Grade 5 Prime Factor Trees Worksheet - Complete the factor trees to find the prime factors of each number.
Prime factor trees worksheet for Grade 5 students, featuring four factor trees to complete and find prime factors of numbers 30, 81, 56, and 72.
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Show Answer Key & Explanations
Step-by-step solution for: Prime Factorization worksheet
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Show Answer Key & Explanations
Step-by-step solution for: Prime Factorization worksheet
To solve this problem, we need to complete each factor tree by breaking down the numbers into their prime factors. A prime factor is a number that can only be divided by 1 and itself (like 2, 3, 5, 7, 11, etc.).
Let’s go one tree at a time.
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Tree 1: Number 30
We start with 30. It’s already split into 5 and a blank box.
Since 5 × ? = 30 → the missing number is 6.
Now break down 6: 6 = 2 × 3 (both are prime).
So the tree becomes:
- 30 → 5 and 6
- 6 → 2 and 3
Final prime factors: 5, 2, 3
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Tree 2: Number 81
81 is split into a blank box and 9.
Since 9 × ? = 81 → the missing number is 9.
Now break down each 9:
9 = 3 × 3 (both prime)
So both branches from 9 will be 3 and 3.
Final prime factors: 3, 3, 3, 3
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Tree 3: Number 56
56 is split into a blank circle and a blank square.
Let’s pick an easy factor pair. 56 ÷ 8 = 7 → so let’s say left circle is 7, right square is 8.
Now break down 8: 8 = 2 × 4 → but 4 isn’t prime, so break 4 further: 4 = 2 × 2.
So:
- 56 → 7 and 8
- 8 → 2 and 4
- 4 → 2 and 2
Final prime factors: 7, 2, 2, 2
*(Note: You could also start with 56 = 2 × 28, then 28 = 4 × 7, etc.—but the tree structure guides us. Since the left branch is a circle (likely meant to be prime), 7 makes sense there.)*
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Tree 4: Number 72
72 is split into two blank squares.
Let’s choose 8 and 9 (since 8 × 9 = 72).
Break down 8: 8 = 2 × 4 → then 4 = 2 × 2 → so 8 → 2, 2, 2
Break down 9: 9 = 3 × 3
So:
- 72 → 8 and 9
- 8 → 2 and 4 → 4 → 2 and 2
- 9 → 3 and 3
Final prime factors: 2, 2, 2, 3, 3
*(Alternative: 72 = 6 × 12, but again, the tree structure suggests splitting into two parts first — 8 and 9 works well here.)*
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Now, let’s fill in all the blanks as they appear in the original trees:
Tree 1 (30):
- Top: 30
- Left child: 5 (given)
- Right child (square): 6
- Children of 6: 2 and 3 (both circles)
Tree 2 (81):
- Top: 81
- Left child (square): 9
- Right child: 9 (given)
- Children of left 9: 3 and 3
- Children of right 9: 3 and 3
Tree 3 (56):
- Top: 56
- Left child (circle): 7
- Right child (square): 8
- Children of 8: left circle = 2, right square = 4
- Children of 4: 2 and 2
Tree 4 (72):
- Top: 72
- Left child (square): 8
- Right child (square): 9
- Children of 8: 2 and 4
- Children of 4: 2 and 2
- Children of 9: 3 and 3
Wait — looking back at the original image description for Tree 4:
> 72
> / \
> □ □
> / \ / \
> ○ ○ ○ □
> / \
> ○ ○
Actually, the right branch of 72 has a square that splits into two circles — meaning that square must be a composite number that breaks into two primes. So if we put 9 on the right, it splits into 3 and 3 — perfect.
On the left, 8 splits into 2 and 4 — but 4 is not prime, so the next level should break 4 into 2 and 2. But in the diagram, the left side of 72 has a square that splits into two circles — which implies those two circles are the final prime factors. That means the square under 72 on the left must be a number that breaks into two primes directly — like 8 breaks into 2 and 4? No, 4 isn’t prime.
Wait — perhaps the left square under 72 is meant to be 6? 6 = 2 × 3 — both prime. Then the right square is 12? 12 = 3 × 4 → no, 4 not prime. Or 12 = 2 × 6 → still not done.
