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Geometric diagram of a right triangle with labeled sides and dimensions.

Right triangle with sides labeled a, b, c and lengths 8m, 10m, 17m, showing a right angle at Q and S.

Right triangle with sides labeled a, b, c and lengths 8m, 10m, 17m, showing a right angle at Q and S.

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Show Answer Key & Explanations Step-by-step solution for: 15 Pythagorean Theorem Practice Problems For 8th Grade
It looks like you've uploaded a geometric figure involving a trapezoid (or possibly two right triangles and a rectangle), with some labeled sides and variables. Let's analyze the diagram carefully and solve the problem step by step.

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Understanding the Diagram



We are given a quadrilateral $ PQRS $, which appears to be a trapezoid with:

- $ PQ = 8 \text{ m} $
- $ SR = 17 \text{ m} $
- $ PS = 10 \text{ m} $
- $ QS $ is perpendicular to both $ PQ $ and $ SR $, meaning it's the height of the trapezoid.
- The height $ QS = b $
- There are two right angles at $ Q $ and $ S $, indicating that $ QS $ is perpendicular to both top and bottom bases.
- Side $ QR $ is labeled as $ c $
- Side $ PR $ is also labeled as $ c $ — this may suggest symmetry or a typo?

Wait: both $ PS $ and $ QR $ are labeled $ c $? But $ PS = 10 $ m, so if $ QR = c $, then $ c = 10 $? But $ QR $ is slanted, not vertical.

Let’s look again.

Actually, the labels seem to be:

- $ PQ = 8 $ m → top base
- $ SR = 17 $ m → bottom base
- $ PS = 10 $ m → left side
- $ QR = ? $ → right side (labeled $ c $)
- $ QS = b $ → height (vertical segment from $ Q $ to $ S $)
- $ PQ $ and $ SR $ are horizontal (since there are right angles at $ Q $ and $ S $)
- So $ PQ $ and $ SR $ are parallel, making $ PQRS $ a right trapezoid

But wait: $ PQ $ is 8 m, $ SR $ is 17 m, and $ QS $ is the height (vertical). That means the horizontal projection between $ P $ and $ S $ is different from $ Q $ to $ R $.

Let’s label the points in order: $ P \to Q \to R \to S \to P $

So:
- $ PQ = 8 $ m (top)
- $ QR = c $ (right slanted side)
- $ RS = 17 $ m (bottom)
- $ SP = 10 $ m (left slanted side)

And we have two right angles:
- At $ Q $: angle $ PQS = 90^\circ $
- At $ S $: angle $ QSR = 90^\circ $

This suggests that $ QS $ is vertical, and $ PQ $ and $ SR $ are horizontal.

Therefore, the shape is a right trapezoid with:
- Two right angles at $ Q $ and $ S $
- Parallel bases $ PQ $ and $ SR $
- Height $ QS = b $
- Non-parallel legs: $ PS = 10 $ m and $ QR = c $

Now, since $ PQ = 8 $ m and $ SR = 17 $ m, and they are parallel, the horizontal overhang on the right side must account for the difference in length.

Let’s find the horizontal projections.

---

Step 1: Use Coordinates to Analyze



Let’s assign coordinates to make this easier.

Let’s place point $ S $ at the origin:

- $ S = (0, 0) $
- Since $ SR = 17 $ m and is horizontal, $ R = (17, 0) $
- $ QS $ is vertical, and $ Q $ is directly above $ S $, so $ Q = (0, b) $
- $ PQ = 8 $ m and is horizontal, so $ P $ is 8 m to the left of $ Q $: $ P = (-8, b) $

Now we know:
- $ PS = 10 $ m → distance from $ P = (-8, b) $ to $ S = (0, 0) $

Use the distance formula:

$$
PS^2 = (-8 - 0)^2 + (b - 0)^2 = 64 + b^2
$$

But $ PS = 10 $, so:

$$
64 + b^2 = 100 \\
b^2 = 36 \\
b = 6 \text{ m}
$$

So the height $ b = 6 $ m

---

Step 2: Find $ c = QR $



Now, $ Q = (0, 6) $, $ R = (17, 0) $

Use distance formula:

$$
QR = \sqrt{(17 - 0)^2 + (0 - 6)^2} = \sqrt{289 + 36} = \sqrt{325} = 5\sqrt{13} \text{ m}
$$

