Sudoku Puzzles To Print - 10 Free PDF Printables | Printablee - Free Printable

Let's solve both Sudoku puzzles step by step. We'll start with the left puzzle, then move to the right puzzle.

---

✔ Sudoku Rules Reminder:

- Each row must contain digits 1–9 without repetition.
- Each column must contain digits 1–9 without repetition.
- Each of the nine 3×3 subgrids (boxes) must contain digits 1–9 without repetition.

We’ll solve each puzzle using logical deduction.

---

## 🔹 Left Puzzle

```
+-------+-------+-------+
| 1 2 7 | 5 3 6 | 9 |
| 9 4 | 8 2 1 | 7 5 |
| 6 5 | 4 1 | 8 |
+-------+-------+-------+
| 1 4 | 2 3 | 8 9 6 |
| 3 6 9 | 8 7 | 2 1 |
| 8 7 | 6 9 5 | 4 |
+-------+-------+-------+
| 2 | 9 7 4 | 3 |
| 4 3 | 2 6 9 | 7 |
| 7 6 | 3 1 | 5 2 |
+-------+-------+-------+
```

We will fill in the blanks one by one.

---

Step 1: Fill in easy cells

Let’s label rows R1 to R9 and columns C1 to C9.

#### Look at R1C7:
R1 has: 1,2,7,5,3,6,?,9 → missing: 4,8
C7 has: ?,1,?,8,2,4,3,?,5 → values present: 1,2,3,4,5,8 → missing: 6,7,9
Box (1,3): top-right box (R1–R3, C7–C9)
Current:
- R1C7: ?
- R1C8: 9
- R1C9: ?
- R2C7: 7
- R2C8: 5
- R2C9: ?
- R3C7: ?
- R3C8: 8
- R3C9: ?

So far: 7,5,8,9 → missing: 1,2,3,4,6

But R1 needs 4 or 8 in C7 → but 8 is already in box → so R1C7 = 4

✔ R1C7 = 4

Now R1: 1,2,7,5,3,6,4,?,9 → missing: 8 → R1C8 = 8? But R1C8 is already 9 → wait!

Wait! R1: C1=1, C2=2, C3=7, C4=5, C5=3, C6=6, C7=?, C8=9, C9=?

So we have: 1,2,7,5,3,6,?,9,?

Missing: 4,8

C7: values: R1C7=?, R2C7=7, R3C7=?, R4C7=8, R5C7=2, R6C7=4, R7C7=3, R8C7=?, R9C7=5

So C7: 7,8,2,4,3,5 → missing: 1,6,9

So R1C7 can be 4 or 8 from row, but 8 is in C7 → R4C7=8 → so R1C7 ≠8 → only possible: 4

But 4 is in C7 at R6 → R6C7=4 → so 4 is already in C7 → so R1C7 cannot be 4

Wait! Contradiction?

Let’s list C7:

- R1C7: ?
- R2C7: 7
- R3C7: ?
- R4C7: 8
- R5C7: 2
- R6C7: 4
- R7C7: 3
- R8C7: ?
- R9C7: 5

So values in C7: 7,8,2,4,3,5 → missing: 1,6,9

So R1C7 ∈ {1,6,9}

But R1 has: 1,2,7,5,3,6,?,9,? → missing: 4,8

So R1C7 must be 4 or 8 → but neither 4 nor 8 are in missing for C7 → contradiction?

Wait! That means R1C7 must be in both:

- Row 1 missing: 4,8
- Column 7 missing: 1,6,9

No overlap → impossible?

That suggests an error in our assumption.

Wait — let's recheck R1:

R1: C1=1, C2=2, C3=7, C4=5, C5=3, C6=6, C7=?, C8=9, C9=?

So numbers used: 1,2,3,5,6,7,9 → missing: 4,8

So R1C7 and R1C9 must be 4 and 8 in some order.

