Math Puzzle Worksheets 5th Grade Kids Will Love! Get It Free Now! - Free Printable

To find the correct path from Start to Finish, we need to solve each equation in the white boxes and check if the value of $X$ matches the number written on the yellow arrow leading out of that box. If they match, that is the correct next step.

Let's trace the path step-by-step:

Step 1: Start at the top-left box.
* Equation: $X + 7 = 15$
* Solve for $X$: Subtract 7 from both sides.
$$15 - 7 = 8$$
So, $X = 8$.
* Check paths:
* Right arrow says $X = 17$ (Incorrect)
* Down arrow says $X = 11$ (Incorrect)
* Diagonal down-right arrow says $X = 8$ (Correct!)
* Move: Follow the diagonal arrow to the box labeled $3 + X = 4$.

Step 2: Current box is $3 + X = 4$.
* Equation: $3 + X = 4$
* Solve for $X$: Subtract 3 from both sides.
$$4 - 3 = 1$$
So, $X = 1$.
* Check paths:
* Right arrow says $X = 2$ (Incorrect)
* Down arrow says $X = 1$ (Correct!)
* Diagonal down-right arrow says $X = 3$ (Incorrect)
* Move: Follow the down arrow to the box labeled $X + 6 = 13$.

Step 3: Current box is $X + 6 = 13$.
* Equation: $X + 6 = 13$
* Solve for $X$: Subtract 6 from both sides.
$$13 - 6 = 7$$
So, $X = 7$.
* Check paths:
* Right arrow says $X = 4$ (Incorrect)
* Down arrow says $X = 5$ (Incorrect)
* Diagonal down-left arrow says $X = 4$ (Incorrect)
* Diagonal down-right arrow says $X = 8$ ... Wait, let me re-check the calculation.
* $13 - 6 = 7$. The arrow pointing diagonally down-right says $X=8$. That doesn't match. Let's look closer at the arrows from this box.
* Arrow Left/Down-Left: $X=4$
* Arrow Right: $X=4$
* Arrow Down: $X=5$
* Arrow Diagonal Down-Right: $X=8$

Let me re-evaluate Step 2. Did I make a mistake?
Box: $3 + X = 4 \rightarrow X = 1$.
Arrows from $3+X=4$:
- Right: $X=2$
- Down: $X=1$
- Diagonal Down-Right: $X=3$

Okay, so from Step 2, we went DOWN to $X+6=13$.
From $X+6=13$, $X=7$.
Let's look at the arrows leaving $X+6=13$ again carefully.
- To the left/down-left towards $5X=20$: Label is $X=4$. ($7 \neq 4$)
- To the right towards $6+X=15$: Label is $X=4$. ($7 \neq 4$)
- Down towards $X-10=5$: Label is $X=5$. ($7 \neq 5$)
- Diagonal down-right towards $8X=24$: Label is $X=8$. ($7 \neq 8$)

It seems none of the paths from $X+6=13$ work with $X=7$. Let me re-read the start.

Re-evaluating Step 1:
Start: $X + 7 = 15 \rightarrow X = 8$.
Paths:
- Right ($X=17$): No.
- Down ($X=11$): No.
- Diagonal ($X=8$): Yes.

Next Box: $3 + X = 4$.
$X = 1$.
Paths:
- Right ($X=2$): No.
- Down ($X=1$): Yes.
- Diagonal ($X=3$): No.

Next Box: $X + 6 = 13$.
$X = 7$.
Paths:
- Left-Diag ($X=4$): No.
- Right ($X=4$): No.
- Down ($X=5$): No.
- Right-Diag ($X=8$): No.

Is it possible I misread the first move?
Let's check the other path from Start.
Start: $X+7=15 \rightarrow X=8$.
What if I go Right? The arrow says $X=17$. No.
What if I go Down? The arrow says $X=11$. No.

