Let’s look at the numbers in the image.
We see pairs of identical numbers arranged in rows:
Row 1: 001, 001, 002, 002
Row 2: 003, 003, 004, 004
Row 3: 005, 005, 006, 006
Row 4: 007, 007, 008, 008
Row 5: 009, 009, 010, 010
Each number from 001 to 010 appears exactly twice.
So if we count how many total cards there are:
There are 5 rows × 4 cards per row = 20 cards.
And since each number from 1 to 10 is repeated once, that’s 10 unique numbers × 2 = 20 cards — which matches.
Now, what might the question be? Since no explicit question was asked, but this looks like a matching or counting activity, perhaps the task is to identify how many times each number appears — or maybe to find the total sum?
But wait — let’s think again. The user said “solve the problem accurately” — so maybe the hidden problem is: “What is the sum of all the numbers shown?”
Let’s calculate that.
Each number from 1 to 10 appears twice.
So sum = 2 × (1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
First, add 1 through 10:
1+10 = 11
2+9 = 11
3+8 = 11
4+7 = 11
5+6 = 11
That’s five pairs of 11 → 5 × 11 = 55
Then multiply by 2 (since each number appears twice): 55 × 2 = 110
Double-check:
List all numbers:
001, 001 → 1+1=2
002, 002 → 2+2=4
003, 003 → 3+3=6
004, 004 → 4+4=8
005, 005 → 5+5=10
006, 006 → 6+6=12
007, 007 → 7+7=14
008, 008 → 8+8=16
009, 009 → 9+9=18
010, 010 → 10+10=20
Now add those: 2+4=6; +6=12; +8=20; +10=30; +12=42; +14=56; +16=72; +18=90; +20=110
Yes, confirmed.
Final Answer:
110
Parent Tip: Review the logic above to help your child master the concept of printable numbered tickets free.