GED Math Practice Test 1 | PDF | Area | Interest - Free Printable

1. (10 - 5) + 4 x 11 = 5 + 44 = 49. The answer is B) 49.

2. The original mean of the data set (12, 14, 20, 18, 14, 24, 16, 14) is (12 + 14 + 20 + 18 + 14 + 24 + 16 + 14) / 8 = 132 / 8 = 16.5. Adding 12 and 14 gives a new mean of (132 + 12 + 14) / 10 = 158 / 10 = 15.8. Adding 12 and 16 gives a new mean of (132 + 12 + 16) / 10 = 160 / 10 = 16. Adding 18 and 22 gives a new mean of (132 + 18 + 22) / 10 = 172 / 10 = 17.2. Adding 22 and 24 gives a new mean of (132 + 22 + 24) / 10 = 178 / 10 = 17.8. The highest mean is achieved by adding 22 and 24. The answer is D) 22 and 24.

3. 20% of $160 is $32. So the Kindle will cost $160 - $32 = $128. The answer is D) $128.

4. Krystal has 12 girls in her cabin. She needs to buy 12 popsicles. Each pack has 4 popsicles and costs $3.50. So she needs 12 / 4 = 3 packs. The cost is 3 x $3.50 = $10.50. The answer is A) $10.50.

5. y - 9 > 18. Add 9 to both sides: y > 27. The answer is B) y > 27.

6. Peter has $10. The cost of 7 light plate covers is 7 x $0.75 = $5.25. The cost of 4 outlet plate covers is 4 x $1.25 = $5.00. The total cost is $5.25 + $5.00 = $10.25, which is more than $10. The cost of 6 light plate covers is 6 x $0.75 = $4.50. The cost of 6 outlet plate covers is 6 x $1.25 = $7.50. The total cost is $4.50 + $7.50 = $12.00, which is more than $10. The cost of 6 light plate covers is $4.50. The cost of 4 outlet plate covers is $5.00. The total cost is $4.50 + $5.00 = $9.50, which is less than $10. The cost of 5 light plate covers is 5 x $0.75 = $3.75. The cost of 6 outlet plate covers is $7.50. The total cost is $3.75 + $7.50 = $11.25, which is more than $10. The only set Peter can afford is 6 light plate covers and 4 outlet plate covers. The answer is C) 6 light plate covers and 4 outlet plate covers.

7. The line passes through the points (0, 6) and (4, 10). The slope is (10 - 6) / (4 - 0) = 4 / 4 = 1. The answer is B) 1.