Math worksheet for calculating the area of different quadrilaterals.

Sure! Let’s solve each problem step by step. The worksheet asks for the area of each quadrilateral. We’ll identify the shape and use the correct area formula for each.

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[1] Square (side = 22 in)

- All sides equal, all angles 90° → Square
- Area = side × side = s²
- Area = 22 × 22 = 484 in²

✔ Answer: 484 in²

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[2] Rectangle (length = 28 m, width = 12 m)

- Opposite sides equal, all angles 90° → Rectangle
- Area = length × width
- Area = 28 × 12 = 336 m²

✔ Answer: 336 m²

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[3] Parallelogram (base = 10 m, height = 9 m)

- Opposite sides parallel and equal → Parallelogram
- Area = base × height
- Area = 10 × 9 = 90 m²

✔ Answer: 90 m²

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[4] Rhombus / Kite (diagonals = 10 cm and 3 cm)

- Shape has perpendicular diagonals → likely a rhombus or kite
- Area = (d₁ × d₂) ÷ 2
- Diagonals are 10 cm and 3 cm
- Area = (10 × 3) ÷ 2 = 30 ÷ 2 = 15 cm²

✔ Answer: 15 cm²

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[5] Trapezoid (bases = 7 yd and 12 yd, height = 1.5 yd)

- One pair of parallel sides → Trapezoid
- Area = (sum of bases) × height ÷ 2
- Area = (7 + 12) × 1.5 ÷ 2 = 19 × 1.5 ÷ 2 = 28.5 ÷ 2 = 14.25 yd²

✔ Answer: 14.25 yd²

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[6] Trapezoid (bases = 5 mm and 9 mm, height = 3 mm)

- Again, trapezoid
- Area = (b₁ + b₂) × h ÷ 2
- Area = (5 + 9) × 3 ÷ 2 = 14 × 3 ÷ 2 = 42 ÷ 2 = 21 mm²

✔ Answer: 21 mm²

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[7] Parallelogram (base = 30 m, height = 28 m)

- Opposite sides parallel → Parallelogram
- Area = base × height
- Area = 30 × 28 = 840 m²

✔ Answer: 840 m²

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[8] Rhombus / Kite (diagonals = 8 in and 6 in)

- Diagonals intersect at right angles → Rhombus or Kite
- Area = (d₁ × d₂) ÷ 2
- Area = (8 × 6) ÷ 2 = 48 ÷ 2 = 24 in²

✔ Answer: 24 in²

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## ✔ Final Answers:

1. 484 in²
2. 336 m²
3. 90 m²
4. 15 cm²
5. 14.25 yd²
6. 21 mm²
7. 840 m²
8. 24 in²

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