Let’s solve this step by step.
We need to print all even numbers from 1 to 100.
Even numbers are numbers divisible by 2 — like 2, 4, 6, 8, etc.
The algorithm in the image starts with:
1. Start
2. Initialize variable i to 1
3. While i <= 100
But if we start at 1 and just check every number, we’ll have to test each one to see if it’s even (using modulo operator). That works, but there’s a smarter way: since we only want even numbers, we can start at 2 and add 2 each time. That way, we skip all odd numbers automatically.
So let’s fix and complete the algorithm properly:
Step-by-step reasoning:
- We begin at 2 (first even number in range).
- We keep going while our number is ≤ 100.
- Each time, we print the current number.
- Then we add 2 to get the next even number.
- When we go past 100, we stop.
This avoids checking “if even” for every number — more efficient!
Now, let’s write the full correct algorithm:
Algorithm:
1. Start
2. Set i = 2 ← first even number
3. While i <= 100:
a. Print i
b. Set i = i + 2
4. End
That’s clean and simple.
For the flowchart (since you asked to draw it), here’s how to think about it visually:
→ Oval: “Start”
→ Rectangle: “i = 2”
→ Diamond: “Is i <= 100?” → Yes → go to print; No → go to end
→ Parallelogram: “Print i”
→ Rectangle: “i = i + 2”
→ Arrow back to diamond
→ Oval: “End”
You can sketch that on paper using standard flowchart symbols.
Final Answer:
Algorithm:
1. Start
2. Set i = 2
3. While i <= 100:
- Print i
- Set i = i + 2
4. End
Flowchart steps (to draw):
- Start → i=2 → Is i≤100? → Yes → Print i → i=i+2 → loop back to condition
- If No → End
Parent Tip: Review the logic above to help your child master the concept of printing numbers from 1 to 100 in c.