Rearranging Formulae: Complete with ease | airSlate SignNow - Free Printable
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Step-by-step solution for: Rearranging Formulae: Complete with ease | airSlate SignNow
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Show Answer Key & Explanations
Step-by-step solution for: Rearranging Formulae: Complete with ease | airSlate SignNow
Let's solve each of the equations for the specified variable. I'll go through them one by one, showing the steps clearly.
---
We want to isolate $ b $.
Subtract $ mx $ from both sides:
$$
b = y - mx
$$
✔ Answer: $ b = y - mx $
---
We want to isolate $ m $.
Subtract $ b $ from both sides:
$$
y - b = mx
$$
Now divide both sides by $ x $ (assuming $ x \ne 0 $):
$$
m = \frac{y - b}{x}
$$
✔ Answer: $ m = \frac{y - b}{x} $
---
We want to isolate $ w $.
Divide both sides by $ lh $:
$$
w = \frac{V}{lh}
$$
✔ Answer: $ w = \frac{V}{lh} $
---
Divide both sides by $ \pi r^2 $:
$$
h = \frac{V}{\pi r^2}
$$
✔ Answer: $ h = \frac{V}{\pi r^2} $
---
Note: $ v_0 $ is likely a typo and should be $ v_i $. Assuming that:
$$
v_i = v_f - at
$$
✔ Answer: $ v_i = v_f - at $
---
Subtract $ v_i $ from both sides:
$$
v_f - v_i = at
$$
Divide by $ t $:
$$
a = \frac{v_f - v_i}{t}
$$
✔ Answer: $ a = \frac{v_f - v_i}{t} $
---
Wait — this equation is $ P = F/A $, but you're asked to solve for $ I $? That doesn't make sense unless $ I $ is related.
But in physics, pressure $ P = F/A $, so there’s no $ I $ here.
Possibility: This might be a typo. If $ P = F/A $, then solving for $ F $:
$$
F = PA
$$
Or if it's meant to be $ I = P $ or something else?
But based on what's written: $ P = F/A $, and we’re to solve for $ I $? That can’t be done unless $ I $ is defined.
Assuming this is a typo and it's meant to be solve for $ F $:
$$
F = PA
$$
✔ Answer (assuming typo): $ F = PA $
If not, please clarify.
---
Subtract $ v_0 t + \frac{1}{2} a t^2 $ from both sides:
$$
x_0 = x - v_0 t - \frac{1}{2} a t^2
$$
✔ Answer: $ x_0 = x - v_0 t - \frac{1}{2} a t^2 $
---
This is already solved for $ v $. But let's check.
The equation is $ v = f\lambda $, and we're to solve for $ v $? That’s already done.
So unless it's asking to express $ v $ in terms of $ f $ and $ \lambda $, which it is, then:
✔ Answer: $ v = f\lambda $
(No change needed.)
---
Divide both sides by $ F $:
$$
d = \frac{W}{F}
$$
✔ Answer: $ d = \frac{W}{F} $
---
Divide both sides by $ a $:
$$
m = \frac{F}{a}
$$
✔ Answer: $ m = \frac{F}{a} $
---
Divide both sides by $ m $:
$$
g = \frac{F}{m}
$$
✔ Answer: $ g = \frac{F}{m} $
---
Divide both sides by $ m $:
$$
c^2 = \frac{E}{m}
$$
Take square root of both sides:
$$
c = \sqrt{\frac{E}{m}}
$$
✔ Answer: $ c = \sqrt{\frac{E}{m}} $
---
Divide both sides by $ v $:
$$
m = \frac{p}{v}
$$
✔ Answer: $ m = \frac{p}{v} $
---
Wait — the equation is $ V = IR $, and we're to solve for $ R_0 $? But $ R_0 $ isn't in the equation.
Possibility: Typo. Likely meant to solve for $ R $.
So:
$$
R = \frac{V}{I}
$$
✔ Answer (assuming typo): $ R = \frac{V}{I} $
If $ R_0 $ is intended to be $ R $, then same thing.
