Free Printable Sudoku for Kids - Free Printable

To solve the Sudoku puzzles, we need to follow the basic rules of Sudoku:

1. Each row must contain the digits 1 through 4 exactly once.
2. Each column must contain the digits 1 through 4 exactly once.
3. Each 2x2 subgrid (box) must contain the digits 1 through 4 exactly once.

Let's solve each puzzle step by step.

---

Puzzle 1

```
1 _ _ _
_ _ _ 1
2 _ _ _
_ 4 _ 2
```

#### Step-by-Step Solution:
1. Row 1: The first cell is 1. The last cell in Row 4 is 2. So, Row 1 must have 3 and 4.
- Since Column 4 already has a 1, Row 1 cannot have a 1 in Column 4.
- Place 3 in Row 1, Column 4: `1 _ _ 3`.
- Now, Row 1 needs 2 and 4. Place 2 in Row 1, Column 2, and 4 in Row 1, Column 3: `1 2 4 3`.

2. Row 4: The second cell is 4, and the last cell is 2. So, Row 4 needs 1 and 3.
- Since Column 1 already has a 1, Row 4 cannot have a 1 in Column 1.
- Place 1 in Row 4, Column 1, and 3 in Row 4, Column 3: `1 4 3 2`.

3. Column 4: The top cell is 3, and the bottom cell is 2. So, Column 4 needs 1 and 4.
- Since Row 2 already has a 1, Column 4 cannot have a 1 in Row 2.
- Place 1 in Row 2, Column 4, and 4 in Row 3, Column 4: `_ _ 1 4`.

4. Row 2: The last cell is 1. So, Row 2 needs 3 and 4.
- Since Column 2 already has a 2, Row 2 cannot have a 2 in Column 2.
- Place 3 in Row 2, Column 2, and 4 in Row 2, Column 3: `_ 3 4 1`.

5. Row 3: The middle cell is 4, and the last cell is 2. So, Row 3 needs 1 and 3.
- Since Column 1 already has a 1, Row 3 cannot have a 1 in Column 1.
- Place 1 in Row 3, Column 1, and 3 in Row 3, Column 2: `1 3 4 2`.

#### Final Solution for Puzzle 1:
```
1 2 4 3
3 4 1 2
1 3 4 2
1 4 3 2
```

---

Puzzle 2

```
_ _ _ 3
_ 3 1 _
_ 4 2 _
2 _ _ _
```

#### Step-by-Step Solution:
1. Row 4: The first cell is 2. So, Row 4 needs 1, 3, and 4.
- Since Column 2 already has a 3, Row 4 cannot have a 3 in Column 2.
- Place 1 in Row 4, Column 2, and 3 in Row 4, Column 3: `2 1 3 _`.

2. Column 4: The top cell is 3. So, Column 4 needs 1, 2, and 4.
- Since Row 3 already has a 2, Column 4 cannot have a 2 in Row 3.
- Place 2 in Row 1, Column 4, and 4 in Row 3, Column 4: `_ _ 2 3`.

3. Row 1: The last cell is 3. So, Row 1 needs 1, 2, and 4.
- Since Column 1 already has a 2, Row 1 cannot have a 2 in Column 1.
- Place 1 in Row 1, Column 1, and 4 in Row 1, Column 2: `1 4 2 3`.

4. Row 3: The second cell is 4, and the third cell is 2. So, Row 3 needs 1 and 3.
- Since Column 1 already has a 1, Row 3 cannot have a 1 in Column 1.
- Place 3 in Row 3, Column 1, and 1 in Row 3, Column 4: `3 4 2 1`.

5. Row 2: The second cell is 3, and the third cell is 1. So, Row 2 needs 2 and 4.
- Since Column 1 already has a 1, Row 2 cannot have a 1 in Column 1.
- Place 4 in Row 2, Column 1, and 2 in Row 2, Column 4: `4 3 1 2`.

#### Final Solution for Puzzle 2:
```
1 4 2 3
4 3 1 2
3 4 2 1
2 1 3 4
```

---

Puzzle 3

```
_ _ _ 2
_ 2 3 _
_ 4 1 _
1 _ _ _
```

#### Step-by-Step Solution:
1. Row 4: The first cell is 1. So, Row 4 needs 2, 3, and 4.
- Since Column 2 already has a 2, Row 4 cannot have a 2 in Column 2.
- Place 3 in Row 4, Column 2, and 4 in Row 4, Column 3: `1 3 4 _`.

2. Column 4: The top cell is 2. So, Column 4 needs 1, 3, and 4.
- Since Row 3 already has a 1, Column 4 cannot have a 1 in Row 3.
- Place 3 in Row 3, Column 4, and 4 in Row 2, Column 4: `_ _ 3 4`.

3. Row 1: The last cell is 2. So, Row 1 needs 1, 3, and 4.
- Since Column 1 already has a 1, Row 1 cannot have a 1 in Column 1.
- Place 3 in Row 1, Column 1, and 4 in Row 1, Column 2: `3 4 _ 2`.

4. Row 3: The second cell is 4, and the third cell is 1. So, Row 3 needs 2 and 3.
- Since Column 1 already has a 3, Row 3 cannot have a 3 in Column 1.
- Place 2 in Row 3, Column 1, and 3 in Row 3, Column 4: `2 4 1 3`.

5. Row 2: The second cell is 2, and the third cell is 3. So, Row 2 needs 1 and 4.
- Since Column 1 already has a 2, Row 2 cannot have a 2 in Column 1.
- Place 1 in Row 2, Column 1, and 4 in Row 2, Column 4: `1 2 3 4`.

#### Final Solution for Puzzle 3:
```
3 4 1 2
1 2 3 4
2 4 1 3
1 3 4 2
```

---

Final Answers

1. Puzzle 1:
```
1 2 4 3
3 4 1 2
1 3 4 2
1 4 3 2
```

2. Puzzle 2:
```
1 4 2 3
4 3 1 2
3 4 2 1
2 1 3 4
```

3. Puzzle 3:
```
3 4 1 2
1 2 3 4
2 4 1 3
1 3 4 2
```

Boxed Final Answer:
\[
\boxed{
\begin{array}{|c|c|c|c|}
\hline
1 & 2 & 4 & 3 \\
\hline
3 & 4 & 1 & 2 \\
\hline
1 & 3 & 4 & 2 \\
\hline
1 & 4 & 3 & 2 \\
\hline
\end{array}
\quad
\begin{array}{|c|c|c|c|}
\hline
1 & 4 & 2 & 3 \\
\hline
4 & 3 & 1 & 2 \\
\hline
3 & 4 & 2 & 1 \\
\hline
2 & 1 & 3 & 4 \\
\hline
\end{array}
\quad
\begin{array}{|c|c|c|c|}
\hline
3 & 4 & 1 & 2 \\
\hline
1 & 2 & 3 & 4 \\
\hline
2 & 4 & 1 & 3 \\
\hline
1 & 3 & 4 & 2 \\
\hline
\end{array}
}
\]