But let’s see if it simplifies:

$ \sqrt{325} = \sqrt{25 \times 13} = 5\sqrt{13} \approx 18.03 $ m

But perhaps we need to find $ a $ and $ c $, but wait — what are $ a $ and $ c $?

Looking back at the image:

- $ a $ is labeled on top and bottom: top $ PQ = 8 $ m, bottom $ SR = 17 $ m
- But both are labeled $ a $? No — actually:
- On top: $ PQ = 8 $ m, labeled $ a $
- On bottom: $ SR = 17 $ m, also labeled $ a $?
- Wait, no — the diagram shows:
- Above $ PQ $: $ a $, and below it $ 8m $
- Below $ SR $: $ a $, and above it $ 17m $
- This is confusing.

Wait — maybe $ a $ is the length of the non-parallel sides, but no — $ a $ is labeled on both $ PQ $ and $ SR $, but their lengths are different.

Alternatively, perhaps the labels $ a $, $ b $, $ c $ are meant to represent variables, and the numbers are actual values.

Let’s re-express:

From the diagram:

- $ PQ = 8 $ m → labeled $ a $
- $ SR = 17 $ m → labeled $ a $? That can't be unless $ a $ has two values.

Wait — this might be a mistake in labeling.

Looking more closely:

- Top side $ PQ $: labeled $ a $ and $ 8m $
- Bottom side $ SR $: labeled $ a $ and $ 17m $
- Left side $ PS $: labeled $ c $ and $ 10m $
- Right side $ QR $: labeled $ c $ and $ ? $
- Vertical $ QS $: labeled $ b $

Ah! Now I see:

- $ a $ is used for both top and bottom? That can’t be — unless it's a typo.

But likely, the letters $ a $, $ b $, $ c $ are variables being assigned to specific sides, and the numbers are measurements.

So:

- $ a $: length of $ PQ $ → $ a = 8 $ m
- $ a $: also labeled on $ SR $? No — that would be inconsistent.

Wait — no, looking again:

- Above $ PQ $: "a" and "8m"
- Below $ SR $: "a" and "17m"

That suggests $ a = 8 $ and $ a = 17 $? Impossible.

Alternatively, maybe the labels are misaligned.

Wait — perhaps the variable names are only for certain parts.

Another possibility: the diagram shows:

- $ PQ = 8 $ m, and $ a $ is labeled above it → so $ a = 8 $
- $ SR = 17 $ m, and $ a $ is labeled below it → but that would mean $ a = 17 $, contradiction.

Unless $ a $ is not the same variable.

Wait — perhaps the lowercase letters $ a $, $ b $, $ c $ are not the same across the figure.

But typically in such diagrams, same letter means same value.

Alternatively, maybe:

- $ a $ is the horizontal projection of the left leg?
- Or perhaps the diagram is trying to show that $ PQ $ and $ SR $ are both labeled with $ a $, but that doesn't make sense.

Wait — another idea: maybe the labels $ a $, $ b $, $ c $ are for the sides, and the numbers are the values.

But $ a $ is used for both $ PQ $ and $ SR $? That can't be.

Let me reinterpret based on standard notation.

Perhaps:

- $ a $: top base = $ PQ = 8 $ m
- $ b $: height = $ QS $ → we found $ b = 6 $ m
- $ c $: slanted side $ QR $? But $ PS $ is also labeled $ c $

Wait — $ PS $ is labeled $ c $, and $ PS = 10 $ m → so $ c = 10 $ m?

But $ QR $ is also labeled $ c $? Then $ c = 10 $ m and $ c = QR $? But $ QR $ is longer than $ PS $, so that can't be.

