Protons, Neutrons, and Electrons Practice Worksheet | Slides ... - Free Printable

Problem Overview:

The task involves filling in the necessary information for various elements based on their atomic number, atomic mass, and other properties. The key concepts to use are:
1. Atomic Number: Represents the number of protons (and electrons) in a neutral atom.
2. Atomic Mass: The total mass of an atom, primarily due to protons and neutrons.
3. Number of Neutrons: Calculated as \( \text{Atomic Mass} - \text{Atomic Number} \).

Solution:

#### Step 1: Understand the format
Each element is given with:
- Atomic Number (top left)
- Element Symbol (center)
- Atomic Mass (bottom)

We need to:
1. Identify the element name.
2. Determine the number of protons.
3. Calculate the number of neutrons.

#### Step 2: Solve for each element

##### Row 1:
1. He (Helium)
- Atomic Number: 2
- Atomic Mass: 4
- Element Name: Helium
- Number of Protons: 2 (same as atomic number)
- Number of Neutrons: \( 4 - 2 = 2 \)

2. Fe (Iron)
- Atomic Number: 26
- Atomic Mass: 56
- Element Name: Iron
- Number of Protons: 26
- Number of Neutrons: \( 56 - 26 = 30 \)

3. Al (Aluminum)
- Atomic Number: 13
- Atomic Mass: 27
- Element Name: Aluminum
- Number of Protons: 13
- Number of Neutrons: \( 27 - 13 = 14 \)

##### Row 2:
4. Ca (Calcium)
- Atomic Number: 20
- Atomic Mass: 40
- Element Name: Calcium
- Number of Protons: 20
- Number of Neutrons: \( 40 - 20 = 20 \)

5. Ne (Neon)
- Atomic Number: 10
- Atomic Mass: 20
- Element Name: Neon
- Number of Protons: 10
- Number of Neutrons: \( 20 - 10 = 10 \)

6. C (Carbon)
- Atomic Number: 6
- Atomic Mass: 12
- Element Name: Carbon
- Number of Protons: 6
- Number of Neutrons: \( 12 - 6 = 6 \)

##### Row 3:
7. F (Fluorine)
- Atomic Number: 9
- Atomic Mass: 19
- Element Name: Fluorine
- Number of Protons: 9
- Number of Neutrons: \( 19 - 9 = 10 \)

8. Cl (Chlorine)
- Atomic Number: 17
- Atomic Mass: 35
- Element Name: Chlorine
- Number of Protons: 17
- Number of Neutrons: \( 35 - 17 = 18 \)

9. Na (Sodium)
- Atomic Number: 11
- Atomic Mass: 23
- Element Name: Sodium
- Number of Protons: 11
- Number of Neutrons: \( 23 - 11 = 12 \)

#### Step 3: Organize the answers

| Element | Atomic Number | Atomic Mass | Element Name | # Protons | # Neutrons |
|---------|---------------|-------------|------------------|-----------|------------|
| He | 2 | 4 | Helium | 2 | 2 |
| Fe | 26 | 56 | Iron | 26 | 30 |
| Al | 13 | 27 | Aluminum | 13 | 14 |
| Ca | 20 | 40 | Calcium | 20 | 20 |
| Ne | 10 | 20 | Neon | 10 | 10 |
| C | 6 | 12 | Carbon | 6 | 6 |
| F | 9 | 19 | Fluorine | 9 | 10 |
| Cl | 17 | 35 | Chlorine | 17 | 18 |
| Na | 11 | 23 | Sodium | 11 | 12 |

Final Answer:

\[
\boxed{
\begin{array}{|c|c|c|c|c|c|}
\hline
\text{Element} & \text{Atomic Number} & \text{Atomic Mass} & \text{Element Name} & \# \text{Protons} & \# \text{Neutrons} \\
\hline
\text{He} & 2 & 4 & \text{Helium} & 2 & 2 \\
\text{Fe} & 26 & 56 & \text{Iron} & 26 & 30 \\
\text{Al} & 13 & 27 & \text{Aluminum} & 13 & 14 \\
\text{Ca} & 20 & 40 & \text{Calcium} & 20 & 20 \\
\text{Ne} & 10 & 20 & \text{Neon} & 10 & 10 \\
\text{C} & 6 & 12 & \text{Carbon} & 6 & 6 \\
\text{F} & 9 & 19 & \text{Fluorine} & 9 & 10 \\
\text{Cl} & 17 & 35 & \text{Chlorine} & 17 & 18 \\
\text{Na} & 11 & 23 & \text{Sodium} & 11 & 12 \\
\hline
\end{array}
}
\]