Alternatively, maybe 72 = 36 × 2? But 36 is big.
Let me re-express based on standard factor trees and the diagram structure.
Looking again at Tree 4:
The root is 72.
It splits into two squares.
Left square splits into two circles → so left square must be a product of two primes → e.g., 6 (2×3), or 10 (2×5), etc.
Right square splits into a circle and a square → so right square must be a product of a prime and a composite → e.g., 12 = 3 × 4, then 4 = 2×2.
That fits!
So:
72 = 6 × 12
Left square: 6 → splits into 2 and 3 (circles)
Right square: 12 → splits into 3 and 4 (circle and square)
Then 4 → splits into 2 and 2 (circles)
Perfect match to the diagram.
So:
- 72 → 6 and 12
- 6 → 2 and 3
- 12 → 3 and 4
- 4 → 2 and 2
Final prime factors: 2, 3, 3, 2, 2 → same as before, just different path.
This matches the diagram exactly.
So let’s finalize all trees with correct placements:
---
Tree 1: 30
- 30 → 5 and 6
- 6 → 2 and 3
Blanks filled:
- Square under 30: 6
- Two circles under 6: 2 and 3
---
Tree 2: 81
- 81 → 9 and 9
- Each 9 → 3 and 3
Blanks filled:
- Left square under 81: 9
- Four circles: all 3s
---
Tree 3: 56
- 56 → 7 and 8
- 8 → 2 and 4
- 4 → 2 and 2
Blanks filled:
- Left circle: 7
- Right square: 8
- Circle under 8: 2
- Square under 8: 4
- Two circles under 4: 2 and 2
---
Tree 4: 72
- 72 → 6 and 12
- 6 → 2 and 3
- 12 → 3 and 4
- 4 → 2 and 2
Blanks filled:
- Left square: 6
- Right square: 12
- Circles under 6: 2 and 3
- Circle under 12: 3
- Square under 12: 4
- Circles under 4: 2 and 2
---
All calculations verified. Prime factorizations are correct.
Final Answer:
Tree 1: 6, 2, 3
Tree 2: 9, 3, 3, 3, 3
Tree 3: 7, 8, 2, 4, 2, 2
Tree 4: 6, 12, 2, 3, 3, 4, 2, 2
Let’s go one tree at a time.
---
Tree 1: Number 30
We start with 30. It’s already split into 5 and a blank box.
Since 5 × ? = 30 → the missing number is 6.
Now break down 6: 6 = 2 × 3 (both are prime).
So the tree becomes:
- 30 → 5 and 6
- 6 → 2 and 3
Final prime factors: 5, 2, 3
---
Tree 2: Number 81
81 is split into a blank box and 9.
Since 9 × ? = 81 → the missing number is 9.
Now break down each 9:
9 = 3 × 3 (both prime)
So both branches from 9 will be 3 and 3.
Final prime factors: 3, 3, 3, 3
---
Tree 3: Number 56
56 is split into a blank circle and a blank square.
Let’s pick an easy factor pair. 56 ÷ 8 = 7 → so let’s say left circle is 7, right square is 8.
Now break down 8: 8 = 2 × 4 → but 4 isn’t prime, so break 4 further: 4 = 2 × 2.
So:
- 56 → 7 and 8
- 8 → 2 and 4
- 4 → 2 and 2
Final prime factors: 7, 2, 2, 2
*(Note: You could also start with 56 = 2 × 28, then 28 = 4 × 7, etc.—but the tree structure guides us. Since the left branch is a circle (likely meant to be prime), 7 makes sense there.)*
---
Tree 4: Number 72
72 is split into two blank squares.
Let’s choose 8 and 9 (since 8 × 9 = 72).
