Genetics worksheet on dog coat color inheritance using Punnett squares.
A blurry image of a genetics worksheet titled "A Little Added Challenge" featuring Punnett squares for dog coat color inheritance, with questions and diagrams.
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Step-by-step solution for: SOLUTION: SCB101 Punnett Square Practice Worksheet - Studypool
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Show Answer Key & Explanations
Step-by-step solution for: SOLUTION: SCB101 Punnett Square Practice Worksheet - Studypool
Let’s solve this step by step.
We are told:
- There is a hereditary deafness caused by a recessive gene “d”.
- That means:
→ To be deaf, the dog must have genotype dd (two copies of the recessive allele).
→ If the dog has at least one D, it can hear (genotypes DD or Dd).
- Gilbert is a male dog who can hear → so his genotype is either DD or Dd.
- We want to find out what his genotype is — specifically, whether he carries the deafness gene (i.e., is Dd) or not (DD).
- The way to test this is to breed him with a deaf female → which must be dd (since deafness is recessive).
---
Since Gilbert can hear, and deafness is recessive, he could be:
→ DD (homozygous dominant — no deafness gene)
→ Dd (heterozygous — carrier of deafness gene but still hears)
✔ So answer for part 1: DD or Dd
---
We’ll do two Punnett squares — one assuming Gilbert is DD, one assuming he is Dd.
---
#### Possible Cross 1: Gilbert = DD × Deaf Female = dd
Gametes from Gilbert (DD): only D
Gametes from female (dd): only d
Punnett Square:
| | d | d |
|-------|-------|-------|
| D | Dd | Dd |
| D | Dd | Dd |
All offspring: Dd → all can hear (because they have one D)
So:
- % of possible Genotypes:
→ 100% Dd
→ 0% DD
→ 0% dd
- % of possible Phenotypes:
→ 100% Can Hear
→ 0% Deaf
---
#### Possible Cross 2: Gilbert = Dd × Deaf Female = dd
Gametes from Gilbert (Dd): D or d
Gametes from female (dd): only d
Punnett Square:
| | d | d |
|-------|-------|-------|
| D | Dd | Dd |
| d | dd | dd |
Offspring:
- 50% Dd → can hear
- 50% dd → deaf
So:
- % of possible Genotypes:
→ 50% Dd
→ 0% DD
→ 50% dd
- % of possible Phenotypes:
→ 50% Can Hear
→ 50% Deaf
---
If we breed Gilbert with a deaf female (dd), then:
→ If any puppies are deaf (dd), that means Gilbert must have given them a “d” allele → so Gilbert is Dd.
→ If all puppies can hear (all Dd), then Gilbert likely gave only “D” alleles → so Gilbert is probably DD.
But note: even if Gilbert is Dd, there’s a 50% chance each puppy is hearing — so if you get only hearing puppies in a small litter, it might just be luck. But if you get *any* deaf puppy, you know for sure Gilbert is Dd.
So the key is:
👉 If any offspring are deaf, Gilbert is Dd. If all offspring can hear, Gilbert is likely DD.
---
Final Answer:
1. Two possible genotypes of Gilbert: DD or Dd
2.
Possible Cross 1 (Gilbert = DD):
- % Genotypes: 100% Dd, 0% DD, 0% dd
- % Phenotypes: 100% Can Hear, 0% Deaf
Possible Cross 2 (Gilbert = Dd):
- % Genotypes: 50% Dd, 0% DD, 50% dd
- % Phenotypes: 50% Can Hear, 50% Deaf
3. You can tell Gilbert’s genotype by breeding him with a deaf female (dd). If any puppies are deaf, Gilbert is Dd. If all puppies can hear, Gilbert is likely DD.
We are told:
- There is a hereditary deafness caused by a recessive gene “d”.
- That means:
→ To be deaf, the dog must have genotype dd (two copies of the recessive allele).
→ If the dog has at least one D, it can hear (genotypes DD or Dd).
- Gilbert is a male dog who can hear → so his genotype is either DD or Dd.
- We want to find out what his genotype is — specifically, whether he carries the deafness gene (i.e., is Dd) or not (DD).
- The way to test this is to breed him with a deaf female → which must be dd (since deafness is recessive).
---
Part 1: What are the two possible genotypes of Gilbert?
Since Gilbert can hear, and deafness is recessive, he could be:
→ DD (homozygous dominant — no deafness gene)
→ Dd (heterozygous — carrier of deafness gene but still hears)
✔ So answer for part 1: DD or Dd
---
Part 2: Breeding Gilbert with a deaf female (dd)
We’ll do two Punnett squares — one assuming Gilbert is DD, one assuming he is Dd.
---
#### Possible Cross 1: Gilbert = DD × Deaf Female = dd
Gametes from Gilbert (DD): only D
Gametes from female (dd): only d
Punnett Square:
| | d | d |
|-------|-------|-------|
| D | Dd | Dd |
| D | Dd | Dd |
All offspring: Dd → all can hear (because they have one D)
So:
- % of possible Genotypes:
→ 100% Dd
→ 0% DD
→ 0% dd
- % of possible Phenotypes:
→ 100% Can Hear
→ 0% Deaf
---
#### Possible Cross 2: Gilbert = Dd × Deaf Female = dd
Gametes from Gilbert (Dd): D or d
Gametes from female (dd): only d
Punnett Square:
| | d | d |
|-------|-------|-------|
| D | Dd | Dd |
| d | dd | dd |
Offspring:
- 50% Dd → can hear
- 50% dd → deaf
So:
- % of possible Genotypes:
→ 50% Dd
→ 0% DD
→ 50% dd
- % of possible Phenotypes:
→ 50% Can Hear
→ 50% Deaf
---
Part 3: How would you tell the genotype of Gilbert’s male dog?
If we breed Gilbert with a deaf female (dd), then:
→ If any puppies are deaf (dd), that means Gilbert must have given them a “d” allele → so Gilbert is Dd.
→ If all puppies can hear (all Dd), then Gilbert likely gave only “D” alleles → so Gilbert is probably DD.
But note: even if Gilbert is Dd, there’s a 50% chance each puppy is hearing — so if you get only hearing puppies in a small litter, it might just be luck. But if you get *any* deaf puppy, you know for sure Gilbert is Dd.
So the key is:
👉 If any offspring are deaf, Gilbert is Dd. If all offspring can hear, Gilbert is likely DD.
---
Final Answer:
1. Two possible genotypes of Gilbert: DD or Dd
2.
Possible Cross 1 (Gilbert = DD):
- % Genotypes: 100% Dd, 0% DD, 0% dd
- % Phenotypes: 100% Can Hear, 0% Deaf
Possible Cross 2 (Gilbert = Dd):
- % Genotypes: 50% Dd, 0% DD, 50% dd
- % Phenotypes: 50% Can Hear, 50% Deaf
3. You can tell Gilbert’s genotype by breeding him with a deaf female (dd). If any puppies are deaf, Gilbert is Dd. If all puppies can hear, Gilbert is likely DD.
Parent Tip: Review the logic above to help your child master the concept of punnett squares practice worksheet.