Structured math worksheet featuring grid paper to help students practice multiplying decimals with varying degrees of difficulty.

Let’s solve each multiplication problem step by step.

We’ll multiply the numbers as if they were whole numbers first, then count how many decimal places are in the original numbers and put the decimal point in the answer accordingly.

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Problem 1: 0.35 × 0.9

Step 1: Multiply 35 × 9 = 315
Step 2: Count decimal places — 0.35 has 2, 0.9 has 1 → total 3 decimal places
Step 3: Put decimal in 315 → 0.315 ✔ (already shown)

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Problem 2: 0.34 × 0.05

Step 1: Multiply 34 × 5 = 170
Step 2: Decimal places — 0.34 has 2, 0.05 has 2 → total 4
Step 3: Put decimal in 170 → 0.0170 → which is 0.017

Wait — let’s check:
0.34 × 0.05 = ?
Actually, 34 × 5 = 170 → with 4 decimal places → 0.0170 → yes, 0.017

But wait — 0.0170 is same as 0.017, but we should write it as 0.0170? No — trailing zero after decimal doesn’t matter unless specified. But actually, 0.0170 is correct for 4 decimal places? Let me recalculate:

0.34 × 0.05
= (34/100) × (5/100) = 170 / 10000 = 0.0170 → so 0.017 is fine, but technically 0.0170 has 4 decimal places. However, we usually drop trailing zeros. So final answer: 0.017

Wait — no! 170 divided by 10000 is 0.0170 — that’s 4 digits after decimal: 0.0170 → but 0.0170 = 0.017? Actually, no — 0.0170 means 170 ten-thousandths, which is same as 17 thousandths? Wait:

0.0170 = 170/10000 = 17/1000 = 0.017 → yes, same value.

But to be precise with decimal places, we write 0.0170? No — standard practice is to write without trailing zeros unless needed. So 0.017 is acceptable.

Actually, let’s do it properly:

0.34 × 0.05
Multiply: 34 × 5 = 170
Decimal places: 2 + 2 = 4 → so move decimal 4 places left from 170 → 0.0170 → which is 0.017

But 0.0170 is written as 0.017 — yes.

Wait — I think I made a mistake. 170 with 4 decimal places: start from right of 170, move 4 places left:

170 → .170 → .0170 → .00170? No:

Number is 170. To put 4 decimal places: write as 0.0170

Yes: 0.0170

But 0.0170 = 0.017 — so we can write 0.017

However, in some contexts, they want exact decimal places. Since 0.34 has 2, 0.05 has 2, answer should have 4 decimal places → so 0.0170

But 0.0170 is same as 0.017 — and typically we don’t write trailing zeros. Let me confirm with calculator logic:

0.34 * 0.05 = 0.017 — yes, exactly.

So answer is 0.017

I think I’m overcomplicating. Let’s just compute:

0.34 × 0.05 = ?

0.34 × 0.05 = 0.34 × (5/100) = (0.34 × 5)/100 = 1.70 / 100 = 0.0170 → which is 0.017

Final: 0.017

But let’s keep it as 0.0170 for now? No — standard is 0.017.

Actually, 0.0170 is not wrong, but unnecessary. We’ll go with 0.017

Wait — no! 0.34 × 0.05:

Do 34 × 5 = 170

Total decimal places: 2 + 2 = 4

So 170 becomes 0.0170 — which is 0.017 when simplified, but since the problem might expect 4 decimal places, let’s write 0.0170

But in the first example, 0.35 × 0.9 = 0.315 — which has 3 decimal places, and they wrote it as 0.315, not 0.3150.

Similarly, here, 0.017 is fine.

I think I should just calculate numerically:

0.34 × 0.05 = 0.017 — yes.

Let’s move on and come back.

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Problem 3: 0.79 × 0.2

Step 1: 79 × 2 = 158
Step 2: Decimal places — 0.79 has 2, 0.2 has 1 → total 3
Step 3: 158 → 0.158

Answer: 0.158

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Problem 4: 0.99 × 0.8

Step 1: 99 × 8 = 792
Step 2: Decimal places — 0.99 has 2, 0.8 has 1 → total 3
Step 3: 792 → 0.792

Answer: 0.792

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Problem 5: 5.53 × 0.6

Step 1: 553 × 6 = 3318
Step 2: Decimal places — 5.53 has 2, 0.6 has 1 → total 3
Step 3: 3318 → 3.318

Answer: 3.318

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Problem 6: 7.49 × 0.3

Step 1: 749 × 3 = 2247
Step 2: Decimal places — 7.49 has 2, 0.3 has 1 → total 3
Step 3: 2247 → 2.247

Answer: 2.247

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Problem 7: 7.51 × 0.8

Step 1: 751 × 8 = 6008
Step 2: Decimal places — 7.51 has 2, 0.8 has 1 → total 3
Step 3: 6008 → 6.008

Answer: 6.008

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Problem 8: 4.22 × 0.2

Step 1: 422 × 2 = 844
Step 2: Decimal places — 4.22 has 2, 0.2 has 1 → total 3
Step 3: 844 → 0.844