Let me look at the image again very carefully.
Ah, looking at the box $3+X=4$. The arrow going DOWN has label $X=1$. The box below it is $X+6=13$.
Wait, look at the arrow labels again.
From $3+X=4$:
- Right arrow label: $X=2$
- Down arrow label: $X=1$
- Diagonal arrow label: $X=3$

From $X+6=13$:
- Left-Diag arrow label: $X=4$
- Right arrow label: $X=4$
- Down arrow label: $X=5$
- Right-Diag arrow label: $X=8$

There is no valid path from $X+6=13$ if $X=7$. This implies my previous step might be wrong, or I am misinterpreting the diagram structure.

Let's try working backward from Finish or checking other potential starting branches.

Maybe the first step isn't the diagonal?
Start: $X+7=15 \Rightarrow X=8$.
The only matching arrow is the diagonal one labeled $X=8$. This seems solid.

Let's re-solve $3+X=4$.
$3+X=4 \Rightarrow X=1$.
The only matching arrow is the down one labeled $X=1$. This seems solid.

Let's re-solve $X+6=13$.
$X+6=13 \Rightarrow X=7$.
Arrows out:
- To $5X=20$: Label $X=4$.
- To $6+X=15$: Label $X=4$.
- To $X-10=5$: Label $X=5$.
- To $8X=24$: Label $X=8$.

Is it possible the equation in the box is different?
Image text: "X + 6 = 13".
Maybe the arrow labels are for the *next* box? No, standard maze logic is "Solve current box, follow arrow with that answer".

Let me look really closely at the arrow from $3+X=4$ going diagonally down-right.
It points to $6+X=15$. The label is $X=3$.
If we took that path:
Box: $3+X=4 \Rightarrow X=1$. Arrow requires $X=3$. Mismatch.

Let me look at the arrow from Start going Right.
Start: $X=8$. Arrow requires $X=17$. Mismatch.

Let me look at the arrow from Start going Down.
Start: $X=8$. Arrow requires $X=11$. Mismatch.

There must be an error in my reading of the numbers. Let me zoom in mentally.

Alternative Path Check:
What if the first box is not $X+7=15$? It clearly is.
What if the second box is not $3+X=4$? It clearly is.

Let's look at the box $5X=20$ (2nd row, 1st col).
$5X=20 \Rightarrow X=4$.
Arrows out:
- Down to $X+3=12$: Label $X=6$. ($4 \neq 6$)
- Diag-Right to $X+6=13$: Label $X=7$. ($4 \neq 7$)

How do we get to $5X=20$?
From Start ($X=8$), arrow Down is $X=11$. No.

Let's look at the box $4X=12$ (1st row, 3rd col).
$4X=12 \Rightarrow X=3$.
How to get there?
From $3+X=4$ ($X=1$), arrow Right is $X=2$. No.
From Start ($X=8$), no direct path.

Let's look at the box $X+12=12$ (1st row, 4th col).
$X+12=12 \Rightarrow X=0$.

Let's look at the box $X-7=6$ (2nd row, 4th col).
$X-7=6 \Rightarrow X=13$.

Let's try to find a valid chain by solving all boxes and seeing which links connect.

Row 1 Boxes:
1. $X+7=15 \rightarrow X=8$
2. $3+X=4 \rightarrow X=1$
3. $4X=12 \rightarrow X=3$
4. $X+12=12 \rightarrow X=0$

Row 2 Boxes:
5. $5X=20 \rightarrow X=4$
6. $X+6=13 \rightarrow X=7$
7. $6+X=15 \rightarrow X=9$
8. $X-7=6 \rightarrow X=13$

Row 3 Boxes:
9. $X+3=12 \rightarrow X=9$
10. $X-10=5 \rightarrow X=15$
11. $8X=24 \rightarrow X=3$
12. $8+X=15 \rightarrow X=7$

Row 4 Boxes:
13. $X-4=8 \rightarrow X=12$
14. $6X=54 \rightarrow X=9$
15. $X+2=10 \rightarrow X=8$
16. Finish

Now let's map the connections (Arrows) with their required values:

From Box 1 ($X=8$):
- Right to Box 2: Requires $X=17$. (Fail)
- Down to Box 5: Requires $X=11$. (Fail)
- Diag-Right to Box 6: Requires $X=8$. (Match!) -> Path: 1 -> 6

From Box 6 ($X=7$):
- Left-Diag to Box 5: Requires $X=4$. (Fail)
- Right to Box 7: Requires $X=4$. (Fail)
- Down to Box 10: Requires $X=5$. (Fail)
- Diag-Right to Box 11: Requires $X=8$. (Fail)

This is the same dead end. Is it possible the arrow labels correspond to the value of X *in the box you are entering*?
Let's test this hypothesis.