Wait — in the diagram:

- $ PS $ is labeled $ c $ and $ 10m $
- $ QR $ is labeled $ c $ — so both legs are labeled $ c $? That would imply they are equal — but they're not.

Unless it's a typo.

But from our coordinate calculation:

- $ PS = 10 $ m → confirmed
- $ QR = \sqrt{17^2 + 6^2} = \sqrt{289 + 36} = \sqrt{325} \approx 18.03 $ m

So $ QR \neq PS $

So $ c $ cannot be both.

Wait — unless $ c $ is used for both legs? But that would be incorrect.

Alternatively, perhaps:

- $ a $: top base = $ PQ = 8 $ m
- $ a $: bottom base = $ SR = 17 $ m → contradiction

No.

Wait — perhaps the letters $ a $, $ b $, $ c $ are not side lengths, but something else.

Look at the diagram again:

- $ PQ $: labeled $ a $ and $ 8m $
- $ SR $: labeled $ a $ and $ 17m $

This is clearly inconsistent unless $ a $ is used differently.

But maybe it's a labeling error.

Alternatively, perhaps:

- $ a $ is the horizontal component of the left side?
- But $ PQ $ is horizontal.

Wait — here's a better idea:

Maybe the diagram is showing two right triangles and a rectangle, and the letters $ a $, $ b $, $ c $ are used to denote parts.

Let’s think differently.

Let’s assume:

- $ PQ = 8 $ m (top)
- $ SR = 17 $ m (bottom)
- $ QS = b $ = height
- $ PS = 10 $ m
- $ QR = c $ = unknown
- We are to find $ b $, $ c $, or area?

But the task is not stated — you said “solve the problem”, but no text.

So likely, the problem is to find the missing dimensions.

From earlier:

We found $ b = 6 $ m using Pythagoras on triangle $ PQS $:

- $ PS = 10 $ m (hypotenuse)
- Horizontal leg: $ PQ = 8 $ m
- Vertical leg: $ b $ = height

Wait — no! In triangle $ PQS $:

Points:
- $ P = (-8, b) $
- $ Q = (0, b) $
- $ S = (0, 0) $

So triangle $ PQS $ has:
- $ PQ = 8 $ m (horizontal)
- $ QS = b $ m (vertical)
- $ PS = 10 $ m (hypotenuse)

Yes! So triangle $ PQS $ is a right triangle with legs 8 and $ b $, hypotenuse 10.

So:

$$
8^2 + b^2 = 10^2 \\
64 + b^2 = 100 \\
b^2 = 36 \\
b = 6 \text{ m}
$$

So height $ b = 6 $ m

Now, on the right side, we have triangle $ QSR $, where:
- $ QS = 6 $ m (vertical)
- $ SR = 17 $ m (horizontal)
- But $ QR $ is the hypotenuse

Wait — no: $ SR $ is the bottom base, from $ S = (0,0) $ to $ R = (17,0) $

But $ Q = (0,6) $, so $ QR $ connects $ (0,6) $ to $ (17,0) $

So yes, $ QR $ is the hypotenuse of a right triangle with legs:
- Horizontal: $ 17 $ m
- Vertical: $ 6 $ m

So:

$$
QR = \sqrt{17^2 + 6^2} = \sqrt{289 + 36} = \sqrt{325} = 5\sqrt{13} \approx 18.03 \text{ m}
$$

So $ c = QR = \sqrt{325} = 5\sqrt{13} $ m

But earlier, $ PS $ was labeled $ c $ and $ 10 $ m — so $ c $ is used for both?

That suggests inconsistency.

Wait — perhaps the labeling is:

- $ PS $: labeled $ c $ and $ 10 $ m → so $ c = 10 $
- $ QR $: labeled $ c $ → so $ c = QR $? But then $ c $ can't be both.

So likely, the label $ c $ is only for $ PS $, and $ QR $ is unlabeled.

But in the diagram, $ QR $ is labeled $ c $

So either:
- It's a typo, or
- $ c $ is used for multiple things

Alternatively, perhaps $ a $ is the difference in bases?

Wait — the horizontal overhang on the right is $ 17 - 8 = 9 $ m

Because top is 8 m, bottom is 17 m, and since the left side goes straight down (from $ Q $ to $ S $), the extra length on the bottom is 9 m to the right.

So the right leg $ QR $ spans a horizontal distance of 17 m and vertical 6 m.

But the horizontal distance from $ Q $ to $ R $ is 17 m, but $ Q $ is above $ S $, so the horizontal run is 17 m.

But the total base is 17 m, top is 8 m, so the overhang on the right is $ 17 - 8 = 9 $ m.

But the left side is vertical? No — $ PQ $ is horizontal, $ QS $ is vertical, so the left side is $ PS $, which is slanted.

Wait — from $ P $ to $ S $: $ P = (-8, 6) $, $ S = (0,0) $

So horizontal run: $ 8 $ m, vertical drop: $ 6 $ m

So the left leg is slanted, covering 8 m horizontally and 6 m vertically.

On the right, from $ Q = (0,6) $ to $ R = (17,0) $, horizontal run: $ 17 $ m, vertical drop: $ 6 $ m

So the total horizontal span from $ P $ to $ R $ is $ 17 - (-8) = 25 $ m

But the bottom base is only 17 m from $ S $ to $ R $

Wait — no: $ S = (0,0) $, $ R = (17,0) $, $ P = (-8,6) $, $ Q = (0,6) $

So the trapezoid has:
- Top base $ PQ = 8 $ m (from $ x = -8 $ to $ x = 0 $)
- Bottom base $ SR = 17 $ m (from $ x = 0 $ to $ x = 17 $)
- So the trapezoid extends from $ x = -8 $ to $ x = 17 $, width $ 25 $ m

But the two bases are not aligned.

Now, to summarize:

We have solved:

- $ b = 6 $ m (height)
- $ c = QR = \sqrt{17^2 + 6^2} = \sqrt{325} = 5\sqrt{13} $ m
- But $ PS = 10 $ m is already given

Now, what about $ a $? It is labeled on both $ PQ $ and $ SR $, but those are different lengths.

Possibly, the label $ a $ is meant to be for the top base, so $ a = 8 $ m

Then $ a $ on bottom is a mistake.

Alternatively, perhaps $ a $ is the horizontal overhang?

But the overhang on the left is 8 m (from $ P $ to $ S $), on the right is 17 m (from $ Q $ to $ R $), but $ Q $ is above $ S $, so the right overhang is 17 m horizontally.

Wait — no: the horizontal projection of the right leg is 17 m, but the base extension beyond the top is only $ 17 - 8 = 9 $ m on the right side.

But the top base is from $ x = -8 $ to $ 0 $, bottom from $ x = 0 $ to $ 17 $, so:

- On the left: the top starts at $ x = -8 $, bottom starts at $ x = 0 $ → overhang of 8 m on the left
- On the right: top ends at $ x = 0 $, bottom ends at $ x = 17 $ → overhang of 17 m on the right

But that can't be — because the top is shorter, so the overhang should be on one side.

Wait — no: the top is $ PQ = 8 $ m from $ x = -8 $ to $ 0 $

The bottom is $ SR = 17 $ m from $ x = 0 $ to $ 17 $

So the left end of the top is at $ x = -8 $, while the bottom starts at $ x = 0 $, so there is an overhang of 8 m on the left.

The right end of the top is at $ x = 0 $, bottom ends at $ x = 17 $, so overhang of 17 m on the right.

But that means the trapezoid is wider on the bottom, with overhangs on both sides? That's possible.

But the legs are:
- Left: from $ P = (-8,6) $ to $ S = (0,0) $
- Right: from $ Q = (0,6) $ to $ R = (17,0) $

So yes, it's a trapezoid with both legs slanted.

But now, the key is: what is the task?