Answer: 0.844

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Problem 9: 9.52 × 0.7

Step 1: 952 × 7 = 6664
Step 2: Decimal places — 9.52 has 2, 0.7 has 1 → total 3
Step 3: 6664 → 6.664

Answer: 6.664

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Problem 10: 537.95 × 9.2

Step 1: Ignore decimals: 53795 × 92

Let me compute 53795 × 90 and 53795 × 2

First, 53795 × 2 = 107590

53795 × 90 = 53795 × 9 × 10 = (484155) × 10 = 4,841,550

Better:

53795 × 92 = 53795 × (100 - 8) = 5379500 - 430360 = ? Or directly:

53795 × 92:

Break it:

53795 × 90 = 53795 × 9 × 10

53795 × 9:

50000×9=450000

3795×9: 3000×9=27000, 795×9=7155 → 27000+7155=34155

So 450000 + 34155 = 484155 → then ×10 = 4,841,550

Now 53795 × 2 = 107,590

Add: 4,841,550 + 107,590 = 4,949,140

So 53795 × 92 = 4,949,140

Now decimal places: 537.95 has 2, 9.2 has 1 → total 3 decimal places

So 4,949,140 → move decimal 3 places left → 4949.140

Which is 4949.14

Wait — 4,949,140 with 3 decimal places: 4949.140 → yes, 4949.14

But let me verify:

537.95 × 9.2

Approximate: 538 × 9.2 ≈ 538 × 9 = 4842, 538 × 0.2 = 107.6, total ≈ 4949.6 — close to 4949.14? Hmm, maybe I miscalculated.

Better to do:

537.95 × 9.2

First, 537.95 × 9 = 4841.55

Then 537.95 × 0.2 = 107.59

Add: 4841.55 + 107.59 = 4949.14

Yes! So 4949.14

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Problem 11: 345.961 × 3.7

Step 1: Ignore decimals: 345961 × 37

Compute 345961 × 30 = 10,378,830

345961 × 7 = 2,421,727

Add: 10,378,830 + 2,421,727 = 12,800,557

Decimal places: 345.961 has 3, 3.7 has 1 → total 4

So 12,800,557 → move decimal 4 places left → 1280.0557

Answer: 1280.0557

Verify:

345.961 × 3.7

Approx: 346 × 3.7 ≈ 346 × 3 = 1038, 346 × 0.7 = 242.2, total ≈ 1280.2 — close to 1280.0557 — good.

Exact:

345.961 × 3 = 1037.883

345.961 × 0.7 = 242.1727

Add: 1037.883 + 242.1727 = 1280.0557 — yes.

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Now, back to Problem 2: 0.34 × 0.05

We had 34 × 5 = 170

Decimal places: 2 + 2 = 4 → so 0.0170

But 0.0170 is 0.017 — however, since the first example was written as 0.315 (3 decimal places), and here we have 4 decimal places, perhaps we should write it as 0.0170? But in reality, 0.0170 is the same as 0.017.

Looking at the worksheet, in the first problem, they wrote 0.315, which is correct for 3 decimal places.

For 0.34 × 0.05, it should be 0.0170 to show 4 decimal places? But typically, we omit trailing zeros.

I think for consistency, since the problem didn't specify, we'll write the exact value without unnecessary zeros.

0.34 × 0.05 = 0.017 — and that's fine.

But let's double-check with another method:

0.34 × 0.05 = 34/100 × 5/100 = 170/10000 = 17/1000 = 0.017

Yes, so 0.017

Similarly, all others are correct.

Now, let's list all answers:

1. 0.35 × 0.9 = 0.315 (given)
2. 0.34 × 0.05 = 0.017
3. 0.79 × 0.2 = 0.158
4. 0.99 × 0.8 = 0.792
5. 5.53 × 0.6 = 3.318
6. 7.49 × 0.3 = 2.247
7. 7.51 × 0.8 = 6.008
8. 4.22 × 0.2 = 0.844
9. 9.52 × 0.7 = 6.664
10. 537.95 × 9.2 = 4949.14
11. 345.961 × 3.7 = 1280.0557

For problem 10, 537.95 × 9.2 = 4949.14 — but 4949.14 has 2 decimal places, while we expected 3? No:

537.95 has 2 decimal places, 9.2 has 1, total 3, but 4949.14 is 4949.140, which is fine — we can write it as 4949.14 since the last digit is zero.

Similarly, for problem 11, 1280.0557 has 4 decimal places, which is correct.

In problem 10, 537.95 × 9.2:

537.95 × 9.2 = let's calculate again:

537.95 × 9 = 4841.55

537.95 × 0.2 = 107.59

Sum: 4841.55 + 107.59 = 4949.14 — yes, and 4949.14 has two decimal places, but mathematically it's correct because the product ends with .14, and the third decimal would be zero.

Actually, 4949.14 is the same as 4949.140, so it's fine.

Similarly, for problem 2, 0.017 is the same as 0.0170.

So all answers are correct.

Now, to present them in order as per the worksheet.

The worksheet has:

First row:
- 0.35 × 0.9 = 0.315 (given)
- 0.34 × 0.05 = ?
- 0.79 × 0.2 = ?

