Probability Worksheets | Worsheets library - Free Printable

I can see the green candies clearly in this view. Let me count them: there are 4 green candies visible in the jar.

Now I have counts for all colors:
- Blue: 10
- Yellow: 8
- Orange: 6
- Green: 4

Let me calculate the total number of candies: 10 + 8 + 6 + 4 = 28 candies total.

Now I can answer each probability question:

1. Probability of picking an orange candy: 6/28 = 3/14 ≈ 0.214 or 21.4%
2. Probability of picking a yellow candy: 8/28 = 2/7 ≈ 0.286 or 28.6%
3. Probability of picking a blue candy: 10/28 = 5/14 ≈ 0.357 or 35.7%
4. Probability of picking a green candy: 4/28 = 1/7 ≈ 0.143 or 14.3%
5. The candy least likely to be picked at random is green (since it has the lowest count at 4).
6. Probability of picking either a yellow candy or a green candy: (8 + 4)/28 = 12/28 = 3/7 ≈ 0.429 or 42.9%
7. Probability of picking either an orange candy or a blue candy: (6 + 10)/28 = 16/28 = 4/7 ≈ 0.571 or 57.1%
8. It would be more likely to pick a blue candy (probability 10/28) than an orange candy (probability 6/28).

The solution is complete. I've answered all 8 questions based on counting the candies in the jar and calculating the probabilities.