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Classifying Quadrilaterals Color by Number - Free Printable

Classifying Quadrilaterals Color by Number

Educational worksheet: Classifying Quadrilaterals Color by Number. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Classifying Quadrilaterals Color by Number
Let’s solve this step by step.

This is a coloring puzzle based on numbers. Each section of the mandala has a number from 1 to 12. The goal is usually to color each section according to its number — for example, all sections with “1” get one color, all with “2” get another, and so on. But since no color key is given, we assume the task is simply to identify how many times each number appears in the entire design — that’s a common version of this kind of worksheet.

So let’s count how many times each number (from 1 to 12) shows up in the whole picture.

We’ll go number by number:

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Number 1:
Look carefully:
- Top left pentagon: 1
- Left side small triangle between pentagons: 1
- Bottom left pentagon: 1
- Right side small triangle near bottom: 1
→ That’s 4 times.

Wait — let me double-check by scanning again.

Actually, let’s do it more systematically. I’ll list every occurrence as I find them.

Better yet — let’s group by shape layers to avoid missing any.

The mandala has:
- Center circle: 9 → 1 time
- Inner petals (triangles): there are 6 triangles around center → numbers: 9, 4, 9, 4, 9, 4? Wait no — looking at image:

Actually, from center outward:

Center: 9 → 1

Then next ring: 6 curved petal shapes → numbers: 7, 10, 2, 3, 7, 3 → wait, let's label positions clockwise starting from top:

Top petal: 10
Right-top: 2
Right-bottom: 3
Bottom: 7
Left-bottom: 3
Left-top: 7

Wait — actually, looking again:

From center, the six large petals (between center and inner triangles):

Starting from top and going clockwise:

1. Top: 10
2. Upper right: 2
3. Lower right: 3
4. Bottom: 7
5. Lower left: 3
6. Upper left: 7

So those are: 10, 2, 3, 7, 3, 7 → so 3 appears twice, 7 appears twice, 2 once, 10 once.

Then inside those petals are 6 small triangles pointing inward:

Top triangle: 9
Upper right: 4
Lower right: 9
Bottom: 9
Lower left: 4
Upper left: 9

Wait — let’s check:

Actually, the small triangles inside the petals:

Top: 9
Upper right: 4
Lower right: 9
Bottom: 9
Lower left: 4
Upper left: 9 → that’s four 9s and two 4s? No:

Wait — counting:

Positions:

- Top triangle: 9
- Upper right triangle: 4
- Lower right triangle: 9
- Bottom triangle: 9
- Lower left triangle: 4
- Upper left triangle: 9 → yes, that’s 9,4,9,9,4,9 → so 9 appears 4 times, 4 appears 2 times.

But earlier center was also 9 → so total 9s so far: center (1) + these 4 = 5? Wait no — center is separate.

Let me restart with a full count.

I will go layer by layer, clockwise, and tally each number.

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Layer 1: Center circle → only one section: 9

Count: 9 → 1

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Layer 2: Six large petals surrounding center (the big leaf-like shapes)

Going clockwise from top:

1. Top petal: 10
2. Upper-right petal: 2
3. Lower-right petal: 3
4. Bottom petal: 7
5. Lower-left petal: 3
6. Upper-left petal: 7

So: 10, 2, 3, 7, 3, 7 → counts:
10:1, 2:1, 3:2, 7:2

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Layer 3: Six small triangles inside those petals (pointing toward center)

Clockwise from top:

1. Top triangle: 9
2. Upper-right triangle: 4
3. Lower-right triangle: 9
4. Bottom triangle: 9
5. Lower-left triangle: 4
6. Upper-left triangle: 9

So: 9,4,9,9,4,9 → counts:
9:4, 4:2

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Layer 4: Ring of 12 pentagons (outer middle ring)

Going clockwise from top:

1. Top pentagon: 8
2. Next (upper right): 3
3. Next: 2
4. Next: 12
5. Next: 5
6. Next: 10
7. Bottom pentagon: 8
8. Next (lower left): 10
9. Next: 2
10. Next: 5
11. Next: 12
12. Next (upper left): 3

Wait — let me verify positions.