Second row:
- 0.99 × 0.8 = ?
- 5.53 × 0.6 = ?
- 7.49 × 0.3 = ?

Third row:
- 7.51 × 0.8 = ?
- 4.22 × 0.2 = ?
- 9.52 × 0.7 = ?

Fourth row:
- 537.95 × 9.2 = ?
- 345.961 × 3.7 = ?

So final answers:

1. 0.34 × 0.05 = 0.017
2. 0.79 × 0.2 = 0.158
3. 0.99 × 0.8 = 0.792
4. 5.53 × 0.6 = 3.318
5. 7.49 × 0.3 = 2.247
6. 7.51 × 0.8 = 6.008
7. 4.22 × 0.2 = 0.844
8. 9.52 × 0.7 = 6.664
9. 537.95 × 9.2 = 4949.14
10. 345.961 × 3.7 = 1280.0557

For the last one, 1280.0557, it's fine.

Now, to box the final answers as per the task.

Since the user didn't specify which one to solve, but the image has multiple, I think we need to provide all.

But the instruction says "solve the problem", and there are multiple problems. Probably, we should list all solutions.

In the response, since it's a worksheet, we can provide the answers in order.

But for the Final Answer section, perhaps list them all.

Looking back at the user's request: "Solve the problem accurately." and the image has multiple problems.

I think we should provide all answers.

In the Final Answer section, we can list them.

But the format says "Final Answer: [provide only the final correct answer]"

Since there are multiple, perhaps list them.

To be safe, I'll provide all answers in order.

So, compiling:

- 0.34 × 0.05 = 0.017
- 0.79 × 0.2 = 0.158
- 0.99 × 0.8 = 0.792
- 5.53 × 0.6 = 3.318
- 7.49 × 0.3 = 2.247
- 7.51 × 0.8 = 6.008
- 4.22 × 0.2 = 0.844
- 9.52 × 0.7 = 6.664
- 537.95 × 9.2 = 4949.14
- 345.961 × 3.7 = 1280.0557

For the first one, it's given as 0.315, so we don't need to repeat.

In the worksheet, the first box is already filled with 0.315, so for the others, we fill in.

So for the response, since the user might expect the answers for the empty boxes, we can list them.

But to be precise, let's see the image description: it shows the first problem solved, and others empty.

So for the Final Answer, perhaps list the answers for the unsolved problems.

But the instruction is to solve the problem, and there are multiple.

I think it's fine to provide all.

Perhaps in the Final Answer, we can write the answers in a list.

Since the response format requires a single "Final Answer" section, and it should be the correct answer, but there are many, I'll list them.

Another way: perhaps the user wants the method, but the options are false for explain and teach, so only solve.

I think for clarity, I'll provide the answers as:

The solutions are:
0.34 × 0.05 = 0.017
0.79 × 0.2 = 0.158
0.99 × 0.8 = 0.792
5.53 × 0.6 = 3.318
7.49 × 0.3 = 2.247
7.51 × 0.8 = 6.008
4.22 × 0.2 = 0.844
9.52 × 0.7 = 6.664
537.95 × 9.2 = 4949.14
345.961 × 3.7 = 1280.0557

For the Final Answer section, since it's multiple, I'll box them as a list.

But the format says "provide only the final correct answer", so perhaps for each, but that might be messy.

I think it's acceptable to list them.

To match the worksheet, perhaps write the answers in the order of the boxes.

Let me number the boxes as per the image:

Box 1: 0.35 × 0.9 = 0.315 (given)

Box 2: 0.34 × 0.05 = ?

Box 3: 0.79 × 0.2 = ?

Box 4: 0.99 × 0.8 = ?

Box 5: 5.53 × 0.6 = ?

Box 6: 7.49 × 0.3 = ?

Box 7: 7.51 × 0.8 = ?

Box 8: 4.22 × 0.2 = ?

Box 9: 9.52 × 0.7 = ?

Box 10: 537.95 × 9.2 = ?

Box 11: 345.961 × 3.7 = ?

So for Final Answer, I'll provide the values for boxes 2 to 11.

So:

Box 2: 0.017

Box 3: 0.158

Box 4: 0.792

Box 5: 3.318

Box 6: 2.247

Box 7: 6.008

Box 8: 0.844

Box 9: 6.664

Box 10: 4949.14

Box 11: 1280.0557

Now, for box 2, is it 0.017 or 0.0170? As discussed, 0.017 is sufficient.

Similarly, for box 10, 4949.14 is fine.

For box 11, 1280.0557 is correct.

So final answer will be this list.

In the response, since the options are false for explain and teach, we only have Final Answer.

So I'll write:

Final Answer:
0.017, 0.158, 0.792, 3.318, 2.247, 6.008, 0.844, 6.664, 4949.14, 1280.0557

To make it clear, perhaps label them, but the format says "only the final correct answer", so maybe just the numbers in order.

Since the first problem is given, the next 10 are to be solved, so 10 answers.

Boxes 2 to 11 are 10 problems.

Yes.

So the answers are:

0.017, 0.158, 0.792, 3.318, 2.247, 6.008, 0.844, 6.664, 4949.14, 1280.0557

I think that's it.