Now C7: values:

- R1C7: ?
- R2C7: 7
- R3C7: ?
- R4C7: 8
- R5C7: 2
- R6C7: 4
- R7C7: 3
- R8C7: ?
- R9C7: 5

So used: 7,8,2,4,3,5 → missing: 1,6,9

So R1C7 ∈ {1,6,9} → but R1 requires 4 or 8 → no intersection → impossible?

This implies that the puzzle might be invalid? Or I made a mistake.

Wait — maybe I misread the grid.

Let me write the left puzzle clearly:

```
Row 1: 1 2 7 | 5 3 6 | ? 9 ?
Row 2: 9 4 ? | 8 2 1 | 7 5 ?
Row 3: 6 ? 5 | 4 ? 1 | ? ? 8
Row 4: 1 ? 4 | 2 3 ? | 8 9 6
Row 5: 3 6 9 | 8 ? 7 | 2 1 ?
Row 6: ? 8 7 | 6 9 5 | 4 ? ?
Row 7: ? 2 ? | 9 7 4 | 3 ? ?
Row 8: 4 3 ? | 2 6 9 | ? ? 7
Row 9: 7 ? 6 | 3 1 ? | 5 2 ?
```

Wait — in Row 1, C7 is blank, C8 is 9, C9 is blank.

So R1: 1,2,7,5,3,6,?,9,? → missing: 4,8

So R1C7 and R1C9 = 4 and 8

Now check C7:

- R1C7: ?
- R2C7: 7
- R3C7: ?
- R4C7: 8
- R5C7: 2
- R6C7: 4
- R7C7: 3
- R8C7: ?
- R9C7: 5

Used: 7,8,2,4,3,5 → missing: 1,6,9

So R1C7 ∈ {1,6,9} → but R1 needs 4 or 8 → no overlap → impossible?

But this can't be. So either I misread the puzzle or there's a typo.

Wait — look at R4C7: is it 8?

Yes: Row 4: 1 ? 4 | 2 3 ? | 8 9 6 → so C7 is 8

R6C7: 4 → yes

R5C7: 2 → yes

So C7 has: 8,4,2,3,5,7 → so 1,6,9 missing

R1C7 must be 4 or 8 → but 8 and 4 are already in C7 → so R1C7 cannot be 4 or 8 → contradiction

Thus, no valid number for R1C7 → the puzzle is invalid?

But that can't be. Let's double-check the original image.

Looking back:

Left puzzle:

Row 1: 1 2 7 | 5 3 6 | ? 9 ?

Row 2: 9 4 ? | 8 2 1 | 7 5 ?

Row 3: 6 ? 5 | 4 ? 1 | ? ? 8

Row 4: 1 ? 4 | 2 3 ? | 8 9 6

Row 5: 3 6 9 | 8 ? 7 | 2 1 ?

Row 6: ? 8 7 | 6 9 5 | 4 ? ?

Row 7: ? 2 ? | 9 7 4 | 3 ? ?

Row 8: 4 3 ? | 2 6 9 | ? ? 7

Row 9: 7 ? 6 | 3 1 ? | 5 2 ?

Now let's look at R1C9: it's blank.

So R1: missing 4 and 8 → R1C7 and R1C9 = 4 and 8

But C7 has 8 (R4), 4 (R6), so both 4 and 8 are in C7 → so R1C7 cannot be 4 or 8 → impossible

Therefore, the left puzzle is unsolvable as given unless there's a typo.

Wait — could it be that R1C7 is not in C7? No, it is.

Unless the grid is misread.

Wait — perhaps the blank in R1C7 is not actually blank? Let's count.

In the image, the first row is:

| 1 | 2 | 7 | 5 | 3 | 6 | | 9 | |

So C7 is blank, C8=9, C9=blank

So yes, two blanks in R1.

But C7 has 8 (R4), 4 (R6), 2 (R5), 3 (R7), 5 (R9), 7 (R2) → so 1,6,9 missing

So R1C7 must be one of 1,6,9

But R1 needs 4 or 8 → no common value → contradiction

So this puzzle has no solution due to inconsistency.

But maybe I made a mistake.

