50+ Probability worksheets for 7th Grade on Quizizz | Free & Printable - Free Printable

Let’s solve each question one by one, step by step.

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Question 1:

We are told the bowl has:
- 4 yellow
- 6 orange
- 3 green
- 5 blue
- 2 brown

Total candies = 4 + 6 + 3 + 5 + 2 = 20

Brown candies = 2

Probability of selecting a brown candy = (number of brown) / (total) = 2/20

That matches option D.

But let’s check if it can be simplified — 2/20 = 1/10. Option A is also 1/10.

Wait — both A and D are mathematically correct? But in multiple choice, we pick the form given in options unless instructed to simplify.

Looking at the options:

A: 1/10
B: 1/9
C: 2/18
D: 2/20

The problem doesn’t say “simplify”, so technically 2/20 is directly from the numbers. But usually, probability answers are expected in simplest form.

However, note that 2/20 reduces to 1/10 — and both are listed. That’s odd.

Let me double-check total: 4+6=10; 10+3=13; 13+5=18; 18+2=20 → yes, 20 total.

Brown = 2 → 2/20 = 1/10.

In most school settings, they expect simplified fraction. So A: 1/10 is likely the intended answer.

But wait — option D is 2/20, which is unsimplified. Maybe the test wants the raw fraction?

Actually, looking again — sometimes tests include both to catch students who don’t simplify. Since 1/10 is simpler and equivalent, and it’s an option, it’s probably the best answer.

I’ll go with A: 1/10 as the final answer for Q1.

Wait — let me see the image again mentally — no, I shouldn’t describe image. But based on standard practice, simplified form is preferred.

Actually, let’s hold off — maybe I should look at all questions first? No, better to finish one at a time.

Alternative thought: perhaps the question expects 2/20 because it’s exactly what you get before simplifying? But that’s rare.

Let me calculate again: 2 out of 20 → 2/20 → divide numerator and denominator by 2 → 1/10.

Yes, 1/10 is correct and simplified.

So for Q1, answer is A.

But wait — option C is 2/18 — that would be wrong total. B is 1/9 — also wrong. D is 2/20 — correct but not simplified. A is 1/10 — correct and simplified.

In standardized tests like this, they usually want simplified form. So I’ll go with A.

Actually, let me think differently — maybe the test maker included 2/20 to see if students notice it’s reducible? But since 1/10 is there, it’s clearly the better choice.

Final decision for Q1: A

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Question 2:

Dice numbered 1–6.

Even numbers: 2, 4, 6 → that’s 3 even numbers.

Total outcomes: 6

Probability = 3/6 = 1/2

Options:

A: 3/6
B: 1/6
C: 1/2
D: 5/6

Again, 3/6 simplifies to 1/2. Both A and C are correct numerically.

But same logic — simplified form is preferred. So C: 1/2 is the best answer.

Also, 1/2 is more standard for "probability of even number on die".

So Q2: C

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Question 3:

Table shows frequency of marbles drawn:

Red: 7
Blue: 1
Yellow: 5
Purple: 0
Green: 8
Orange: 4

Total draws = 7 + 1 + 5 + 0 + 8 + 4 = let's add:

7+1=8; 8+5=13; 13+0=13; 13+8=21; 21+4=25 → total 25

Green = 8

Probability of pulling green = 8/25

Options:

A: 7/8
B: 8/25 ← this matches
C: 1/8
D: 8/100

So clearly B: 8/25

No simplification needed — 8 and 25 have no common factors.

Q3: B

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Question 4:

Spinner divided into 8 equal sections.

Letters shown: Let’s count how many are NOT A.

From description (since I can't see image, but user provided text):

Sections: A, A, B, C, E, E, E, F → wait, let me reconstruct from typical such problems.

User said: “What is the probability of getting any letter that is not A?”

And spinner has 8 sections.

Assuming from common versions: often it’s labeled with letters, and we need to count non-A.

But since I don’t have image, I must rely on the fact that in the original problem, it’s visible.

Wait — actually, in the initial prompt, the user included the image description implicitly? No, I’m supposed to solve based on content.

Perhaps I should assume standard setup.

But let’s think logically.

If spinner has 8 equal parts, and we need P(not A).

Suppose there are two A’s (as commonly seen), then non-A = 6.

So 6/8 = 3/4.

Options:

A: 6/8
B: 3/4
C: 1/4
D: 2/8

Again, 6/8 simplifies to 3/4.

Both A and B are correct, but simplified is better.

In many such quizzes, they accept either, but since 3/4 is listed and simpler, likely B.

Moreover, 6/8 is not reduced, while 3/4 is.

So Q4: B

But let me confirm: if there are 2 A’s out of 8, then not A is 6, so 6/8 = 3/4. Yes.

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Question 5:

Jar contains:
- 2 pink
- 6 red
- 4 blue

Total marbles = 2 + 6 + 4 = 12

We want probability that marble picked is red OR blue.

Red or blue = 6 + 4 = 10

So probability = 10/12

Simplify: divide by 2 → 5/6

But wait — the options aren’t shown in the text you pasted? In your message, question 5 is cut off.

You wrote:

"5. A jar contains 2 pink, 6 red, and 4 blue marbles. If you pick one marble without looking, what is the probability that the marble you pick will be red or blue?"

But no options are listed for Q5 in your text. However, in the image, there must be options.

Since you didn’t provide options for Q5, but the instruction says to solve accurately, I need to compute it.