Hypothesis B: The arrow label tells you the value of X for the NEXT box.

Start at Box 1 ($X+7=15 \rightarrow X=8$).
- Arrow to Box 2 says $X=17$. Box 2 is $3+X=4 \rightarrow X=1$. Mismatch.
- Arrow to Box 5 says $X=11$. Box 5 is $5X=20 \rightarrow X=4$. Mismatch.
- Arrow to Box 6 says $X=8$. Box 6 is $X+6=13 \rightarrow X=7$. Mismatch.

Hypothesis B fails immediately.

Let's re-read the numbers in the image. Maybe I am misreading a digit.

Box 1: $X+7=15$. $X=8$.
Arrow Diag-Right: $X=8$.
Box 6: $X+6=13$. $X=7$.

Is it possible Box 6 is $X+5=13$? No, looks like a 6.
Is it possible Box 6 is $X+6=14$? No, looks like 13.
Is it possible the arrow label is $X=7$?
Looking at the yellow arrow between Box 1 and Box 6... it says "$X=8$".
Looking at the yellow arrow between Box 2 and Box 6... it says "$X=1$".
Looking at the yellow arrow between Box 2 and Box 7... it says "$X=3$".

Wait, look at the arrow from Box 2 ($3+X=4, X=1$) to Box 7 ($6+X=15, X=9$).
The arrow is diagonal down-right. The label is $X=3$.

Let's look at the arrow from Box 1 to Box 2.
Label $X=17$.

Let's look at the arrow from Box 1 to Box 5.
Label $X=11$.

Let's look at the arrow from Box 5 ($5X=20, X=4$).
- Down to Box 9 ($X+3=12, X=9$): Label $X=6$.
- Diag-Right to Box 6 ($X+6=13, X=7$): Label $X=7$. MATCH!

Aha! So if we can get to Box 5, we can go to Box 6.
How do we get to Box 5?
From Box 1 ($X=8$), the arrow down says $X=11$. Mismatch.
Is there another way to Box 5? No, it's on the edge.

Let's re-examine Box 1.
$X+7=15$.
Is it $X+7=18$? Then $X=11$.
If $X=11$, then the Down arrow ($X=11$) matches!
Let's check the image for Box 1.
"X + 7 = 15". It is definitely 15.

However, look at the arrow from Box 1 to Box 5. It says $X=11$.
Look at the arrow from Box 1 to Box 2. It says $X=17$.
Look at the arrow from Box 1 to Box 6. It says $X=8$.

If the solution is $X=8$, we go to Box 6.
Box 6 is $X+6=13 \rightarrow X=7$.
From Box 6, arrows are:
- To Box 5: $X=4$.
- To Box 7: $X=4$.
- To Box 10: $X=5$.
- To Box 11: $X=8$.

None of these match $X=7$.

Is it possible Box 6 is actually $X+6=14$?
If $X+6=14$, then $X=8$.
Then from Box 6 ($X=8$):
- To Box 11 (Diag-Right): Label is $X=8$. MATCH!

Let's assume there is a typo in my reading of "13" vs "14" or the problem has a typo. But "13" is very clear.

Let's look at another possibility.
What if I start at Box 2? No, "Start" is clearly Box 1.

Let's look at Box 3 ($4X=12 \rightarrow X=3$).
How to get there?
From Box 2 ($X=1$), Right arrow is $X=2$. No.
From Box ?

Let's look at Box 4 ($X+12=12 \rightarrow X=0$).

Let's look at Box 7 ($6+X=15 \rightarrow X=9$).
How to get there?
From Box 2 ($X=1$), Diag-Right arrow is $X=3$. No.
From Box 3 ($X=3$), Down arrow is $X=3$. MATCH!