Wait — could R1C7 be 8? But R4C7=8 → same column → no

Could R1C7 be 4? R6C7=4 → same column → no

So R1C7 cannot be 4 or 8 → but R1 needs those two numbers → so R1C7 and R1C9 must be 4 and 8, but neither can go in C7 → so R1C7 cannot be 4 or 8 → contradiction

Thus, the left puzzle is invalid.

Let’s try the right puzzle.

---

## 🔹 Right Puzzle

```
+-------+-------+-------+
| 5 3 2 | 9 8 | 7 6 |
| 1 9 | 5 6 2 | 8 7 |
| 8 7 | 6 3 | 1 5 4 |
+-------+-------+-------+
| 1 9 6 | 3 8 | 2 |
| 6 4 | 7 2 5 | 9 1 |
| 7 6 | 2 3 | 5 4 |
+-------+-------+-------+
| 8 5 | 7 1 | 6 9 |
| 9 3 | 4 7 6 | 2 |
| 2 7 4 | 1 | 9 3 5 |
+-------+-------+-------+
```

Let’s write it clearly:

```
Row 1: 5 3 2 | 9 8 ? | 7 ? 6
Row 2: ? 1 9 | 5 6 2 | 8 7 ?
Row 3: 8 ? 7 | 6 3 ? | 1 5 4
Row 4: 1 9 6 | 3 ? 8 | ? 2 ?
Row 5: 6 4 ? | 7 2 5 | ? 9 1
Row 6: 7 6 ? | 2 ? 3 | 5 4 ?
Row 7: ? 8 5 | ? 7 1 | ? 6 9
Row 8: 9 ? 3 | 4 7 6 | ? 2 ?
Row 9: 2 7 4 | ? 1 ? | 9 3 5
```

Let’s solve this one.

---

Step 1: Find easy cells

Look at R1C6 (row 1, col 6)

R1: 5,3,2,9,8,?,7,?,6 → missing: 1,4

So R1C6 ∈ {1,4}

C6: R1C6=?, R2C6=2, R3C6=?, R4C6=8, R5C6=5, R6C6=3, R7C6=1, R8C6=6, R9C6=?

So C6: 2,8,5,3,1,6 → missing: 4,7,9

So R1C6 ∈ {1,4} ∩ {4,7,9} → only 4 possible

✔ R1C6 = 4

Now R1: 5,3,2,9,8,4,7,?,6 → missing: 1

So R1C8 = 1

✔ R1C8 = 1

Now R1 is complete: 5,3,2,9,8,4,7,1,6

Update:

```
Row 1: 5 3 2 | 9 8 4 | 7 1 6
```

Now look at R2C1

R2: ?,1,9 | 5,6,2 | 8,7,?

Missing: 3,4

C1: R1C1=5, R2C1=?, R3C1=8, R4C1=1, R5C1=6, R6C1=7, R7C1=?, R8C1=9, R9C1=2

So C1: 5,8,1,6,7,9,2 → missing: 3,4

So R2C1 ∈ {3,4} → good

Now R2: missing 3,4 → so R2C1 and R2C9 = 3 and 4

C9: R1C9=6, R2C9=?, R3C9=4, R4C9=?, R5C9=1, R6C9=?, R7C9=9, R8C9=?, R9C9=5

So C9: 6,4,1,9,5 → missing: 2,3,7,8

So R2C9 ∈ {2,3,7,8} → but R2 needs 3 or 4 → so R2C9 = 3 (only common)

✔ R2C9 = 3 → then R2C1 = 4

✔ R2C1 = 4

Now R2: 4,1,9 | 5,6,2 | 8,7,3

Update:

```
Row 2: 4 1 9 | 5 6 2 | 8 7 3
```

Now R3C2

R3: 8,?,7 | 6,3,? | 1,5,4

Missing: 2,9

C2: R1C2=3, R2C2=1, R3C2=?, R4C2=9, R5C2=4, R6C2=6, R7C2=8, R8C2=?, R9C2=7

So C2: 3,1,9,4,6,8,7 → missing: 2,5

So R3C2 ∈ {2,9} ∩ {2,5} → only 2 possible

✔ R3C2 = 2 → then R3C6 = 9

R3: 8,2,7 | 6,3,9 | 1,5,4

Now update:

```
Row 3: 8 2 7 | 6 3 9 | 1 5 4
```

Now R4C7 and R4C9

R4: 1,9,6 | 3,?,8 | ?,2,?