---
## ✔ Final Answers Summary:
| Problem | Equation | Solve for | Answer |
|--------|---------|-----------|--------|
| 1 | $ y = mx + b $ | $ b $ | $ b = y - mx $ |
| 2 | $ y = mx + b $ | $ m $ | $ m = \frac{y - b}{x} $ |
| 3 | $ V = lwh $ | $ w $ | $ w = \frac{V}{lh} $ |
| 4 | $ V = \pi r^2 h $ | $ h $ | $ h = \frac{V}{\pi r^2} $ |
| 5 | $ v_f = v_i + at $ | $ v_i $ | $ v_i = v_f - at $ |
| 6 | $ v_f = v_i + at $ | $ a $ | $ a = \frac{v_f - v_i}{t} $ |
| 7 | $ P = F/A $ | $ I $ | ✘ Invalid variable; likely typo — $ F = PA $ |
| 8 | $ x = x_0 + v_0 t + \frac{1}{2} a t^2 $ | $ x_0 $ | $ x_0 = x - v_0 t - \frac{1}{2} a t^2 $ |
| 9 | $ v = f\lambda $ | $ v $ | $ v = f\lambda $ |
| 10 | $ W = Fd $ | $ d $ | $ d = \frac{W}{F} $ |
| 11 | $ F = ma $ | $ m $ | $ m = \frac{F}{a} $ |
| 12 | $ F = mg $ | $ g $ | $ g = \frac{F}{m} $ |
| 13 | $ E = mc^2 $ | $ c $ | $ c = \sqrt{\frac{E}{m}} $ |
| 14 | $ p = mv $ | $ m $ | $ m = \frac{p}{v} $ |
| 15 | $ V = IR $ | $ R_0 $ | ✘ Likely typo — $ R = \frac{V}{I} $ |
---
⚠️ Note: Problems 7 and 15 contain variables ($ I $ and $ R_0 $) not present in the original equations. These are likely typos. The correct interpretations are:
- #7: Solve for $ F $ → $ F = PA $
- #15: Solve for $ R $ → $ R = \frac{V}{I} $
Let me know if you'd like these corrected in a printable format!
---
1. $ y = mx + b $ → Solve for $ b $
We want to isolate $ b $.
Subtract $ mx $ from both sides:
$$
b = y - mx
$$
✔ Answer: $ b = y - mx $
---
2. $ y = mx + b $ → Solve for $ m $
We want to isolate $ m $.
Subtract $ b $ from both sides:
$$
y - b = mx
$$
Now divide both sides by $ x $ (assuming $ x \ne 0 $):
$$
m = \frac{y - b}{x}
$$
✔ Answer: $ m = \frac{y - b}{x} $
---
3. $ V = lwh $ → Solve for $ w $
We want to isolate $ w $.
Divide both sides by $ lh $:
$$
w = \frac{V}{lh}
$$
✔ Answer: $ w = \frac{V}{lh} $
---
4. $ V = \pi r^2 h $ → Solve for $ h $
Divide both sides by $ \pi r^2 $:
$$
h = \frac{V}{\pi r^2}
$$
✔ Answer: $ h = \frac{V}{\pi r^2} $
---
5. $ v_f = v_i + at $ → Solve for $ v_0 $
Note: $ v_0 $ is likely a typo and should be $ v_i $. Assuming that:
$$
v_i = v_f - at
$$
✔ Answer: $ v_i = v_f - at $
---
6. $ v_f = v_i + at $ → Solve for $ a $
Subtract $ v_i $ from both sides:
$$
v_f - v_i = at
$$
Divide by $ t $:
$$
a = \frac{v_f - v_i}{t}
$$
✔ Answer: $ a = \frac{v_f - v_i}{t} $
---
7. $ P = F/A $ → Solve for $ I $
Wait — this equation is $ P = F/A $, but you're asked to solve for $ I $? That doesn't make sense unless $ I $ is related.
But in physics, pressure $ P = F/A $, so there’s no $ I $ here.
Possibility: This might be a typo. If $ P = F/A $, then solving for $ F $:
$$
F = PA
$$
Or if it's meant to be $ I = P $ or something else?
But based on what's written: $ P = F/A $, and we’re to solve for $ I $? That can’t be done unless $ I $ is defined.
Assuming this is a typo and it's meant to be solve for $ F $:
$$
F = PA
$$
✔ Answer (assuming typo): $ F = PA $
If not, please clarify.