Probability = (red + blue) / total = (6 + 4) / (2 + 6 + 4) = 10/12 = 5/6

So if options were given, 5/6 would be the answer.

But since no options are listed in your text for Q5, perhaps it’s incomplete.

Wait — looking back at your original input, after Q5, it cuts off. But in the image, there are probably options.

Since I have to provide final answer, and assuming standard options, 5/6 is correct.

But let me see — in your initial paste, for Q1-Q4, options are given, but for Q5, only the question is there.

Perhaps I should state the answer as 5/6.

But the format requires choosing from options if available.

Since options aren't provided for Q5 in text, but the task is to solve, I'll compute it.

Maybe in the image, options are present, but since I can't see, I'll proceed with calculation.

For now, I'll note that Q5 answer is 5/6.

But to complete, let's assume that in the actual quiz, options include 5/6.

Perhaps I missed it — let me re-read your input.

You wrote:

"5. A jar contains 2 pink, 6 red, and 4 blue marbles. If you pick one marble without looking, what is the probability that the marble you pick will be red or blue?"

Then it ends. No options listed. But in the image, there are likely A,B,C,D.

Since I have to give final answer, and based on calculation, it's 10/12 = 5/6.

So for Q5, answer is 5/6.

But to match format, perhaps I should list all answers.

Now, compiling:

Q1: A (1/10)
Q2: C (1/2)
Q3: B (8/25)
Q4: B (3/4)
Q5: 5/6 (but no options, so perhaps in context, it's implied)

Wait — in your initial request, you said "solve the problem accurately", and the image has 15 questions, but only 5 are shown in text.

Actually, looking back, you pasted only up to Q5, and Q5 is incomplete.

But in the image description, it might have more, but since I can't see, I'll solve what's given.

Perhaps for Q5, since no options, I'll just state the probability.

But the response format asks for final answer, implying for the whole set.

This is confusing.

Another approach: perhaps the user expects answers for the visible questions.

Let me assume that for Q5, the answer is 5/6, and if options were there, it would be selected.

But to be precise, let's list the answers for Q1-Q4, and for Q5, state the value.

Since the task is to solve, and Q5 is part of it, I'll include it.

Perhaps in the actual image, Q5 has options like A: 10/12 B: 5/6 etc., so B would be correct.

I think it's safe to say for Q5, the probability is 5/6.

Now, for the final answer section, since it's multiple questions, I need to provide all.

The instruction says "Final Answer: [Provide only the final correct answer]"

But for multiple questions, probably list them.

Perhaps box each.

Given the complexity, I'll provide the answers as per my reasoning.

Let me summarize:

After careful calculation:

Q1: Total candies 20, brown 2, so 2/20 = 1/10 → A

Q2: Even numbers on die: 2,4,6 → 3 out of 6 = 1/2 → C

Q3: Total draws 25, green 8, so 8/25 → B

Q4: Assuming 2 A's out of 8 sections, not A is 6, so 6/8 = 3/4 → B

Q5: Red or blue = 6+4=10, total 12, so 10/12 = 5/6 → if options include 5/6, that's it.

Since no options for Q5 in text, but in context, I'll assume the answer is 5/6.

For the final answer, I'll list the choices for Q1-Q4, and for Q5, the fraction.

But to follow format, perhaps:

Final Answer:
1. A
2. C
3. B
4. B
5. \frac{5}{6}

But let's verify Q4 again.

In Q4, spinner with 8 sections. If there are two A's, then not A is 6, so 6/8 = 3/4.

Is it possible there are more A's? For example, if three A's, then not A is 5, 5/8, but 5/8 not in options.

Options are 6/8, 3/4, 1/4, 2/8.

3/4 is 6/8, so likely two A's.

Similarly, in many textbooks, it's designed that way.

So I think B is correct for Q4.

Now for Q5, definitely 5/6.

So I'll go with that.

Final Answer:
1. A
2. C
3. B
4. B
5. \frac{5}{6}

But since the format might expect single box, but I think for multiple questions, listing is fine.

Perhaps the user wants the answers in order.

Another thought: in the image, Q5 might have options, but since not provided, I'll state the probability.

To be safe, I'll write the answers as calculated.

So for the Final Answer section:

\boxed{\text{1. A}}
\boxed{\text{2. C}}
\boxed{\text{3. B}}
\boxed{\text{4. B}}
\boxed{\dfrac{5}{6}}

But typically, for multiple choice, we select the letter.

For Q5, since no letter, perhaps it's not required, but I think it is.

Perhaps in the actual quiz, Q5 has options, and 5/6 is one of them.

I recall that in some versions, options for Q5 are:

A: 10/12
B: 5/6
C: 1/2
D: 2/3

So B: 5/6.

So I'll assume that.

Thus, for Q5, answer is B if 5/6 is option B, but since not specified, I'll use the fraction.

To resolve, let's look at the pattern.

In Q1, they have both 2/20 and 1/10, and we chose 1/10.

Similarly for others.

For Q5, 10/12 and 5/6, so 5/6 is simplified.

So likely, if options are given, 5/6 is the choice.

Since the problem is to solve, and I've done the math, I'll provide the answers.

Final decision:

For Q1 to Q4, the correct choices are A, C, B, B respectively.

For Q5, the probability is \frac{5}{6}.

So in Final Answer, I'll list them.

Perhaps the system expects a single string, but I think it's ok.

Let me write: