Profit and Loss | PDF - Free Printable

Let's solve each of these profit and loss word problems step by step.

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1. A TV was bought for ₹18,950 and sold at a loss of ₹4780. Find the selling price.

- Cost Price (CP) = ₹18,950
- Loss = ₹4,780
- Selling Price (SP) = CP – Loss
$$
SP = 18,950 - 4,780 = ₹14,170
$$

✔ Answer: ₹14,170

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2. A second-hand car was sold for ₹1,90,000, at a loss of ₹85. Find the CP of the car.

- Selling Price (SP) = ₹1,90,000
- Loss = ₹85
- CP = SP + Loss
$$
CP = 1,90,000 + 85 = ₹1,90,085
$$

✔ Answer: ₹1,90,085

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3. Jane sold her neck set for ₹20,000 at a profit of ₹1,737. Find the CP of the neck set.

- SP = ₹20,000
- Profit = ₹1,737
- CP = SP – Profit
$$
CP = 20,000 - 1,737 = ₹18,263
$$

✔ Answer: ₹18,263

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4. Abraham bought a music system for ₹6375.00 and spent ₹75.00 on transportation. He sold it for ₹6400.00. Find his profit or loss percent.

- CP = ₹6375 + ₹75 = ₹6450
- SP = ₹6400
- Since SP < CP → Loss
- Loss = CP – SP = 6450 – 6400 = ₹50
- Loss % = $ \frac{\text{Loss}}{\text{CP}} \times 100 = \frac{50}{6450} \times 100 \approx 0.776\% $

✔ Answer: Loss of approximately 0.78%

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5. Joy bought pens at ₹120 a dozen. He sold it for ₹15 each. What is his profit percent?

- CP per pen = ₹120 / 12 = ₹10
- SP per pen = ₹15
- Profit per pen = 15 – 10 = ₹5
- Profit % = $ \frac{5}{10} \times 100 = 50\% $

✔ Answer: 50% profit

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6. Simi bought a study table for ₹9000. She sold it at a profit of 20%. How much profit did she make? What is the selling price?

- CP = ₹9000
- Profit % = 20%
- Profit = $ \frac{20}{100} \times 9000 = ₹1800 $
- SP = CP + Profit = 9000 + 1800 = ₹10,800

✔ Answer: Profit = ₹1800, SP = ₹10,800

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7. Find the selling price if the cost price is ₹1200 and loss percent is 25.

- CP = ₹1200
- Loss % = 25%
- Loss = $ \frac{25}{100} \times 1200 = ₹300 $
- SP = CP – Loss = 1200 – 300 = ₹900

✔ Answer: ₹900

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8. Marshall bought 20 refills and sold them at ₹4 each. If it had cost ₹50 for the refills, what was his profit or loss percent?

- Total CP = ₹50
- Number of refills = 20
- SP per refill = ₹4
- Total SP = 20 × 4 = ₹80
- Since SP > CP → Profit
- Profit = 80 – 50 = ₹30
- Profit % = $ \frac{30}{50} \times 100 = 60\% $

✔ Answer: 60% profit

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9. Mr. Smith buys pencils at ₹250 per hundred and sells each at ₹1.75. Find his loss or profit.

- CP per pencil = ₹250 / 100 = ₹2.50
- SP per pencil = ₹1.75
- Since SP < CP → Loss
- Loss per pencil = 2.50 – 1.75 = ₹0.75
- Loss % = $ \frac{0.75}{2.50} \times 100 = 30\% $

✔ Answer: 30% loss

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10. Davis bought a second-hand cycle for ₹500. He spent ₹80 in repairs and ₹175 in repainting. He then sold it to John for ₹900. How much did he gain or lose?

- Total CP = Purchase + Repairs + Repainting
= 500 + 80 + 175 = ₹755
- SP = ₹900
- Profit = SP – CP = 900 – 755 = ₹145

✔ Answer: Gain of ₹145

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11. A fruit vendor bought 600 apples for ₹4800. He spent ₹400 on transportation. How much should he sell each to get a profit of ₹1000?

- Total CP = 4800 + 400 = ₹5200
- Desired Profit = ₹1000
- Total SP needed = 5200 + 1000 = ₹6200
- Number of apples = 600
- SP per apple = $ \frac{6200}{600} = ₹10.33 $ (approx)

✔ Answer: ₹10.33 per apple (or ₹10.34 if rounded up)

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12. Tim bought a box of chocolates for ₹650 and sold it to Tom at a profit of ₹75. Find the selling price.

- CP = ₹650
- Profit = ₹75
- SP = CP + Profit = 650 + 75 = ₹725

✔ Answer: ₹725

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13. David bought 2 dozen eggs for ₹56. Since 6 of them broke, he incurred a loss of ₹20 on selling them. What was the selling price of one egg?

- 2 dozen = 24 eggs
- CP = ₹56
- Loss = ₹20
- So, SP of all eggs = CP – Loss = 56 – 20 = ₹36
- But only 24 – 6 = 18 eggs were sold
- SP per egg = $ \frac{36}{18} = ₹2 $

✔ Answer: ₹2 per egg

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## ✔ Final Answers Summary:

| Q | Answer |
|---|--------|
| 1 | ₹14,170 |
| 2 | ₹1,90,085 |
| 3 | ₹18,263 |
| 4 | Loss ≈ 0.78% |
| 5 | 50% profit |
| 6 | Profit = ₹1800, SP = ₹10,800 |
| 7 | ₹900 |
| 8 | 60% profit |
| 9 | 30% loss |
| 10 | Gain of ₹145 |
| 11 | ₹10.33 per apple |
| 12 | ₹725 |
| 13 | ₹2 per egg |

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