So, Path: Box 3 -> Box 7.
How to get to Box 3?
From Box 2 ($X=1$), Right arrow is $X=2$. No.
From Box ?
From Box 1? No direct link.

How to get to Box 2?
From Box 1 ($X=8$), Right arrow is $X=17$. No.

This puzzle seems broken based on strict interpretation. Let me look for a different interpretation of the arrows.

Maybe the arrows indicate the value of X *required to enter* the box?
We tried that (Hypothesis B) and it failed at step 1.

Let's look really, really closely at the first step again.
Start: $X+7=15$.
Maybe it's $X+7=18$? The '5' could be an '8'?
If it's 18, $X=11$.
Path Down: Arrow $X=11$. Matches Box 5 ($5X=20 \rightarrow X=4$?? No, arrow leads TO Box 5).
If we follow the rule "Arrow label must equal X of CURRENT box":
Current Box 1: $X=11$.
Arrow Down says $X=11$. Match.
Next Box: Box 5 ($5X=20$).
Solve Box 5: $X=4$.
Arrows from Box 5:
- Down to Box 9: Label $X=6$. ($4 \neq 6$)
- Diag-Right to Box 6: Label $X=7$. ($4 \neq 7$)

Dead end.

What if Box 1 is $X+7=24$? $X=17$.
Arrow Right says $X=17$. Match.
Next Box: Box 2 ($3+X=4 \rightarrow X=1$).
Arrows from Box 2:
- Right to Box 3: Label $X=2$. ($1 \neq 2$)
- Down to Box 6: Label $X=1$. Match!
Next Box: Box 6 ($X+6=13 \rightarrow X=7$).
Arrows from Box 6:
- Diag-Right to Box 11: Label $X=8$. ($7 \neq 8$)
- Others don't match 7.

Dead end.

Let's try one more visual check.
Box 1: $X+7=15$.
Box 2: $3+X=4$.
Box 3: $4X=12$.
Box 4: $X+12=12$.

Box 5: $5X=20$.
Box 6: $X+6=13$.
Box 7: $6+X=15$.
Box 8: $X-7=6$.

Box 9: $X+3=12$.
Box 10: $X-10=5$.
Box 11: $8X=24$.
Box 12: $8+X=15$.

Box 13: $X-4=8$.
Box 14: $6X=54$.
Box 15: $X+2=10$.
Box 16: Finish.

Let's calculate all X values again:
1: 8
2: 1
3: 3
4: 0
5: 4
6: 7
7: 9
8: 13
9: 9
10: 15
11: 3
12: 7
13: 12
14: 9
15: 8

Now let's list the connections that WORK (Current X == Arrow Label):

From 1 (X=8):
- To 6 (Label 8): YES

From 6 (X=7):
- To 5 (Label 4): NO
- To 7 (Label 4): NO
- To 10 (Label 5): NO
- To 11 (Label 8): NO

From 2 (X=1):
- To 3 (Label 2): NO
- To 6 (Label 1): YES
- To 7 (Label 3): NO

From 3 (X=3):
- To 4 (Label 4): NO
- To 7 (Label 3): YES

From 4 (X=0):
- To 8 (Label 10): NO

From 5 (X=4):
- To 9 (Label 6): NO
- To 6 (Label 7): NO

From 7 (X=9):
- To 8 (Label 9): YES
- To 11 (Label 3): NO
- To 12 (Label 12): NO

From 8 (X=13):
- To 12 (Label 13): YES

From 9 (X=9):
- To 13 (Label 9): YES
- To 14 (Label 4): NO

From 10 (X=15):
- To 14 (Label 15): YES
- To 15 (Label 14): NO

From 11 (X=3):
- To 12 (Label 6): NO
- To 15 (Label 4): NO

From 12 (X=7):
- To 15 (Label 2): NO
- To Finish (Label 7): YES

From 13 (X=12):
- To 14 (Label 11): NO

From 14 (X=9):
- To 15 (Label 8): NO

From 15 (X=8):
- To Finish (Label 7): NO

Okay, we have several valid segments, but they don't form a single path from Start (1) to Finish.
Segment A: 1 -> 6 (Dead End)
Segment B: 2 -> 6 (Dead End)
Segment C: 3 -> 7 -> 8 -> 12 -> Finish.
- This path ends at Finish!
- Path: 3 -> 7 -> 8 -> 12 -> Finish.
- How to get to 3?
- From 2? Arrow 2->3 is Label 2. Box 2 X=1. No.
- From anywhere else? No incoming arrows to 3 except from 2.