Since you said “solve the problem” but didn't state it, likely the goal is to find:

- The height $ b $
- The length $ c = QR $
- Or the area

Given that $ b $ is unknown, and $ c $ is unknown, and we have enough info.

So let’s compute:

Final Answers:



1. Height $ b $:
- From triangle $ PQS $: right triangle with legs $ PQ = 8 $ m, $ QS = b $, hypotenuse $ PS = 10 $ m
- $ 8^2 + b^2 = 10^2 $
- $ 64 + b^2 = 100 $
- $ b^2 = 36 $
- $ b = 6 $ m

2. Length $ c = QR $:
- From $ Q = (0,6) $ to $ R = (17,0) $
- $ c = \sqrt{(17-0)^2 + (0-6)^2} = \sqrt{289 + 36} = \sqrt{325} = 5\sqrt{13} $ m ≈ 18.03 m

3. Area of trapezoid:
- Area = $ \frac{1}{2} \times (a_1 + a_2) \times h $
- $ a_1 = PQ = 8 $ m, $ a_2 = SR = 17 $ m, $ h = b = 6 $ m
- Area = $ \frac{1}{2} \times (8 + 17) \times 6 = \frac{1}{2} \times 25 \times 6 = 75 $ m²

So likely, the problem is to find $ b $ and $ c $, or the area.

But since the question isn't specified, and the diagram has variables $ a $, $ b $, $ c $, probably:

- $ a = 8 $ m (top base)
- $ b = 6 $ m (height)
- $ c = 5\sqrt{13} $ m (right leg)

But $ c $ is also labeled on $ PS $, which is 10 m — so that’s a conflict.

Unless the label $ c $ is only for $ QR $, and $ PS $ is labeled $ c $ by mistake.

Alternatively, perhaps $ c $ is for the slanted side, but both are slanted.

Wait — in the diagram, $ PS $ is labeled $ c $ and $ 10 $ m, so $ c = 10 $

Then $ QR $ is labeled $ c $ — so $ c = 10 $? But we calculated $ QR \approx 18.03 $, so impossible.

Thus, the only consistent interpretation is that:

- $ a = 8 $ m (PQ)
- $ b = 6 $ m (QS)
- $ c = 10 $ m (PS)
- $ QR $ is not labeled $ c $ — or it's a typo

But the diagram shows $ QR $ labeled $ c $

So likely, the labeling is:

- $ a $: top base = 8 m
- $ b $: height = ?
- $ c $: right leg = ?

And $ PS = 10 $ m is just a number, not $ c $

But $ PS $ is labeled $ c $ and $ 10 $ m — so $ c = 10 $

Then $ QR $ is also labeled $ c $ — so $ c = QR $? Contradiction.

Therefore, the most plausible explanation is that:

- $ a = 8 $ m (top base)
- $ b = ? $ (height)
- $ c = 10 $ m (left leg, PS)
- $ QR $ is unlabeled, but we can compute it

But the diagram shows $ QR $ labeled $ c $

So unless it's a typo, we must conclude that $ c $ is used for both legs — but they are different.

Alternatively, perhaps the diagram intends for us to find $ b $, and $ c $ is not needed.

But based on the information, we can only say:

Solution:



- The height $ b $ is $ \boxed{6} $ meters.
- The length $ c = QR = \boxed{5\sqrt{13}} $ meters (approximately 18.03 m).
- However, since $ PS = 10 $ m is also labeled $ c $, there is a labeling inconsistency.

Likely, the intended answer is $ b = 6 $ m.

If the problem is to find the height, then:

> Answer: $ b = 6 $ meters

If the problem is to find the area:

> Area = $ \frac{1}{2} \times (8 + 17) \times 6 = 75 $ m²

Please clarify the exact task if you have more context.

But based on the diagram and common problems, the most likely goal is to find $ b $, the height.

Final Answer: $ \boxed{b = 6} $ meters

Parent Tip: Review the logic above to help your child master the concept of pythagorean theorem math problems.
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