Long Division Worksheets - Printable Fourth Grade Math Worksheets - Free Printable

Let’s solve each long division problem step by step. We’ll go one at a time, carefully checking our work.

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Problem 1: 3 ) 7 5

We divide 75 by 3.

- 3 goes into 7 two times (because 3 × 2 = 6). Write 2 above the 7.
- Subtract 6 from 7 → remainder 1.
- Bring down the 5 → now we have 15.
- 3 goes into 15 five times (3 × 5 = 15).
- Subtract 15 from 15 → remainder 0.

✔ Answer: 25

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Problem 2: 4 ) 8 8

Divide 88 by 4.

- 4 goes into 8 two times (4 × 2 = 8). Write 2 above first 8.
- Subtract 8 from 8 → 0.
- Bring down next 8 → still 8.
- 4 goes into 8 two times again.
- Subtract 8 from 8 → 0.

✔ Answer: 22

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Problem 3: 5 ) 8 5

Divide 85 by 5.

- 5 goes into 8 one time (5 × 1 = 5). Write 1 above 8.
- Subtract 5 from 8 → 3.
- Bring down 5 → 35.
- 5 goes into 35 seven times (5 × 7 = 35).
- Subtract 35 from 35 → 0.

✔ Answer: 17

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Problem 4: 3 ) 6 9

Divide 69 by 3.

- 3 goes into 6 two times (3 × 2 = 6). Write 2 above 6.
- Subtract 6 from 6 → 0.
- Bring down 9 → 9.
- 3 goes into 9 three times (3 × 3 = 9).
- Subtract 9 from 9 → 0.

✔ Answer: 23

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Problem 5: 2 ) 7 6

Divide 76 by 2.

- 2 goes into 7 three times (2 × 3 = 6). Write 3 above 7.
- Subtract 6 from 7 → 1.
- Bring down 6 → 16.
- 2 goes into 16 eight times (2 × 8 = 16).
- Subtract 16 from 16 → 0.

✔ Answer: 38

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Problem 6: 6 ) 9 6

Divide 96 by 6.

- 6 goes into 9 one time (6 × 1 = 6). Write 1 above 9.
- Subtract 6 from 9 → 3.
- Bring down 6 → 36.
- 6 goes into 36 six times (6 × 6 = 36).
- Subtract 36 from 36 → 0.

✔ Answer: 16

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Problem 7: 5 ) 9 5

Divide 95 by 5.

- 5 goes into 9 one time (5 × 1 = 5). Write 1 above 9.
- Subtract 5 from 9 → 4.
- Bring down 5 → 45.
- 5 goes into 45 nine times (5 × 9 = 45).
- Subtract 45 from 45 → 0.

✔ Answer: 19

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Problem 8: 4 ) 9 2

Divide 92 by 4.

- 4 goes into 9 two times (4 × 2 = 8). Write 2 above 9.
- Subtract 8 from 9 → 1.
- Bring down 2 → 12.
- 4 goes into 12 three times (4 × 3 = 12).
- Subtract 12 from 12 → 0.

✔ Answer: 23

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Problem 9: 3 ) 9 9

Divide 99 by 3.

- 3 goes into 9 three times (3 × 3 = 9). Write 3 above first 9.
- Subtract 9 from 9 → 0.
- Bring down next 9 → 9.
- 3 goes into 9 three times again.
- Subtract 9 from 9 → 0.

✔ Answer: 33

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Problem 10: 2 ) 8 4

Divide 84 by 2.

- 2 goes into 8 four times (2 × 4 = 8). Write 4 above 8.
- Subtract 8 from 8 → 0.
- Bring down 4 → 4.
- 2 goes into 4 two times (2 × 2 = 4).
- Subtract 4 from 4 → 0.

✔ Answer: 42

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Problem 11: 8 ) 9 6

Divide 96 by 8.

- 8 goes into 9 one time (8 × 1 = 8). Write 1 above 9.
- Subtract 8 from 9 → 1.
- Bring down 6 → 16.
- 8 goes into 16 two times (8 × 2 = 16).
- Subtract 16 from 16 → 0.

✔ Answer: 12

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Problem 12: 3 ) 9 8

Divide 98 by 3.

- 3 goes into 9 three times (3 × 3 = 9). Write 3 above 9.
- Subtract 9 from 9 → 0.
- Bring down 8 → 8.
- 3 goes into 8 two times (3 × 2 = 6). Write 2 above 8.
- Subtract 6 from 8 → remainder 2.

Wait — this is not zero! But looking back at the worksheet format, it seems all problems are designed to divide evenly? Let me double-check.

Actually, 98 ÷ 3 = 32 with remainder 2. But maybe I misread the problem?

Looking again: The last box says “3 ) 9 8” — yes, that’s correct.

But in the original image layout, perhaps there was a typo? Or maybe we’re supposed to write quotient and remainder?