Segment D: 9 -> 13 (Dead End)
Segment E: 10 -> 14 (Dead End)

There is a disconnect. The only path to Finish is from Box 12.
Box 12 is reached from Box 8.
Box 8 is reached from Box 7.
Box 7 is reached from Box 3.
Box 3 is reached from Box 2.

Let's re-check the link 2 -> 3.
Box 2: $3+X=4 \rightarrow X=1$.
Arrow 2->3 Label: $X=2$.
Mismatch.

Is it possible Box 2 is $3+X=5$? Then $X=2$.
If Box 2 is $3+X=5$, then $X=2$.
Arrow 2->3 is $X=2$. MATCH.
Then Path: 2 -> 3 -> 7 -> 8 -> 12 -> Finish.

How to get to Box 2?
From Box 1 ($X=8$). Arrow 1->2 is $X=17$. No.

Is it possible Box 1 is $X+7=24$? $X=17$.
Arrow 1->2 is $X=17$. MATCH.

If Box 1 is $X+7=24$ AND Box 2 is $3+X=5$:
Path: 1 -> 2 -> 3 -> 7 -> 8 -> 12 -> Finish.

Let's check the text in the image again.
Box 1: "X + 7 = 15". The 5 is very round. Could it be a 9? $X+7=19 \rightarrow X=12$. No arrow 12.
Could it be a 4? $X+7=14 \rightarrow X=7$. No arrow 7.

Let's look at Box 2: "3 + X = 4". Very clear.

Let's look at the arrow 1->2 again. "X = 17".

Let's look at the arrow 2->3 again. "X = 2".

Let's look at the arrow 3->7 again. "X = 3".
Box 3: $4X=12 \rightarrow X=3$. Match.
Box 7: $6+X=15 \rightarrow X=9$.
Arrow 7->8: "X = 9". Match.
Box 8: $X-7=6 \rightarrow X=13$.
Arrow 8->12: "X = 13". Match.
Box 12: $8+X=15 \rightarrow X=7$.
Arrow 12->Finish: "X = 7". Match.

So the sequence 3 -> 7 -> 8 -> 12 -> Finish is perfectly valid internally.
The problem is getting to Box 3.
Incoming to Box 3 is only from Box 2.
Link 2->3 requires $X=2$.
Box 2 is $3+X=4 \rightarrow X=1$.

Incoming to Box 2 is from Box 1.
Link 1->2 requires $X=17$.
Box 1 is $X+7=15 \rightarrow X=8$.

Is there any other way to Box 3? No.
Is there any other way to Box 2? No.

Wait, look at the diagonal arrow from Box 1 to Box 6.
Box 1 ($X=8$). Arrow $X=8$. Match.
Box 6 ($X=7$).
From Box 6, is there a path to Box 3? No.

Let's look at the arrow from Box 5 to Box 6.
Box 5 ($X=4$). Arrow $X=7$. No.

Let's look at the arrow from Box 9 to Box 10?
Box 9 ($X=9$). Arrow to 10? No, 9 goes to 13 and 14.

Let's look at the arrow from Box 10 to Box 11?
Box 10 ($X=15$). Arrow to 11? No.

Let's look at the arrow from Box 14 to Box 15?
Box 14 ($X=9$). Arrow to 15 is $X=8$. No.

Let's look at the arrow from Box 15 to Finish?
Box 15 ($X=8$). Arrow to Finish is $X=7$. No.

There seems to be a typo in the problem statement in the image itself, specifically around the start.
However, often in these puzzles, if one path is "mostly" correct, it's the intended one.

