Problem Description:
The task involves solving a series of multiplication problems where each problem multiplies two numbers, and both numbers are up to 10. The goal is to compute the product for each pair of numbers.
Solution Approach:
We will solve each multiplication problem step by step. The general formula for multiplication is:
\[
\text{Product} = \text{First Number} \times \text{Second Number}
\]
Step-by-Step Solution:
#### First Row:
1. \( 7 \times 5 \):
\[
7 \times 5 = 35
\]
2. \( 4 \times 3 \):
\[
4 \times 3 = 12
\]
3. \( 7 \times 5 \):
\[
7 \times 5 = 35
\]
4. \( 3 \times 9 \):
\[
3 \times 9 = 27
\]
#### Second Row:
5. \( 7 \times 4 \):
\[
7 \times 4 = 28
\]
6. \( 6 \times 3 \):
\[
6 \times 3 = 18
\]
7. \( 5 \times 2 \):
\[
5 \times 2 = 10
\]
8. \( 4 \times 5 \):
\[
4 \times 5 = 20
\]
#### Third Row:
9. \( 7 \times 4 \):
\[
7 \times 4 = 28
\]
10. \( 2 \times 2 \):
\[
2 \times 2 = 4
\]
11. \( 4 \times 1 \):
\[
4 \times 1 = 4
\]
12. \( 3 \times 4 \):
\[
3 \times 4 = 12
\]
#### Fourth Row:
13. \( 8 \times 5 \):
\[
8 \times 5 = 40
\]
14. \( 4 \times 9 \):
\[
4 \times 9 = 36
\]
15. \( 5 \times 5 \):
\[
5 \times 5 = 25
\]
16. \( 9 \times 3 \):
\[
9 \times 3 = 27
\]
Final Answers:
Combining all the results, we have:
\[
\begin{aligned}
&7 \times 5 = 35, &4 \times 3 = 12, &7 \times 5 = 35, &3 \times 9 = 27, \\
&7 \times 4 = 28, &6 \times 3 = 18, &5 \times 2 = 10, &4 \times 5 = 20, \\
&7 \times 4 = 28, &2 \times 2 = 4, &4 \times 1 = 4, &3 \times 4 = 12, \\
&8 \times 5 = 40, &4 \times 9 = 36, &5 \times 5 = 25, &9 \times 3 = 27.
\end{aligned}
\]
Boxed Final Answer:
\[
\boxed{35, 12, 35, 27, 28, 18, 10, 20, 28, 4, 4, 12, 40, 36, 25, 27}
\]
Parent Tip: Review the logic above to help your child master the concept of printable addition worksheets for grade 3.
