2nd Grade Math Games - Free Printable

Let’s solve this step by step.

The title says “TABLES COVER UP to 5x5”, which means we’re working with multiplication facts from 0×0 up to 5×5. The top part shows two sets of numbers connected in pairs — like a matching game. Each pair is meant to be multiplied together, and the result should match one of the numbers in the big grid below.

Looking at the top section:

Left side:
- Top row: 3, 2, 0
- Bottom row: 4, 1, 5

They are connected vertically:
→ 3 × 4 = 12
→ 2 × 1 = 2
→ 0 × 5 = 0

Right side:
- Top row: 2, 1, 4
- Bottom row: 0, 5, 3

Connected vertically:
→ 2 × 0 = 0
→ 1 × 5 = 5
→ 4 × 3 = 12

So the products we get from the top part are:
12, 2, 0, 0, 5, 12

Now look at the big 6x6 grid. We need to find those exact numbers (12, 2, 0, 0, 5, 12) inside it and “cover them up” — meaning identify where they appear.

Let’s scan the grid row by row:

Row 1: 12, 10, 5, 8, 2, 0 → has 12, 5, 2, 0 ✔
Row 2: 15, 4, 12, 3, 1, 9 → has 12 ✔
Row 3: 6, 20, 8, 16, 5, 10 → has 5 ✔
Row 4: 25, 9, 6, 2, 20, 12 → has 2, 12 ✔
Row 5: 0, 6, 16, 4, 15, 1 → has 0 ✔
Row 6: 12, 10, 20, 9, 25, 8 → has 12 ✔

We found all the required numbers multiple times! But since the task is called “Cover Up”, it likely means you circle or mark each product that comes from the top pairs.

But wait — maybe the real goal is to use the top numbers as multipliers and find their products in the grid? Let’s double-check.

Actually, looking again — the top diagram has 6 boxes on top and 6 on bottom, paired into 6 multiplications. So there are 6 answers total:
From left: 3×4=12, 2×1=2, 0×5=0
From right: 2×0=0, 1×5=5, 4×3=12

So the six target numbers are: 12, 2, 0, 0, 5, 12

That’s three unique numbers: 0, 2, 5, 12 — but 0 and 12 appear twice.

In the grid, let’s count how many times each appears:

- 0: appears in Row1-Col6, Row5-Col1 → 2 times ✔ matches our two zeros
- 2: appears in Row1-Col5, Row4-Col4 → 2 times, but we only need one 2? Wait — no, we have only one 2 in our list? Let’s check:

Our list: [12, 2, 0, 0, 5, 12] → so:
- 12: twice
- 2: once
- 0: twice
- 5: once

Wait — I think I miscounted earlier.

From top:

Left column pairs:
1. 3 × 4 = 12
2. 2 × 1 = 2
3. 0 × 5 = 0

Right column pairs:
4. 2 × 0 = 0
5. 1 × 5 = 5
6. 4 × 3 = 12

So yes: 12, 2, 0, 0, 5, 12 → that’s correct.

So we need to find in the grid:
- Two 12s
- One 2
- Two 0s
- One 5

Now let’s locate them precisely in the grid (row, column):

Grid rows (1 to 6), columns (1 to 6):

Row 1: [12, 10, 5, 8, 2, 0]
→ Col1: 12 ✔ (first 12)
→ Col3: 5 ✔
→ Col5: 2 ✔
→ Col6: 0 ✔ (first 0)

Row 2: [15, 4, 12, 3, 1, 9]
→ Col3: 12 ✔ (second 12)

Row 3: [6, 20, 8, 16, 5, 10]
→ Col5: 5 → but we already used the 5 from Row1? Wait — we only need ONE 5. So if we take Row1-Col3 for 5, then we don’t need another.

But actually, the problem doesn’t say we can’t reuse — but logically, since we have exactly 6 products to cover, and the grid has many numbers, we just need to pick 6 cells that match our 6 results.

So best to assign:

Products needed: 12, 2, 0, 0, 5, 12

Assignments:

- First 12 → Row1, Col1
- Second 12 → Row2, Col3
- 2 → Row1, Col5
- First 0 → Row1, Col6
- Second 0 → Row5, Col1
- 5 → Row1, Col3 OR Row3, Col5 — either works, but Row1, Col3 is fine.

Wait — Row1, Col3 is 5, and Row1, Col5 is 2, Row1, Col6 is 0 — all in same row, that’s okay.

But let’s make sure we’re not missing anything.

Alternatively, perhaps the “cover up” means you multiply the top number by the bottom number in each vertical pair, and then find that product in the grid and cross it out.

Since there are 6 such pairs, you’ll cross out 6 numbers in the grid.

So final answer should be the positions or values? But the question doesn’t specify what to output.

Looking back at user request: “Solve the problem accurately.” And the image is a worksheet titled “Tables Cover Up to 5x5”.

Typically in such worksheets, you calculate the products from the top diagrams and then find and circle/mark those products in the grid.

Since the user didn’t ask for positions, and given the format, probably the expected answer is to list the six products that come from the top part.

Because the grid is just where you find them — but the actual “solution” is computing those six multiplications.

Moreover, in the context of “tables cover up”, it’s about practicing multiplication tables up to 5x5, so the key is to compute the products correctly.

So let’s confirm the six calculations again:

Top-left group:
- 3 × 4 = 12
- 2 × 1 = 2
- 0 × 5 = 0

Top-right group:
- 2 × 0 = 0
- 1 × 5 = 5
- 4 × 3 = 12

So the six products are: 12, 2, 0, 0, 5, 12

If we list them in order as per the diagram (left to right, top to bottom), it would be:

First row left: 3,2,0 → multiplied by below: 4,1,5 → gives 12,2,0
Then first row right: 2,1,4 → multiplied by below: 0,5,3 → gives 0,5,12

So sequence: 12, 2, 0, 0, 5, 12

Perhaps the answer is to write these six numbers.

Maybe sort them? But no instruction.

Given that, and since the problem is to “solve” it, I think providing the six computed products is the solution.

To be thorough, let’s verify each multiplication:

3 × 4 = 12 ✔️
2 × 1 = 2 ✔️
0 × 5 = 0 ✔️
2 × 0 = 0 ✔️
1 × 5 = 5 ✔️
4 × 3 = 12 ✔️

All correct.

Final Answer:
12, 2, 0, 0, 5, 12