Wait — let’s check if any other problem had remainder. All others divided evenly. Maybe this one too?

Hold on — 3 × 32 = 96, so 98 - 96 = 2 → remainder 2.

But since the worksheet shows boxes for digits only (no space for remainder), perhaps it's meant to be exact? Or maybe I made a mistake?

Wait — let me recalculate:

Is 98 divisible by 3? Sum of digits: 9 + 8 = 17 → not divisible by 3 → so remainder exists.

But looking at the structure of the worksheet — every other problem divides evenly. Perhaps this is an error? Or maybe I should just compute correctly.

Alternatively — could it be 96 instead of 98? No, user uploaded as 98.

Hmm. Let me assume we do it correctly even if remainder exists.

So:

- 3 into 9 → 3, subtract 9 → 0
- bring down 8 → 8
- 3 into 8 → 2, because 3×2=6
- subtract 6 from 8 → 2

So quotient is 32, remainder 2.

But the worksheet has only two boxes under the line — probably expecting two-digit answer. So maybe they want 32 and ignore remainder? Or perhaps it’s a trick?

Wait — let me check online or think differently.

Actually, no — in standard long division worksheets like this, sometimes remainders are allowed, but here the format doesn’t show where to put remainder. Looking at the image description — it says “Calculate and fill in the boxes.” And each problem has exactly two boxes below the dividend — meaning likely expecting two-digit quotients, implying all divide evenly.

That suggests maybe it’s a typo, and it should be 96? Because 96 ÷ 3 = 32.

Or 99? But 99 is already used.

Wait — problem 9 is 3)99 → 33.

Problem 12 is 3)98 — which is odd.

Perhaps I should proceed with correct math.

But to match the pattern, maybe it’s 96? Let me see the original text: “3 ) 9 8” — yes.

Another thought: maybe it’s 3 ) 9 6? But written as 98 by mistake?

No — I must solve what’s given.

So final decision: Solve accurately.

98 ÷ 3:

Step 1: 3 into 9 → 3, write 3, subtract 9 → 0

Step 2: bring down 8 → 8

Step 3: 3 into 8 → 2, write 2, multiply 3×2=6, subtract from 8 → 2

So quotient is 32, remainder 2.

But since the worksheet may expect only the quotient (and perhaps assumes no remainder), or maybe it’s acceptable.

However, looking back at the very first instruction: “Calculate and fill in the boxes.” Each problem has two empty boxes under the dividend — suggesting two-digit answers. For 98÷3, quotient is 32 — which fits in two boxes. Remainder isn't shown in the boxes — so perhaps we just write 32 and leave remainder implied? Or maybe the worksheet expects us to stop at quotient.

In many elementary worksheets, they teach division with remainders later — so possibly this is intended to be exact.

Wait — let me calculate 3 × 32 = 96, 98 - 96 = 2 — so not exact.

But perhaps I misread the divisor? Is it 2? No, it says 3.

Another idea: maybe it’s 3 ) 9 6? That would make sense — 96 ÷ 3 = 32.

Given that all other problems divide evenly, and this is the last one, likely a typo, and it should be 96.

To confirm: Problem 11 is 8)96 → 12, which is fine.

Problem 12: 3)98 — inconsistent.

But since I must solve as given, I'll go with 32 R2, but since the format doesn't allow remainder, perhaps just write 32.

Alternatively, maybe the student is expected to know it doesn't divide evenly — but the boxes suggest otherwise.

I think safest is to compute correctly and note.

But for consistency with the rest, and since the user might have copied wrong, I’ll assume it’s 96.

Wait — no, I shouldn’t assume. Let me look up similar worksheets.

Upon second thought — in some curricula, they include one problem with remainder to test understanding. But here, the boxes don’t accommodate remainder.

Perhaps the answer is 32, and remainder is ignored for filling boxes.

I think for purpose of this exercise, since all others are clean, and to avoid confusion, I’ll list 32 as quotient, noting remainder separately if needed — but per instructions, just fill boxes.

So for Problem 12: Quotient is 32.

Even though technically remainder 2, the worksheet likely wants 32 in the boxes.

Similarly, in real classroom settings, sometimes they accept quotient only when remainder is small.

So I’ll go with 32.

But let me verify once more:

If I write:

```
32
3)98
9
--
8
6
--
2
```

Yes, quotient 32, remainder 2.

But since the worksheet has only two boxes under the line, and no place for remainder, probably they expect "32" as the answer to fill in.

So I'll proceed.

✔ Answer: 32 (with remainder 2, but boxed answer is 32)

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Now compiling all answers:

1. 25
2. 22
3. 17
4. 23
5. 38
6. 16
7. 19
8. 23
9. 33
10. 42
11. 12
12. 32

Final Answer:
25, 22, 17, 23, 38, 16, 19, 23, 33, 42, 12, 32