Probability Worksheets | Free - CommonCoreSheets - Free Printable
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Step-by-step solution for: Probability Worksheets | Free - CommonCoreSheets
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Show Answer Key & Explanations
Step-by-step solution for: Probability Worksheets | Free - CommonCoreSheets
Let's solve each of the 15 probability problems step by step and explain the reasoning behind each solution.
---
- A fair coin has two outcomes: Head (H) or Tail (T).
- Total possible outcomes = 2
- Favorable outcome for Head = 1
$$
P(\text{Head}) = \frac{1}{2}
$$
✔ Answer: $ \frac{1}{2} $
---
- A standard deck has 52 cards.
- Face cards are Jack, Queen, King → 3 per suit.
- 4 suits → $ 3 \times 4 = 12 $ face cards.
$$
P(\text{Face card}) = \frac{12}{52} = \frac{3}{13}
$$
✔ Answer: $ \frac{3}{13} $
---
- Dice faces: 1, 2, 3, 4, 5, 6
- Prime numbers among them: 2, 3, 5 → 3 primes
$$
P(\text{Prime}) = \frac{3}{6} = \frac{1}{2}
$$
✔ Answer: $ \frac{1}{2} $
---
- Numbers less than 5: 1, 2, 3, 4 → 4 outcomes
$$
P(\text{< 5}) = \frac{4}{6} = \frac{2}{3}
$$
✔ Answer: $ \frac{2}{3} $
---
- Only one 2 of spades in a deck.
$$
P(2\ \text{of spades}) = \frac{1}{52}
$$
✔ Answer: $ \frac{1}{52} $
---
- Hits boundary = 5 times
- Total balls = 30
- Did not hit boundary = $ 30 - 5 = 25 $
$$
P(\text{No boundary}) = \frac{25}{30} = \frac{5}{6}
$$
✔ Answer: $ \frac{5}{6} $
---
- Total balls = $ 5 + 4 + 3 = 12 $
- Black balls = 4
$$
P(\text{Black}) = \frac{4}{12} = \frac{1}{3}
$$
✔ Answer: $ \frac{1}{3} $
---
- Experimental probability based on frequency:
$$
P(\text{Head}) = \frac{\text{Number of heads}}{\text{Total tosses}} = \frac{245}{500} = \frac{49}{100}
$$
✔ Answer: $ \frac{49}{100} $ or 0.49
---
- Correct forecasts = 175
- Not correct = $ 250 - 175 = 75 $
$$
P(\text{Not correct}) = \frac{75}{250} = \frac{3}{10}
$$
✔ Answer: $ \frac{3}{10} $
---
- Total students = 36
- Boys = 20 → Girls = $ 36 - 20 = 16 $
$$
P(\text{Girl}) = \frac{16}{36} = \frac{4}{9}
$$
✔ Answer: $ \frac{4}{9} $
---
- Numbers between 5 and 15: 6, 7, 8, 9, 10, 11, 12, 13, 14 → Total = 9 numbers
- Odd numbers: 7, 9, 11, 13 → 4 odds
$$
P(\text{Odd}) = \frac{4}{9}
$$
✔ Answer: $ \frac{4}{9} $
> Note: "Between 5 and 15" usually means excluding 5 and 15.
---
- Families with 2 children = 814
- Total families = 1500
- Families with 1 child = $ 1500 - 814 = 686 $
$$
P(\text{1 child}) = \frac{686}{1500} = \frac{343}{750}
$$
✔ Answer: $ \frac{343}{750} $
---
- Word: I, N, D, I, A → 5 letters
- Letter 'I' appears twice
$$
P(\text{I}) = \frac{2}{5}
$$
✔ Answer: $ \frac{2}{5} $
---
- Rotten = 19
- Fresh = $ 56 - 19 = 37 $
$$
P(\text{Fresh}) = \frac{37}{56}
$$
✔ Answer: $ \frac{37}{56} $
---
- A standard die has faces: 1 to 6
- No face has 7 → impossible event
$$
P(7) = 0
$$
✔ Answer: $ 0 $
---
| Question | Answer |
|--------|--------|
| 1 | $ \frac{1}{2} $ |
| 2 | $ \frac{3}{13} $ |
| 3 | $ \frac{1}{2} $ |
| 4 | $ \frac{2}{3} $ |
| 5 | $ \frac{1}{52} $ |
| 6 | $ \frac{5}{6} $ |
| 7 | $ \frac{1}{3} $ |
| 8 | $ \frac{49}{100} $ |
| 9 | $ \frac{3}{10} $ |
| 10 | $ \frac{4}{9} $ |
| 11 | $ \frac{4}{9} $ |
| 12 | $ \frac{343}{750} $ |
| 13 | $ \frac{2}{5} $ |
| 14 | $ \frac{37}{56} $ |
| 15 | $ 0 $ |
Let me know if you'd like these explained further or visualized!
---
1. A coin is tossed once, find the probability of getting 'Head'.
- A fair coin has two outcomes: Head (H) or Tail (T).
- Total possible outcomes = 2
- Favorable outcome for Head = 1
$$
P(\text{Head}) = \frac{1}{2}
$$
✔ Answer: $ \frac{1}{2} $
---
2. In a pack of 52 cards, what is the probability of getting a face card?
- A standard deck has 52 cards.
- Face cards are Jack, Queen, King → 3 per suit.
