Chemistry worksheet on the nature of gases with handwritten solutions and annotations.

Let’s solve this step by step.

We are given:

- Initial volume of gas, V₁ = 2.5 L
- Initial pressure, P₁ = 1.0 atm
- Final volume, V₂ = ? (we need to find this)
- Final pressure, P₂ = 0.80 atm
- Temperature is constant → so we use Boyle’s Law

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Step 1: Recall Boyle’s Law

When temperature is constant, for a fixed amount of gas:

> P₁ × V₁ = P₂ × V₂

This means if pressure goes down, volume goes up — and vice versa.

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Step 2: Plug in the known values

P₁ = 1.0 atm
V₁ = 2.5 L
P₂ = 0.80 atm
V₂ = ?

So:

> 1.0 × 2.5 = 0.80 × V₂

That gives:

> 2.5 = 0.80 × V₂

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Step 3: Solve for V₂

Divide both sides by 0.80:

> V₂ = 2.5 ÷ 0.80

Let’s calculate that:

2.5 ÷ 0.80 = ?

You can think of it as:

2.5 ÷ 0.8 = 25 ÷ 8 = 3.125

(Or use calculator: 2.5 / 0.8 = 3.125)

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Step 4: Check units and reasonableness

Volume should be in liters → yes, 3.125 L

Does it make sense? Pressure decreased from 1.0 atm to 0.80 atm → so volume should increase. Original volume was 2.5 L → new volume 3.125 L is bigger → makes sense!

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Final Answer:
3.125 L