Four Corner Hart Chart Set, : Bernell Corporation - Free Printable
Educational worksheet: Four Corner Hart Chart Set, : Bernell Corporation. Download and print for classroom or home learning activities.
JPG
1000×1000
310.5 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #1766450
⭐
Show Answer Key & Explanations
Step-by-step solution for: Four Corner Hart Chart Set, : Bernell Corporation
▼
Show Answer Key & Explanations
Step-by-step solution for: Four Corner Hart Chart Set, : Bernell Corporation
Let’s solve this step by step.
We are given four cards with letters arranged in grids. Each card has a label at the bottom: “36pt - Card 2” and “36pt - Card 4”, etc. The task is likely to find which letters appear on both Card 2 and Card 4 — because that’s a common type of puzzle with these kinds of materials (like vision or memory tests).
But wait — let’s look again. Actually, looking at the layout:
There are two main cards shown side-by-side, but each is made of two parts stacked vertically? Or maybe it’s four separate cards? Let me check the labels.
Actually, from the image description (even though I can’t see it, based on your text), we have:
- Top-left grid: black letters only → labeled “2020 © Bernell Corporation” and below it says “36pt - Card 2”? Wait no — actually, looking at the structure:
From your input:
Left side:
Top part: 5 rows x 4 columns of black letters
Bottom part: 5 rows x 4 columns of colored letters → labeled “2020 © Bernell Corporation” and “36pt - Card 2”
Right side:
Top part: 5 rows x 4 columns of colored letters
Bottom part: 5 rows x 4 columns of black letters → labeled “2020 © Bernell Corporation” and “36pt - Card 4”
So actually, there are two full cards being shown:
→ Card 2 = left column (top black + bottom colored)
→ Card 4 = right column (top colored + bottom black)
But the question isn't stated! You said “solve the problem accurately” — but what is the actual problem?
Wait — perhaps the implied task is: Find all letters that appear on BOTH Card 2 and Card 4.
That makes sense for a matching or comparison task.
Let’s proceed under that assumption — since no explicit question was given, but this is a standard activity with such cards.
---
Step 1: List all unique letters on Card 2.
Card 2 consists of:
Top half (black letters):
Row 1: D Y M L
Row 2: C E X T
Row 3: Z B A V
Row 4: U S K G
Row 5: F R N O
Bottom half (colored letters):
Row 1: L F B J
Row 2: I Q X Z
Row 3: D T K U
Row 4: O W P H
Row 5: N S A V
Now combine all letters from Card 2 into one set (ignore duplicates for now):
Black letters: D,Y,M,L,C,E,X,T,Z,B,A,V,U,S,K,G,F,R,N,O
Colored letters: L,F,B,J,I,Q,X,Z,D,T,K,U,O,W,P,H,N,S,A,V
Combine them all:
Full list for Card 2 (unique letters):
A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z
Wait — that’s almost the whole alphabet!
Let’s count how many unique letters:
From black: D,Y,M,L,C,E,X,T,Z,B,A,V,U,S,K,G,F,R,N,O → 20 letters
From colored: L,F,B,J,I,Q,X,Z,D,T,K,U,O,W,P,H,N,S,A,V → adds J,I,Q,W,P,H → so total unique = 20 + 6 = 26? That’s the entire alphabet!
Check if any letter is missing:
Alphabet: A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
In Card 2:
A – yes (black row3, colored row5)
B – yes (black row3, colored row1)
C – yes (black row2)
D – yes (black row1, colored row3)
E – yes (black row2)
F – yes (black row5, colored row1)
G – yes (black row4)
H – yes (colored row4)
I – yes (colored row2)
J – yes (colored row1)
K – yes (black row4, colored row3)
L – yes (black row1, colored row1)
M – yes (black row1)
N – yes (black row5, colored row5)
O – yes (black row5, colored row4)
P – yes (colored row4)
Q – yes (colored row2)
R – yes (black row5)
S – yes (black row4, colored row5)
T – yes (black row2, colored row3)
U – yes (black row4, colored row3)
V – yes (black row3, colored row5)
W – yes (colored row4)
X – yes (black row2, colored row2)
Y – yes (black row1)
Z – yes (black row3, colored row2)
✔ So Card 2 contains ALL 26 letters of the alphabet.
---
Step 2: Now do the same for Card 4.
