Subtraction Games for Kids - Free Printable

The image depicts a game called "Salamander Shoot Out," which is a fun and educational math activity designed to practice addition skills. The goal of the game is for players to "shoot out" their opponents' numbers by rolling two dice and adding the results to find a sum that matches one of the numbers on their opponent's grid.

Game Setup:

1. There are two grids, one yellow and one blue, each containing 9 numbers.
2. Players take turns rolling two dice and adding the numbers shown on the dice.
3. If the sum matches a number on the opponent's grid, the player can "shoot out" (cross out or remove) that number.
4. The first player to shoot out all the numbers on their opponent's grid wins the game.

Numbers in the Grids:

- Yellow Grid (Player 1):
```
4 3 1
2 9 7
6 8 5
```

- Blue Grid (Player 2):
```
10 4 3
6 8 5
2 0 7
```

Possible Sums from Rolling Two Dice:

When rolling two standard six-sided dice, the possible sums range from 2 to 12:
- Minimum sum: \(1 + 1 = 2\)
- Maximum sum: \(6 + 6 = 12\)

Strategy and Explanation:

To solve this problem, we need to determine which sums are most likely to occur and how they can be used to shoot out numbers on the opponent's grid.

#### Step 1: Analyze the Numbers on Each Grid
- Yellow Grid (Player 1): Contains the numbers: 1, 2, 3, 4, 5, 6, 7, 8, 9.
- Blue Grid (Player 2): Contains the numbers: 0, 2, 3, 4, 5, 6, 7, 8, 10.

#### Step 2: Identify Common and Unique Numbers
- Common Numbers: Both grids share the numbers: 2, 3, 4, 5, 6, 7, 8.
- Unique Numbers:
- Yellow Grid: 1, 9.
- Blue Grid: 0, 10.

#### Step 3: Probability of Rolling Specific Sums
The probability of rolling each sum with two dice is as follows:
- Sum of 2: Only (1, 1) → Probability = 1/36
- Sum of 3: (1, 2), (2, 1) → Probability = 2/36
- Sum of 4: (1, 3), (2, 2), (3, 1) → Probability = 3/36
- Sum of 5: (1, 4), (2, 3), (3, 2), (4, 1) → Probability = 4/36
- Sum of 6: (1, 5), (2, 4), (3, 3), (4, 2), (5, 1) → Probability = 5/36
- Sum of 7: (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1) → Probability = 6/36
- Sum of 8: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) → Probability = 5/36
- Sum of 9: (3, 6), (4, 5), (5, 4), (6, 3) → Probability = 4/36
- Sum of 10: (4, 6), (5, 5), (6, 4) → Probability = 3/36
- Sum of 11: (5, 6), (6, 5) → Probability = 2/36
- Sum of 12: Only (6, 6) → Probability = 1/36

From this, we see that the most likely sums are 6 and 7, followed by 5 and 8.

#### Step 4: Focus on High-Probability Sums
Since the most common sums are 6 and 7, players should aim to roll these sums to maximize their chances of shooting out numbers on their opponent's grid.

#### Step 5: Targeting Unique Numbers
- Yellow Grid (Player 1): The unique numbers are 1 and 9. To shoot out these numbers, Player 2 would need to roll:
- Sum of 1: Impossible (minimum sum is 2).
- Sum of 9: Possible rolls are (3, 6), (4, 5), (5, 4), (6, 3).

- Blue Grid (Player 2): The unique numbers are 0 and 10. To shoot out these numbers, Player 1 would need to roll:
- Sum of 0: Impossible (minimum sum is 2).
- Sum of 10: Possible rolls are (4, 6), (5, 5), (6, 4).

Conclusion:

The game revolves around strategic dice rolling and addition. Players should focus on rolling high-probability sums (6 and 7) to target the common numbers on their opponent's grid. Additionally, targeting unique numbers (like 9 for Player 2 or 10 for Player 1) can provide an advantage but requires specific rolls.

Final Answer:

The key to winning is to:
1. Roll high-probability sums (6 and 7) to target common numbers.
2. Aim for unique numbers when possible, though they require specific rolls.

Thus, the solution involves understanding probabilities and focusing on efficient strategies to eliminate numbers on the opponent's grid.

$$
\boxed{\text{Focus on sums 6 and 7, and target unique numbers strategically.}}
$$