Break down 8: 8 = 2 × 4 → then 4 = 2 × 2 → so 8 → 2, 2, 2
Break down 9: 9 = 3 × 3
So:
- 72 → 8 and 9
- 8 → 2 and 4 → 4 → 2 and 2
- 9 → 3 and 3
Final prime factors: 2, 2, 2, 3, 3
*(Alternative: 72 = 6 × 12, but again, the tree structure suggests splitting into two parts first — 8 and 9 works well here.)*
---
Now, let’s fill in all the blanks as they appear in the original trees:
Tree 1 (30):
- Top: 30
- Left child: 5 (given)
- Right child (square): 6
- Children of 6: 2 and 3 (both circles)
Tree 2 (81):
- Top: 81
- Left child (square): 9
- Right child: 9 (given)
- Children of left 9: 3 and 3
- Children of right 9: 3 and 3
Tree 3 (56):
- Top: 56
- Left child (circle): 7
- Right child (square): 8
- Children of 8: left circle = 2, right square = 4
- Children of 4: 2 and 2
Tree 4 (72):
- Top: 72
- Left child (square): 8
- Right child (square): 9
- Children of 8: 2 and 4
- Children of 4: 2 and 2
- Children of 9: 3 and 3
Wait — looking back at the original image description for Tree 4:
> 72
> / \
> □ □
> / \ / \
> ○ ○ ○ □
> / \
> ○ ○
Actually, the right branch of 72 has a square that splits into two circles — meaning that square must be a composite number that breaks into two primes. So if we put 9 on the right, it splits into 3 and 3 — perfect.
On the left, 8 splits into 2 and 4 — but 4 is not prime, so the next level should break 4 into 2 and 2. But in the diagram, the left side of 72 has a square that splits into two circles — which implies those two circles are the final prime factors. That means the square under 72 on the left must be a number that breaks into two primes directly — like 8 breaks into 2 and 4? No, 4 isn’t prime.
Wait — perhaps the left square under 72 is meant to be 6? 6 = 2 × 3 — both prime. Then the right square is 12? 12 = 3 × 4 → no, 4 not prime. Or 12 = 2 × 6 → still not done.
Alternatively, maybe 72 = 36 × 2? But 36 is big.
Let me re-express based on standard factor trees and the diagram structure.
Looking again at Tree 4:
The root is 72.
It splits into two squares.
Left square splits into two circles → so left square must be a product of two primes → e.g., 6 (2×3), or 10 (2×5), etc.
Right square splits into a circle and a square → so right square must be a product of a prime and a composite → e.g., 12 = 3 × 4, then 4 = 2×2.
That fits!
So:
72 = 6 × 12
Left square: 6 → splits into 2 and 3 (circles)
Right square: 12 → splits into 3 and 4 (circle and square)
Then 4 → splits into 2 and 2 (circles)
Perfect match to the diagram.
So:
- 72 → 6 and 12
- 6 → 2 and 3
- 12 → 3 and 4
- 4 → 2 and 2
Final prime factors: 2, 3, 3, 2, 2 → same as before, just different path.
This matches the diagram exactly.
So let’s finalize all trees with correct placements:
---
Tree 1: 30
- 30 → 5 and 6
- 6 → 2 and 3
Blanks filled:
- Square under 30: 6
- Two circles under 6: 2 and 3
---
Tree 2: 81
- 81 → 9 and 9
- Each 9 → 3 and 3
Blanks filled:
- Left square under 81: 9
- Four circles: all 3s
---
Tree 3: 56
- 56 → 7 and 8
- 8 → 2 and 4
- 4 → 2 and 2
Blanks filled:
- Left circle: 7
- Right square: 8
- Circle under 8: 2
- Square under 8: 4
- Two circles under 4: 2 and 2
---
Tree 4: 72
- 72 → 6 and 12
- 6 → 2 and 3
- 12 → 3 and 4
- 4 → 2 and 2
Blanks filled:
- Left square: 6
- Right square: 12
- Circles under 6: 2 and 3
- Circle under 12: 3
- Square under 12: 4
- Circles under 4: 2 and 2
---
All calculations verified. Prime factorizations are correct.
Final Answer:
Tree 1: 6, 2, 3
Tree 2: 9, 3, 3, 3, 3
Tree 3: 7, 8, 2, 4, 2, 2
Tree 4: 6, 12, 2, 3, 3, 4, 2, 2
Parent Tip: Review the logic above to help your child master the concept of prime factors worksheet.