Card 4:
Top half (colored letters):
Row 1: H J U M
Row 2: S D O V
Row 3: X A W G
Row 4: Y S E I
Row 5: T C R L
Bottom half (black letters):
Row 1: R K C E
Row 2: D M X O
Row 3: I Y F N
Row 4: W H V J
Row 5: B A T Z
List all letters from Card 4:
Colored top: H,J,U,M,S,D,O,V,X,A,W,G,Y,S,E,I,T,C,R,L
Black bottom: R,K,C,E,D,M,X,O,I,Y,F,N,W,H,V,J,B,A,T,Z
Combine and get unique letters:
Start listing:
A – yes (colored row3, black row5)
B – yes (black row5)
C – yes (colored row5, black row1)
D – yes (colored row2, black row2)
E – yes (colored row4, black row1)
F – yes (black row3)
G – yes (colored row3)
H – yes (colored row1, black row4)
I – yes (colored row4, black row3)
J – yes (colored row1, black row4)
K – yes (black row1)
L – yes (colored row5)
M – yes (colored row1, black row2)
N – yes (black row3)
O – yes (colored row2, black row2)
P – ??? Not seen yet
Q – ??? Not seen
R – yes (colored row5, black row1)
S – yes (colored row2 and row4)
T – yes (colored row5, black row5)
U – yes (colored row1)
V – yes (colored row2, black row4)
W – yes (colored row3, black row4)
X – yes (colored row3, black row2)
Y – yes (colored row4, black row3)
Z – yes (black row5)
Missing: P and Q
Check again:
Is P anywhere? Look through all positions:
Colored top: H J U M / S D O V / X A W G / Y S E I / T C R L → no P
Black bottom: R K C E / D M X O / I Y F N / W H V J / B A T Z → no P
Q? Same — not present.
So Card 4 has 24 letters: missing P and Q.
---
Step 3: Find letters that appear on BOTH Card 2 and Card 4.
Since Card 2 has all 26 letters, the intersection is just all letters that are in Card 4.
So answer = all letters in Card 4 = 24 letters: everything except P and Q.
But wait — maybe the task is different? Maybe it’s to find letters that are in the SAME position? Or same color? But without an explicit question, the most logical task is “which letters appear on both cards”.
Alternatively, perhaps the task is to compare the two cards and list letters that are repeated across them — which again, since Card 2 has all, it’s just Card 4’s letters.
But let’s double-check: maybe the user meant to ask something else? Since you didn’t specify the question, but in educational contexts with these cards, often the task is to identify matching letters between two cards.
Another possibility: maybe “find the letters that are in both the top and bottom halves of each card?” But that seems less likely.
Given the information, safest assumption: find letters common to Card 2 and Card 4.
As established:
Card 2: all 26 letters
Card 4: 24 letters (missing P, Q)
Therefore, common letters = 24 letters: A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,R,S,T,U,V,W,X,Y,Z
Missing from common: P, Q
But let’s verify if P or Q appear in Card 4 — we already did: no.
Wait — in Card 2, P appears in colored row4: “O W P H” → yes, P is there.
Q appears in Card 2 colored row2: “I Q X Z” → yes.
But not in Card 4.
So final answer: All letters except P and Q.
But perhaps the expected answer is to list them? Or count?
Maybe the task is to find how many letters are shared? Then 24.
But since no specific instruction, I’ll assume we need to list the letters that appear on both cards.
However, writing all 24 might be tedious. Alternatively, state which are missing.
But let’s think differently — perhaps the real task is hidden in the way the cards are presented.
Looking back at your original message: you said “the user uploaded an image containing a task” — but didn’t specify what the task is. In many such worksheets, the task is written on the page — like “Circle the letters that appear on both cards” or “How many letters are the same?”
Since it’s not specified, and to give a useful answer, I’ll go with:
The letters that appear on both Card 2 and Card 4 are all letters of the alphabet except P and Q.
To write it neatly:
Final Answer: A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, R, S, T, U, V, W, X, Y, Z
Or, more concisely: All letters except P and Q.
But since the format requires a final answer after reasoning, and to be precise, I'll list them.
Wait — let me confirm once more if P or Q are in Card 4.
Card 4 colored top:
H J U M
S D O V
X A W G
Y S E I
T C R L → no P or Q
Card 4 black bottom:
R K C E
D M X O
I Y F N
W H V J
B A T Z → still no P or Q
Yes.
And Card 2 has both.