Missing: 4,5,7

C7: R1C7=7, R2C7=8, R3C7=1, R4C7=?, R5C7=?, R6C7=5, R7C7=?, R8C7=?, R9C7=9

So C7: 7,8,1,5,9 → missing: 2,3,4,6

R4C7 ∈ {4,5,7} ∩ {2,3,4,6} → only 4 possible

✔ R4C7 = 4

Then R4: 1,9,6 | 3,?,8 | 4,2,?

Now missing: 5,7

C5: R1C5=8, R2C5=6, R3C5=3, R4C5=?, R5C5=2, R6C5=?, R7C5=7, R8C5=7 → wait, R8C5=7, R7C5=7 → conflict?

Wait:

R7: ?,8,5 | ?,7,1 | ?,6,9 → so R7C5=7

R8: 9,?,3 | 4,7,6 | ?,2,? → R8C5=7

So C5: R1C5=8, R2C5=6, R3C5=3, R4C5=?, R5C5=2, R6C5=?, R7C5=7, R8C5=7 → duplicate 7 in C5 → impossible?

Wait — R7C5=7 and R8C5=7 → same column → invalid

But in the original image:

Row 7: ? 8 5 | ? 7 1 | ? 6 9 → C5=7

Row 8: 9 ? 3 | 4 7 6 | ? 2 ? → C5=7

Yes, both have 7 in C5 → duplicate in column 5 → so the puzzle is invalid?

Wait — is that correct?

Let’s check the original image again.

Right puzzle:

Row 7: ? 8 5 | ? 7 1 | ? 6 9 → C5=7

Row 8: 9 ? 3 | 4 7 6 | ? 2 ? → C5=7

Yes — both have 7 in C5 → so column 5 has two 7s → invalid puzzle

So both puzzles appear to have errors.

But let’s verify carefully.

Check right puzzle C5:

- R1C5: 8
- R2C5: 6
- R3C5: 3
- R4C5: ?
- R5C5: 2
- R6C5: ?
- R7C5: 7
- R8C5: 7 ← same as R7C5
- R9C5: 1

So R7C5 and R8C5 both 7 → duplicate in column 5 → invalid

Similarly, in the left puzzle, we had a contradiction.

So both puzzles have logical inconsistencies.

But perhaps I misread.

Wait — let's recheck the right puzzle image.

Original:

```
5 3 2 9 8 7 6
1 9 5 6 2 8 7
8 7 6 3 1 5 4
1 9 6 3 8 2
6 4 7 2 5 9 1
7 6 2 3 5 4
8 5 7 1 6 9
9 3 4 7 6 2
2 7 4 1 9 3 5
```

Now, R7: ? 8 5 | ? 7 1 | ? 6 9 → so C5=7

R8: 9 ? 3 | 4 7 6 | ? 2 ? → C5=7

Yes, both have 7 in C5 → invalid

Similarly, in left puzzle, R1C7 and R1C9 need 4 and 8, but C7 already has 4 and 8 → so no place for them.

So both puzzles are invalid.

---

✔ Final Answer:

After careful analysis:

- The left Sudoku puzzle has a contradiction in Row 1 and Column 7: R1 needs 4 and 8, but both are already in C7, making it impossible to fill.
- The right Sudoku puzzle has a duplicate 7 in Column 5 (R7C5 and R8C5), violating Sudoku rules.

✘ Conclusion:

Both puzzles are unsolvable due to inherent contradictions.

There may be typos in the provided grids. Please double-check the original puzzle for accuracy.