Final Answer:
The possible eye colors of the child are brown (B) and blue (b); specifically, all offspring will have genotype Bb, so all will have brown eyes.
The possibility of the child having freckles is 100% (all offspring will have genotype Ff, so all will have freckles).
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Explanation:
Let’s go through each of the two bottom problems one by one.
First problem (eye color):
- Father has dominant brown eyes → genotype BB
- Mother has recessive blue eyes → genotype bb
- In the Punnett square, father contributes only B alleles, mother contributes only b alleles.
- So every box in the square is Bb.
- Since B (brown) is dominant over b (blue), any Bb person has brown eyes.
→ All children will have brown eyes.
Second problem (freckles):
- Father has freckles (FF) — dominant trait, homozygous.
- Mother does *not* have freckles (ff) — recessive, so must be homozygous recessive.
- Father gives only F, mother gives only f.
- Every child gets F from dad and f from mom → genotype Ff.
- Since F (freckles) is dominant, Ff means the person *does* have freckles.
→ All children will have freckles. So the possibility is 100%.
Parent Tip: Review the logic above to help your child master the concept of punnett square worksheet with answer key.