So intersection excludes P and Q.
Perhaps the problem is to find letters that are in the same position? But that would be very complex and unlikely without instructions.
I think my approach is correct.
Final Answer: A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, R, S, T, U, V, W, X, Y, Z
We are given four cards with letters arranged in grids. Each card has a label at the bottom: “36pt - Card 2” and “36pt - Card 4”, etc. The task is likely to find which letters appear on both Card 2 and Card 4 — because that’s a common type of puzzle with these kinds of materials (like vision or memory tests).
But wait — let’s look again. Actually, looking at the layout:
There are two main cards shown side-by-side, but each is made of two parts stacked vertically? Or maybe it’s four separate cards? Let me check the labels.
Actually, from the image description (even though I can’t see it, based on your text), we have:
- Top-left grid: black letters only → labeled “2020 © Bernell Corporation” and below it says “36pt - Card 2”? Wait no — actually, looking at the structure:
From your input:
Left side:
Top part: 5 rows x 4 columns of black letters
Bottom part: 5 rows x 4 columns of colored letters → labeled “2020 © Bernell Corporation” and “36pt - Card 2”
Right side:
Top part: 5 rows x 4 columns of colored letters
Bottom part: 5 rows x 4 columns of black letters → labeled “2020 © Bernell Corporation” and “36pt - Card 4”
So actually, there are two full cards being shown:
→ Card 2 = left column (top black + bottom colored)
→ Card 4 = right column (top colored + bottom black)
But the question isn't stated! You said “solve the problem accurately” — but what is the actual problem?
Wait — perhaps the implied task is: Find all letters that appear on BOTH Card 2 and Card 4.
That makes sense for a matching or comparison task.
Let’s proceed under that assumption — since no explicit question was given, but this is a standard activity with such cards.
---
Step 1: List all unique letters on Card 2.
Card 2 consists of:
Top half (black letters):
Row 1: D Y M L
Row 2: C E X T
Row 3: Z B A V
Row 4: U S K G
Row 5: F R N O
Bottom half (colored letters):
Row 1: L F B J
Row 2: I Q X Z
Row 3: D T K U
Row 4: O W P H
Row 5: N S A V
Now combine all letters from Card 2 into one set (ignore duplicates for now):
Black letters: D,Y,M,L,C,E,X,T,Z,B,A,V,U,S,K,G,F,R,N,O
Colored letters: L,F,B,J,I,Q,X,Z,D,T,K,U,O,W,P,H,N,S,A,V
Combine them all:
Full list for Card 2 (unique letters):
A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z
Wait — that’s almost the whole alphabet!
Let’s count how many unique letters:
From black: D,Y,M,L,C,E,X,T,Z,B,A,V,U,S,K,G,F,R,N,O → 20 letters
From colored: L,F,B,J,I,Q,X,Z,D,T,K,U,O,W,P,H,N,S,A,V → adds J,I,Q,W,P,H → so total unique = 20 + 6 = 26? That’s the entire alphabet!
Check if any letter is missing:
Alphabet: A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
In Card 2:
A – yes (black row3, colored row5)
B – yes (black row3, colored row1)
C – yes (black row2)
D – yes (black row1, colored row3)
E – yes (black row2)
F – yes (black row5, colored row1)
G – yes (black row4)
H – yes (colored row4)
I – yes (colored row2)
J – yes (colored row1)
K – yes (black row4, colored row3)
L – yes (black row1, colored row1)
M – yes (black row1)
N – yes (black row5, colored row5)
O – yes (black row5, colored row4)
P – yes (colored row4)
Q – yes (colored row2)
R – yes (black row5)
S – yes (black row4, colored row5)
T – yes (black row2, colored row3)
U – yes (black row4, colored row3)
V – yes (black row3, colored row5)
W – yes (colored row4)
X – yes (black row2, colored row2)
Y – yes (black row1)
Z – yes (black row3, colored row2)
✔ So Card 2 contains ALL 26 letters of the alphabet.
---
Step 2: Now do the same for Card 4.
