Printable math puzzles for kids - Free Printable

To solve the problem, we need to fill in the missing values in both grids step by step. Let's break it down systematically.

---

Left Grid:

The grid is structured as follows:
```
6 + ? = 14
+ + +
? + ? = ?
= = =
? + 9 = 16
13 + ? = ?
```

#### Step 1: Solve the first row.
The equation is:
\[ 6 + ? = 14 \]
Subtract 6 from both sides:
\[ ? = 14 - 6 = 8 \]

So, the first row becomes:
\[ 6 + 8 = 14 \]

#### Step 2: Solve the third row.
The equation is:
\[ ? + 9 = 16 \]
Subtract 9 from both sides:
\[ ? = 16 - 9 = 7 \]

So, the third row becomes:
\[ 7 + 9 = 16 \]

#### Step 3: Solve the fourth row.
The equation is:
\[ 13 + ? = ? \]
We don't know the rightmost value yet, but we can denote it as \( x \). So:
\[ 13 + ? = x \]

#### Step 4: Solve the second column.
The second column equations are:
\[ 8 + ? = ? \]
\[ ? + 9 = 16 \]
From the third row, we already know the bottom value in the second column is 7. So:
\[ ? + 9 = 16 \implies ? = 7 \]

Now, the second column becomes:
\[ 8 + ? = 7 \]
Subtract 8 from both sides:
\[ ? = 7 - 8 = -1 \]

So, the second column becomes:
\[ 8 + (-1) = 7 \]

#### Step 5: Solve the first column.
The first column equations are:
\[ 6 + ? = 13 \]
Subtract 6 from both sides:
\[ ? = 13 - 6 = 7 \]

So, the first column becomes:
\[ 6 + 7 = 13 \]

#### Step 6: Solve the third column.
The third column equations are:
\[ 14 + ? = x \]
\[ ? + 16 = x \]
From the second row, we know the middle value in the third column is the same as the rightmost value in the first row, which is 14. So:
\[ 14 + ? = x \]
\[ ? + 16 = x \]

Since the middle value is 14, the third column becomes:
\[ 14 + 2 = 16 \]

So, the third column becomes:
\[ 14 + 2 = 16 \]

#### Final Left Grid:
```
6 + 8 = 14
+ + +
7 + (-1) = 6
= = =
7 + 9 = 16
13 + 2 = 15
```

---

Right Grid:

The grid is structured as follows:
```
20 - 12 = ?
+ + +
? + ? = ?
= = =
25 - ? = 13
? - ? = ?
```

#### Step 1: Solve the first row.
The equation is:
\[ 20 - 12 = ? \]
Subtract:
\[ ? = 20 - 12 = 8 \]

So, the first row becomes:
\[ 20 - 12 = 8 \]

#### Step 2: Solve the third row.
The equation is:
\[ 25 - ? = 13 \]
Subtract 13 from 25:
\[ ? = 25 - 13 = 12 \]

So, the third row becomes:
\[ 25 - 12 = 13 \]

#### Step 3: Solve the second column.
The second column equations are:
\[ 12 + ? = ? \]
\[ ? + 12 = ? \]
From the third row, we already know the bottom value in the second column is 12. So:
\[ ? + 12 = 13 \implies ? = 1 \]

Now, the second column becomes:
\[ 12 + 1 = 13 \]

#### Step 4: Solve the first column.
The first column equations are:
\[ 20 + ? = ? \]
\[ ? + 25 = ? \]
From the second row, we know the middle value in the first column is the same as the leftmost value in the first row, which is 20. So:
\[ 20 + ? = 25 \]
Subtract 20 from both sides:
\[ ? = 25 - 20 = 5 \]

So, the first column becomes:
\[ 20 + 5 = 25 \]

#### Step 5: Solve the third column.
The third column equations are:
\[ 8 + ? = ? \]
\[ ? + 13 = ? \]
From the second row, we know the middle value in the third column is the same as the rightmost value in the first row, which is 8. So:
\[ 8 + ? = 13 \]
Subtract 8 from both sides:
\[ ? = 13 - 8 = 5 \]

So, the third column becomes:
\[ 8 + 5 = 13 \]

#### Final Right Grid:
```
20 - 12 = 8
+ + +
5 + 1 = 6
= = =
25 - 12 = 13
28 - 5 = 23
```

---

Final Answer:

\[
\boxed{
\begin{array}{c|c|c}
6 & + & 8 = 14 \\
\hline
7 & + & -1 = 6 \\
\hline
7 & + & 9 = 16 \\
\hline
13 & + & 2 = 15 \\
\end{array}
\quad
\begin{array}{c|c|c}
20 & - & 12 = 8 \\
\hline
5 & + & 1 = 6 \\
\hline
25 & - & 12 = 13 \\
\hline
28 & - & 5 = 23 \\
\end{array}
}
\]