---
8. $ x = x_0 + v_0 t + \frac{1}{2} a t^2 $ → Solve for $ x_0 $
Subtract $ v_0 t + \frac{1}{2} a t^2 $ from both sides:
$$
x_0 = x - v_0 t - \frac{1}{2} a t^2
$$
✔ Answer: $ x_0 = x - v_0 t - \frac{1}{2} a t^2 $
---
9. $ v = f\lambda $ → Solve for $ v $
This is already solved for $ v $. But let's check.
The equation is $ v = f\lambda $, and we're to solve for $ v $? That’s already done.
So unless it's asking to express $ v $ in terms of $ f $ and $ \lambda $, which it is, then:
✔ Answer: $ v = f\lambda $
(No change needed.)
---
10. $ W = Fd $ → Solve for $ d $
Divide both sides by $ F $:
$$
d = \frac{W}{F}
$$
✔ Answer: $ d = \frac{W}{F} $
---
11. $ F = ma $ → Solve for $ m $
Divide both sides by $ a $:
$$
m = \frac{F}{a}
$$
✔ Answer: $ m = \frac{F}{a} $
---
12. $ F = mg $ → Solve for $ g $
Divide both sides by $ m $:
$$
g = \frac{F}{m}
$$
✔ Answer: $ g = \frac{F}{m} $
---
13. $ E = mc^2 $ → Solve for $ c $
Divide both sides by $ m $:
$$
c^2 = \frac{E}{m}
$$
Take square root of both sides:
$$
c = \sqrt{\frac{E}{m}}
$$
✔ Answer: $ c = \sqrt{\frac{E}{m}} $
---
14. $ p = mv $ → Solve for $ m $
Divide both sides by $ v $:
$$
m = \frac{p}{v}
$$
✔ Answer: $ m = \frac{p}{v} $
---
15. $ V = IR $ → Solve for $ R_0 $
Wait — the equation is $ V = IR $, and we're to solve for $ R_0 $? But $ R_0 $ isn't in the equation.
Possibility: Typo. Likely meant to solve for $ R $.
So:
$$
R = \frac{V}{I}
$$
✔ Answer (assuming typo): $ R = \frac{V}{I} $
If $ R_0 $ is intended to be $ R $, then same thing.
---
## ✔ Final Answers Summary:
| Problem | Equation | Solve for | Answer |
|--------|---------|-----------|--------|
| 1 | $ y = mx + b $ | $ b $ | $ b = y - mx $ |
| 2 | $ y = mx + b $ | $ m $ | $ m = \frac{y - b}{x} $ |
| 3 | $ V = lwh $ | $ w $ | $ w = \frac{V}{lh} $ |
| 4 | $ V = \pi r^2 h $ | $ h $ | $ h = \frac{V}{\pi r^2} $ |
| 5 | $ v_f = v_i + at $ | $ v_i $ | $ v_i = v_f - at $ |
| 6 | $ v_f = v_i + at $ | $ a $ | $ a = \frac{v_f - v_i}{t} $ |
| 7 | $ P = F/A $ | $ I $ | ✘ Invalid variable; likely typo — $ F = PA $ |
| 8 | $ x = x_0 + v_0 t + \frac{1}{2} a t^2 $ | $ x_0 $ | $ x_0 = x - v_0 t - \frac{1}{2} a t^2 $ |
| 9 | $ v = f\lambda $ | $ v $ | $ v = f\lambda $ |
| 10 | $ W = Fd $ | $ d $ | $ d = \frac{W}{F} $ |
| 11 | $ F = ma $ | $ m $ | $ m = \frac{F}{a} $ |
| 12 | $ F = mg $ | $ g $ | $ g = \frac{F}{m} $ |
| 13 | $ E = mc^2 $ | $ c $ | $ c = \sqrt{\frac{E}{m}} $ |
| 14 | $ p = mv $ | $ m $ | $ m = \frac{p}{v} $ |
| 15 | $ V = IR $ | $ R_0 $ | ✘ Likely typo — $ R = \frac{V}{I} $ |
---
⚠️ Note: Problems 7 and 15 contain variables ($ I $ and $ R_0 $) not present in the original equations. These are likely typos. The correct interpretations are:
- #7: Solve for $ F $ → $ F = PA $
- #15: Solve for $ R $ → $ R = \frac{V}{I} $
Let me know if you'd like these corrected in a printable format!
Parent Tip: Review the logic above to help your child master the concept of rearranging formulas worksheet.