Card 4:
Top half (colored letters):
Row 1: H J U M
Row 2: S D O V
Row 3: X A W G
Row 4: Y S E I
Row 5: T C R L
Bottom half (black letters):
Row 1: R K C E
Row 2: D M X O
Row 3: I Y F N
Row 4: W H V J
Row 5: B A T Z
List all letters from Card 4:
Colored top: H,J,U,M,S,D,O,V,X,A,W,G,Y,S,E,I,T,C,R,L
Black bottom: R,K,C,E,D,M,X,O,I,Y,F,N,W,H,V,J,B,A,T,Z
Combine and get unique letters:
Start listing:
A – yes (colored row3, black row5)
B – yes (black row5)
C – yes (colored row5, black row1)
D – yes (colored row2, black row2)
E – yes (colored row4, black row1)
F – yes (black row3)
G – yes (colored row3)
H – yes (colored row1, black row4)
I – yes (colored row4, black row3)
J – yes (colored row1, black row4)
K – yes (black row1)
L – yes (colored row5)
M – yes (colored row1, black row2)
N – yes (black row3)
O – yes (colored row2, black row2)
P – ??? Not seen yet
Q – ??? Not seen
R – yes (colored row5, black row1)
S – yes (colored row2 and row4)
T – yes (colored row5, black row5)
U – yes (colored row1)
V – yes (colored row2, black row4)
W – yes (colored row3, black row4)
X – yes (colored row3, black row2)
Y – yes (colored row4, black row3)
Z – yes (black row5)
Missing: P and Q
Check again:
Is P anywhere? Look through all positions:
Colored top: H J U M / S D O V / X A W G / Y S E I / T C R L → no P
Black bottom: R K C E / D M X O / I Y F N / W H V J / B A T Z → no P
Q? Same — not present.
So Card 4 has 24 letters: missing P and Q.
---
Step 3: Find letters that appear on BOTH Card 2 and Card 4.
Since Card 2 has all 26 letters, the intersection is just all letters that are in Card 4.
So answer = all letters in Card 4 = 24 letters: everything except P and Q.
But wait — maybe the task is different? Maybe it’s to find letters that are in the SAME position? Or same color? But without an explicit question, the most logical task is “which letters appear on both cards”.
Alternatively, perhaps the task is to compare the two cards and list letters that are repeated across them — which again, since Card 2 has all, it’s just Card 4’s letters.
But let’s double-check: maybe the user meant to ask something else? Since you didn’t specify the question, but in educational contexts with these cards, often the task is to identify matching letters between two cards.
Another possibility: maybe “find the letters that are in both the top and bottom halves of each card?” But that seems less likely.
Given the information, safest assumption: find letters common to Card 2 and Card 4.
As established:
Card 2: all 26 letters
Card 4: 24 letters (missing P, Q)
Therefore, common letters = 24 letters: A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,R,S,T,U,V,W,X,Y,Z
Missing from common: P, Q
But let’s verify if P or Q appear in Card 4 — we already did: no.
Wait — in Card 2, P appears in colored row4: “O W P H” → yes, P is there.
Q appears in Card 2 colored row2: “I Q X Z” → yes.
But not in Card 4.
So final answer: All letters except P and Q.
But perhaps the expected answer is to list them? Or count?
Maybe the task is to find how many letters are shared? Then 24.
But since no specific instruction, I’ll assume we need to list the letters that appear on both cards.
However, writing all 24 might be tedious. Alternatively, state which are missing.
But let’s think differently — perhaps the real task is hidden in the way the cards are presented.
Looking back at your original message: you said “the user uploaded an image containing a task” — but didn’t specify what the task is. In many such worksheets, the task is written on the page — like “Circle the letters that appear on both cards” or “How many letters are the same?”
Since it’s not specified, and to give a useful answer, I’ll go with:
The letters that appear on both Card 2 and Card 4 are all letters of the alphabet except P and Q.
To write it neatly:
Final Answer: A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, R, S, T, U, V, W, X, Y, Z
Or, more concisely: All letters except P and Q.
But since the format requires a final answer after reasoning, and to be precise, I'll list them.
Wait — let me confirm once more if P or Q are in Card 4.
Card 4 colored top:
H J U M
S D O V
X A W G
Y S E I
T C R L → no P or Q
Card 4 black bottom:
R K C E
D M X O
I Y F N
W H V J
B A T Z → still no P or Q
Yes.
And Card 2 has both.
So intersection excludes P and Q.
Perhaps the problem is to find letters that are in the same position? But that would be very complex and unlikely without instructions.
I think my approach is correct.
Final Answer: A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, R, S, T, U, V, W, X, Y, Z
Parent Tip: Review the logic above to help your child master the concept of printable hart chart.