Problem Description:
The task involves evaluating algebraic expressions when the variable \( y \) is given a specific value, \( y = 6 \). The expressions involve basic arithmetic operations: addition and subtraction. We need to substitute \( y = 6 \) into each expression and simplify.
Given Expressions:
1. \( 7 - y \)
2. \( y + 6 \)
3. \( y - 12 \)
4. \( 13 - y \)
5. \( y + 14 \)
6. \( y + 13 \)
7. \( 1 + y \)
8. \( y + 9 \)
9. \( y - 14 \)
10. \( y - 1 \)
Solution:
#### Expression 1: \( 7 - y \)
Substitute \( y = 6 \):
\[
7 - y = 7 - 6 = 1
\]
#### Expression 2: \( y + 6 \)
Substitute \( y = 6 \):
\[
y + 6 = 6 + 6 = 12
\]
#### Expression 3: \( y - 12 \)
Substitute \( y = 6 \):
\[
y - 12 = 6 - 12 = -6
\]
#### Expression 4: \( 13 - y \)
Substitute \( y = 6 \):
\[
13 - y = 13 - 6 = 7
\]
#### Expression 5: \( y + 14 \)
Substitute \( y = 6 \):
\[
y + 14 = 6 + 14 = 20
\]
#### Expression 6: \( y + 13 \)
Substitute \( y = 6 \):
\[
y + 13 = 6 + 13 = 19
\]
#### Expression 7: \( 1 + y \)
Substitute \( y = 6 \):
\[
1 + y = 1 + 6 = 7
\]
#### Expression 8: \( y + 9 \)
Substitute \( y = 6 \):
\[
y + 9 = 6 + 9 = 15
\]
#### Expression 9: \( y - 14 \)
Substitute \( y = 6 \):
\[
y - 14 = 6 - 14 = -8
\]
#### Expression 10: \( y - 1 \)
Substitute \( y = 6 \):
\[
y - 1 = 6 - 1 = 5
\]
Final Answers:
\[
\boxed{
\begin{array}{ll}
1. & 1 \\
2. & 12 \\
3. & -6 \\
4. & 7 \\
5. & 20 \\
6. & 19 \\
7. & 7 \\
8. & 15 \\
9. & -8 \\
10. & 5 \\
\end{array}
}
\]
Explanation:
- For each expression, we replaced \( y \) with the given value \( 6 \).
- We then performed the indicated arithmetic operation (addition or subtraction) to simplify the expression.
- This method ensures that all expressions are evaluated correctly based on the provided value of \( y \).
Parent Tip: Review the logic above to help your child master the concept of pre algebra worksheets for 6th graders.