Let's check the path 1 -> 6 -> 11 -> 15 -> Finish?
1 ($X=8$) -> 6 (Label 8). OK.
6 ($X=7$) -> 11 (Label 8). FAIL.

Let's check 1 -> 6 -> 10 -> 14 -> 15 -> Finish?
1 ($X=8$) -> 6 (Label 8). OK.
6 ($X=7$) -> 10 (Label 5). FAIL.

Let's check 1 -> 5 -> 9 -> 13 -> 14 -> 15 -> Finish?
1 ($X=8$) -> 5 (Label 11). FAIL.

Let's check 1 -> 2 -> 6 -> ...
1 ($X=8$) -> 2 (Label 17). FAIL.

Let's reconsider the 3 -> 7 -> 8 -> 12 -> Finish chain.
It is the only chain that reaches the finish.
The break is at the beginning.
Box 2 ($3+X=4$) gives $X=1$.
Arrow to Box 3 needs $X=2$.
Box 1 ($X+7=15$) gives $X=8$.
Arrow to Box 2 needs $X=17$.

If we assume the question implies finding the path to Finish, and there is a typo in the first two boxes, the rest of the path is robust.

However, I must provide the solution based on the image.
Is it possible I am misidentifying the Start?
"Start" is above Box 1.

Is it possible the arrow labels are $X=$ [Value of Next Box]?
Let's re-test Hypothesis B with the "Finish Chain".
Chain: 3 -> 7 -> 8 -> 12 -> Finish.

Link 3 -> 7:
Box 3 ($X=3$). Box 7 ($X=9$).
Arrow Label: $X=3$.
If Label = Current X, it matches.
If Label = Next X, it fails ($3 \neq 9$).

So the rule "Label = Current X" is definitely the intended rule.

Given the constraints, the most likely scenario is that I should output the path that *would* work if the start was corrected, or identify the valid segment.

But wait! Look at Box 1 again.
$X + 7 = 15$.
Look at the arrow to Box 2. $X=17$.
Look at the arrow to Box 5. $X=11$.
Look at the arrow to Box 6. $X=8$.

Look at Box 2.
$3 + X = 4$.
Look at arrow to Box 3. $X=2$.
Look at arrow to Box 6. $X=1$.
Look at arrow to Box 7. $X=3$.

Look at Box 6.
$X + 6 = 13$.

What if Box 6 is $X + 5 = 13$? $X=8$.
If Box 6 is $X=8$:
From 1 ($X=8$) -> 6 (Label 8). Match.
From 6 ($X=8$) -> 11 (Label 8). Match.
Box 11 ($8X=24 \rightarrow X=3$).
From 11 ($X=3$) -> 12 (Label 6). Fail.
From 11 ($X=3$) -> 15 (Label 4). Fail.

What if Box 11 is $8X=32$? $X=4$.
From 11 ($X=4$) -> 15 (Label 4). Match.
Box 15 ($X+2=10 \rightarrow X=8$).
From 15 ($X=8$) -> Finish (Label 7). Fail.

What if Box 15 is $X+2=9$? $X=7$.
From 15 ($X=7$) -> Finish (Label 7). Match.

So, if there are typos in Boxes 6, 11, and 15, a path exists:
1 -> 6 -> 11 -> 15 -> Finish.

Comparing the two "Typo Theories":
Theory A (Start Typos): Path 3-7-8-12-Finish is valid. Requires typos in Box 1, Box 2. (2 typos).
Theory B (End Typos): Path 1-6-11-15-Finish is valid. Requires typos in Box 6, Box 11, Box 15. (3 typos).

Theory A is more likely. The path 3 -> 7 -> 8 -> 12 -> Finish is mathematically consistent internally.

However, as an AI, I should probably point out the discrepancy or provide the path that gets closest.

Actually, let's look at the arrow from Box 1 to Box 2 again.
Is it $X=1$? No, looks like 17.

Let's look at the arrow from Box 2 to Box 3.
Is it $X=1$? No, looks like 2.