Actually, looking at the image:

Starting from top pentagon and going clockwise:

1. Top: 8
2. Upper right: 3
3. Right: 2
4. Lower right: 12
5. Bottom right: 5
6. Bottom: 10
7. Bottom left: 8
8. Left: 10
9. Upper left: 2
10. Top left: 5
11. Top upper left: 12
12. Between top and top-left: 3? Wait, maybe I miscounted.

Actually, there are exactly 12 pentagons. Let me list them clearly:

Position 1 (top): 8
Position 2 (next clockwise): 3
Position 3: 2
Position 4: 12
Position 5: 5
Position 6: 10
Position 7 (bottom): 8
Position 8: 10
Position 9: 2
Position 10: 5
Position 11: 12
Position 12: 3

Yes — so numbers: 8,3,2,12,5,10,8,10,2,5,12,3

Counts:
8:2
3:2
2:2
12:2
5:2
10:2

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Layer 5: Outermost ring — 12 small segments between the pentagons and outer circle.

Going clockwise from top:

1. Top segment: 9
2. Next: 11
3. Next: 10
4. Next: 6
5. Next: 11
6. Next: 9
7. Bottom segment: 4
8. Next: 10
9. Next: 6
10. Next: 11
11. Next: 3
12. Next: 1

Wait — let’s check:

Actually, from image:

Starting at very top (above top pentagon): segment has 9

Then moving clockwise:

Next segment (between top and upper-right pentagon): 11

Next (after upper-right pentagon): 10

Next: 6

Next: 11

Next: 9

Next (below bottom pentagon): 4

Next: 10

Next: 6

Next: 11

Next: 3

Next (before top): 1

Yes — so numbers: 9,11,10,6,11,9,4,10,6,11,3,1

Counts:
9:2
11:3
10:2
6:2
4:1
3:1
1:1

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Now let’s compile ALL counts from all layers.

Start with Layer 1 (center):
9 → 1

Layer 2 (large petals):
10:1, 2:1, 3:2, 7:2

Layer 3 (small triangles):
9:4, 4:2

Layer 4 (pentagons):
8:2, 3:2, 2:2, 12:2, 5:2, 10:2

Layer 5 (outer segments):
9:2, 11:3, 10:2, 6:2, 4:1, 3:1, 1:1

Now sum all together per number:

Number 1:
Only in Layer 5: 1 → total = 1

Number 2:
Layer 2: 1
Layer 4: 2
Total = 1 + 2 = 3

Number 3:
Layer 2: 2
Layer 4: 2
Layer 5: 1
Total = 2+2+1 = 5

Number 4:
Layer 3: 2
Layer 5: 1
Total = 3

Number 5:
Layer 4: 2
Total = 2

Number 6:
Layer 5: 2
Total = 2

Number 7:
Layer 2: 2
Total = 2

Number 8:
Layer 4: 2
Total = 2

Number 9:
Layer 1: 1
Layer 3: 4
Layer 5: 2
Total = 1+4+2 = 7

Number 10:
Layer 2: 1
Layer 4: 2
Layer 5: 2
Total = 1+2+2 = 5

Number 11:
Layer 5: 3
Total = 3

Number 12:
Layer 4: 2
Total = 2

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Let me verify totals add up.

Total sections should be:

Center: 1
Large petals: 6
Small triangles: 6
Pentagons: 12
Outer segments: 12
Total = 1+6+6+12+12 = 37 sections.

Now sum our counts:

1:1
2:3 → total 4
3:5 → 9
4:3 → 12
5:2 → 14
6:2 → 16
7:2 → 18
8:2 → 20
9:7 → 27
10:5 → 32
11:3 → 35
12:2 → 37 Perfect.

So final count per number:

1: 1
2: 3
3: 5
4: 3
5: 2
6: 2
7: 2
8: 2
9: 7
10: 5
11: 3
12: 2

Final Answer:
1: 1, 2: 3, 3: 5, 4: 3, 5: 2, 6: 2, 7: 2, 8: 2, 9: 7, 10: 5, 11: 3, 12: 2
Parent Tip: Review the logic above to help your child master the concept of printable pictures of quadrilaterals.
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