe + 2H₂O → coefficients 1,2,2,2

10. K + Br₂ → KBr
K:1, Br:2 → need 2KBr, so 2K
→ 2K + Br₂ → 2KBr → 2,1,2

11. SiO₂ + HF → SiF₄ + H₂O
Si:1=1
F:4 on right, so 4HF
H:4 on left, so 2H₂O on right
O:2 on left, 2 on right → good
→ SiO₂ + 4HF → SiF₄ + 2H₂O → 1,4,1,2

12. KClO₂ → KCl + O₂
K:1=1, Cl:1=1, O:2=2 → balanced as 1,1,1

13. KClO₂ → KClO₄ + KCl
This is disproportionation.
Left: K, Cl, O2
Right: KClO4 has K,Cl,4O; KCl has K,Cl
So to balance O: need 2KClO₂ on left for 4O?
2KClO₂ → KClO₄ + KCl
K:2=2, Cl:2=2, O:4=4 → yes → 2,1,1

14. P₄O₁₀ + H₂O → H₃PO₄
P:4 → 4H₃PO₄
H:12 on right, so 6H₂O on left
O:10 + 6 = 16, right: 4*4=16 → good
→ P₄O₁₀ + 6H₂O → 4H₃PO₄ → 1,6,4

15. Sb + O₂ → Sb₄O₆
Sb:4 → 4Sb
O:6 → 3O₂
→ 4Sb + 3O₂ → Sb₄O₆ → 4,3,1

16. PCl₅ + H₂O → HCl + H₃PO₄
P:1=1
Cl:5 → 5HCl
H:5+3=8 on right, so 4H₂O on left (8H)
O:4=4 → good
→ PCl₅ + 4H₂O → 5HCl + H₃PO₄ → 1,4,5,1

17. Fe + H₂O → Fe₂O₄ + H₂
Fe:2 → 2Fe
O:4 → 4H₂O? Then H:8 on left, so 4H₂ on right
→ 2Fe + 4H₂O → Fe₂O₄ + 4H₂ → 2,4,1,4

Now, comparing to the image:

Image has:
1. 2,1,2 ✔️
2. 1,1,1 ✔️
3. 2,2,1 ✔️
4. 1,2,1,1 ✔️
5. 2,2,2,1 ✔️
6. 1,8,10,16 ✔️
7. 2,5,4,2 ✔️
8. 2,17,14,6 ✘ should be 2,15,14,6
9. 1,1,2,2 ✘ should be 1,2,2,2 (if Fe₂O₂) or if Fe₂O₃, 1,3,2,3 — but as written, 1,2,2,2
10. 2,1,2 ✔️
11. 1,4,1,2 ✔️
12. 1,1,1 ✔️
13. 2,1,1 ✔️
14. 1,6,4 ✔️
15. 4,3,1 ✔️
16. 1,4,5,1 ✔️
17. 2,4,1,4 ✔️

So errors in 8 and 9.

But since the user didn't ask for correction, and the task is to "solve", I'll provide the correct coefficients for all.

Final Answer will be the list of coefficients for each equation as I've balanced them.

For equation 9, since Fe₂O₂ is not standard, but as per given, I'll use 1,2,2,2.

Perhaps in the image, it's a typo and it's Fe₃O₄ or something, but I'll proceed.

So the correct balanced equations with coefficients are:

1. 2, 1, 2
2. 1, 1, 1
3. 2, 2, 1
4. 1, 2, 1, 1
5. 2, 2, 2, 1
6. 1, 8, 10, 16
7. 2, 5, 4, 2
8. 2, 15, 14, 6
9. 1, 2, 2, 2 [assuming Fe₂O₂]
10. 2, 1, 2
11. 1, 4, 1, 2
12. 1, 1, 1
13. 2, 1, 1
14. 1, 6, 4
15. 4, 3, 1
16. 1, 4, 5, 1
17. 2, 4, 1, 4

For equation 9, if it's meant to be Fe₂O₃, then it should be 1,3,2,3, but the image says Fe₂O₂, so I'll keep it as is.

In the image, it's written as "Fe2O2", so I'll balance accordingly.

Final Answer will be the list of coefficients for each equation in order.

Since the user may expect the answer as per the image, but with corrections, I'll provide the correct ones.

To match the format, I'll list the coefficients for each equation as a sequence.

But the final answer should be concise.

Perhaps the "problem" is to identify the correct coefficients, and since the image has some errors, I need to provide the right ones.

Given the constraints, I'll box the corrected coefficients for all equations.

But for the sake of the response, I'll provide the final answer as the list of coefficients for each equation, corrected where necessary.

So for equation 8, it's 2,15,14,6 instead of 2,17,14,6

For equation 9, it's 1,2,2,2 instead of 1,1,2,2

Others are correct.

So the final answer is the set of coefficients as I've calculated.

To present it neatly:

1. 2, 1, 2
2. 1, 1, 1
3. 2, 2, 1
4. 1, 2, 1, 1
5. 2, 2, 2, 1
6. 1, 8, 10, 16
7. 2, 5, 4, 2
8. 2, 15, 14, 6
9. 1, 2, 2, 2
10. 2, 1, 2
11. 1, 4, 1, 2
12. 1, 1, 1
13. 2, 1, 1
14. 1, 6, 4
15. 4, 3, 1
16. 1, 4, 5, 1
17. 2, 4, 1, 4

This is the accurate balancing.

For equation 9, if the compound is actually Fe₃O₄, it would be different, but based on the given formula, this is correct.

I think this is the best I can do.

Final Answer will be this list.

But how to box it? Perhaps as a single string or list.

Since it's multiple equations, I'll write it as above.

In the response, I can state the coefficients for each.

But the instruction says "provide only the final correct answer", so I'll format it clearly.

Perhaps: The balanced coefficients for equations 1 to 17 are: [list]

But to save space, I'll write it in a compact form.

Given that, I'll proceed.