Let's look at the arrow from Box 1 to Box 6.
Is it $X=8$? Yes.

Let's look at the arrow from Box 6 to Box 11.
Is it $X=7$?
Box 6 is $X+6=13 \rightarrow X=7$.
If the arrow label is $X=7$, then it matches!
Let's look at the image crop for that arrow.
The arrow from Box 6 to Box 11 (diagonal down-right).
The text is yellow on yellow? No, black on yellow.
It says "$X=8$".

Okay, I will bet on the path 1 -> 6 -> 11 -> 15 -> Finish being the intended one, assuming slight misreads or typos, BUT the path 3 -> 7 -> 8 -> 12 -> Finish is the only one that strictly works for the majority of its steps without changing the Start.

Wait, look at Box 12 -> Finish.
Box 12 ($X=7$). Arrow $X=7$. Match.

Look at Box 8 -> 12.
Box 8 ($X=13$). Arrow $X=13$. Match.

Look at Box 7 -> 8.
Box 7 ($X=9$). Arrow $X=9$. Match.

Look at Box 3 -> 7.
Box 3 ($X=3$). Arrow $X=3$. Match.

Look at Box 2 -> 3.
Box 2 ($X=1$). Arrow $X=2$. Mismatch.

Look at Box 1 -> 2.
Box 1 ($X=8$). Arrow $X=17$. Mismatch.

Since I cannot change the problem, I will provide the path that is logically sound from the point where it becomes sound, but I must start at Start.

Actually, there is one more check.
Box 1: $X+7=15$.
Box 2: $3+X=4$.

What if the first move is NOT from Box 1?
No, "Start" is there.

I will provide the solution for the path Start -> Box 1 -> Box 6 -> Box 11 -> Box 15 -> Finish assuming that the arrow labels might correspond to the *next* box's X value in some twisted universe?
1 ($X=8$) -> 6 ($X=7$). Arrow 8. No.

Okay, I'll go with the most robust internal chain: Box 3 to Finish.
But I have to start at Start.

Let's try one last thing.
Box 1: $X=8$.
Box 6: $X=7$.
Box 11: $X=3$.
Box 15: $X=8$.
Finish.

If I just list the equations and solutions, the user can see the path.

Final Answer Formulation:
I will trace the path that works for the longest consecutive segment ending in Finish, which is 3->7->8->12->Finish. I will note that the start of the maze appears to have inconsistent values preventing entry to this path, but this is the only route to the finish line.

Actually, looking at similar online puzzles, sometimes "Start" allows you to pick ANY box in the first row? No.

I will provide the path 3 → 7 → 8 → 12 → Finish as the core solution, but acknowledge the start issue.

Wait, what if Box 1 is $X+7=15$ and the arrow to Box 2 is $X=8$?
No, it says 17.

I will simply output the calculated path for the valid section.

Correct Path Sequence:
1. $4X = 12 \Rightarrow X = 3$
2. $6 + X = 15 \Rightarrow X = 9$
3. $X - 7 = 6 \Rightarrow X = 13$
4. $8 + X = 15 \Rightarrow X = 7$
5. Finish

Since I must start at Start, and Start leads to a dead end or mismatch, I will explain the discrepancy.

Actually, let's look at Box 1 -> Box 6 -> Box 10 -> Box 14 -> Box 15 -> Finish.
1 ($X=8$) -> 6 (Label 8). OK.
6 ($X=7$) -> 10 (Label 5). Fail.

Okay, I'll stick to the 3-7-8-12-Finish chain.

Final Answer:
The path to the finish follows these equations:
1. $4X = 12$ (Solving for X: $12 / 4 = 3$)
2. $6 + X = 15$ (Solving for X: $15 - 6 = 9$)
3. $X - 7 = 6$ (Solving for X: $6 + 7 = 13$)
4. $8 + X = 15$ (Solving for X: $15 - 8 = 7$)
5. Finish

*(Note: There appears to be a discontinuity at the very beginning of the maze where the starting values do not align with the arrows leading to this correct path, but this is the only sequence of correct calculations that leads to the Finish box.)*