It looks like you've uploaded a list of
trigonometric identities to prove, but no specific image or problem was attached in this message. However, I can help you
solve and explain any of the trigonometric identities listed here.
Since you asked to "solve the problem" and "explain the solution," let's pick
one identity from the list as an example. Let’s go with:
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Problem: Prove the identity
>
1. $ \sec\theta - \tan\theta \sin\theta = \cos\theta $
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✔ Step-by-step Solution
We are to prove:
$$
\sec\theta - \tan\theta \sin\theta = \cos\theta
$$
---
#### 🔹 Step 1: Recall definitions
We know:
- $ \sec\theta = \frac{1}{\cos\theta} $
- $ \tan\theta = \frac{\sin\theta}{\cos\theta} $
Substitute these into the left-hand side (LHS):
$$
\text{LHS} = \sec\theta - \tan\theta \sin\theta = \frac{1}{\cos\theta} - \left( \frac{\sin\theta}{\cos\theta} \right) \cdot \sin\theta
$$
Simplify the second term:
$$
= \frac{1}{\cos\theta} - \frac{\sin^2\theta}{\cos\theta}
$$
Now combine the terms over the common denominator:
$$
= \frac{1 - \sin^2\theta}{\cos\theta}
$$
---
#### 🔹 Step 2: Use Pythagorean identity
Recall:
$$
\sin^2\theta + \cos^2\theta = 1 \Rightarrow 1 - \sin^2\theta = \cos^2\theta
$$
So:
$$
\frac{1 - \sin^2\theta}{\cos\theta} = \frac{\cos^2\theta}{\cos\theta} = \cos\theta
$$
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#### 🔹 Final Result:
$$
\text{LHS} = \cos\theta = \text{RHS}
$$
✔ Therefore, the identity is proven.
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📌 Summary
We used:
- Definitions of $ \sec\theta $ and $ \tan\theta $
- Algebraic simplification
- The Pythagorean identity $ 1 - \sin^2\theta = \cos^2\theta $
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If you'd like, I can walk through
any other identity from the list — just tell me which one (e.g., #2, #10, #35, etc.), and I’ll solve it step by step with full explanation.
Let me know!
Parent Tip: Review the logic above to help your child master the concept of pre calculus trig identities worksheet.