- 4 suits → $ 3 \times 4 = 12 $ face cards.
$$
P(\text{Face card}) = \frac{12}{52} = \frac{3}{13}
$$
✔ Answer: $ \frac{3}{13} $
---
3. A dice is tossed once; find the probability of getting a 'prime number'.
- Dice faces: 1, 2, 3, 4, 5, 6
- Prime numbers among them: 2, 3, 5 → 3 primes
$$
P(\text{Prime}) = \frac{3}{6} = \frac{1}{2}
$$
✔ Answer: $ \frac{1}{2} $
---
4. A dice is tossed once; find the probability of getting a number less than 5.
- Numbers less than 5: 1, 2, 3, 4 → 4 outcomes
$$
P(\text{< 5}) = \frac{4}{6} = \frac{2}{3}
$$
✔ Answer: $ \frac{2}{3} $
---
5. In a pack of 52 cards, find the probability of getting 2 of spades.
- Only one 2 of spades in a deck.
$$
P(2\ \text{of spades}) = \frac{1}{52}
$$
✔ Answer: $ \frac{1}{52} $
---
6. In a cricket match, a batsman hits a boundary of 5 times out of 30 balls he plays. Find the probability that he did not hit a boundary.
- Hits boundary = 5 times
- Total balls = 30
- Did not hit boundary = $ 30 - 5 = 25 $
$$
P(\text{No boundary}) = \frac{25}{30} = \frac{5}{6}
$$
✔ Answer: $ \frac{5}{6} $
---
7. In a bag there are 5 white, 4 black, 3 red balls. One ball is picked up randomly. What is the probability of getting a black ball?
- Total balls = $ 5 + 4 + 3 = 12 $
- Black balls = 4
$$
P(\text{Black}) = \frac{4}{12} = \frac{1}{3}
$$
✔ Answer: $ \frac{1}{3} $
---
8. A coin is tossed 500 times with following frequencies: Head - 245, Tail - 255. What is the probability of getting head?
- Experimental probability based on frequency:
$$
P(\text{Head}) = \frac{\text{Number of heads}}{\text{Total tosses}} = \frac{245}{500} = \frac{49}{100}
$$
✔ Answer: $ \frac{49}{100} $ or 0.49
---
9. In 250 consecutive days weather forecasts were correct 175 times. Find the probability of getting 'not correct' forecast.
- Correct forecasts = 175
- Not correct = $ 250 - 175 = 75 $
$$
P(\text{Not correct}) = \frac{75}{250} = \frac{3}{10}
$$
✔ Answer: $ \frac{3}{10} $
---
10. In class IX total students are 36. Out of which 20 students are boys. Find the probability of girls in the class.
- Total students = 36
- Boys = 20 → Girls = $ 36 - 20 = 16 $
$$
P(\text{Girl}) = \frac{16}{36} = \frac{4}{9}
$$
✔ Answer: $ \frac{4}{9} $
---
11. Between 5 and 15, find the probability of having an odd number.
- Numbers between 5 and 15: 6, 7, 8, 9, 10, 11, 12, 13, 14 → Total = 9 numbers
- Odd numbers: 7, 9, 11, 13 → 4 odds
$$
P(\text{Odd}) = \frac{4}{9}
$$
✔ Answer: $ \frac{4}{9} $
> Note: "Between 5 and 15" usually means excluding 5 and 15.
---
12. In 1500 families, 814 families have 2 children and rest have 1 child. Find the probability of families having 1 child.
- Families with 2 children = 814
- Total families = 1500
- Families with 1 child = $ 1500 - 814 = 686 $
$$
P(\text{1 child}) = \frac{686}{1500} = \frac{343}{750}
$$
✔ Answer: $ \frac{343}{750} $
---
13. In word 'INDIA', what is the probability of getting letter 'I'?
- Word: I, N, D, I, A → 5 letters
- Letter 'I' appears twice
$$
P(\text{I}) = \frac{2}{5}
$$
✔ Answer: $ \frac{2}{5} $
---
14. In a bag of 56 apples, 19 were rotten. One apple is chosen at random. Find the probability of getting a fresh apple.
- Rotten = 19
- Fresh = $ 56 - 19 = 37 $
$$
P(\text{Fresh}) = \frac{37}{56}
$$
✔ Answer: $ \frac{37}{56} $
---
15. A dice is tossed once, what is the probability of getting number '7'?
- A standard die has faces: 1 to 6
- No face has 7 → impossible event
$$
P(7) = 0
$$
✔ Answer: $ 0 $
---
✔ Final Answers Summary:
| Question | Answer |
|--------|--------|
| 1 | $ \frac{1}{2} $ |
| 2 | $ \frac{3}{13} $ |
| 3 | $ \frac{1}{2} $ |
| 4 | $ \frac{2}{3} $ |
| 5 | $ \frac{1}{52} $ |
| 6 | $ \frac{5}{6} $ |
| 7 | $ \frac{1}{3} $ |
| 8 | $ \frac{49}{100} $ |
| 9 | $ \frac{3}{10} $ |
| 10 | $ \frac{4}{9} $ |
| 11 | $ \frac{4}{9} $ |
| 12 | $ \frac{343}{750} $ |
| 13 | $ \frac{2}{5} $ |
| 14 | $ \frac{37}{56} $ |
| 15 | $ 0 $ |
Let me know if you'd like these explained further or visualized!
Parent Tip: Review the logic above to help your child master the concept of probability worksheets pdf.