Let's solve each problem step by step using the formula for the
area of a rectangle:
$$
\text{Area} = \text{Length} \times \text{Width}
$$
We’ll rearrange this formula as needed:
- To find
length: $ \text{Length} = \frac{\text{Area}}{\text{Width}} $
- To find
width: $ \text{Width} = \frac{\text{Area}}{\text{Length}} $
---
1)
Given:
- Width = 7 ft
- Area = 70 ft²
$$
\text{Length} = \frac{70}{7} = 10 \text{ ft}
$$
✔ Length = 10 ft
---
2)
Given:
- Width = 8 yd
- Area = 96 yd²
$$
\text{Length} = \frac{96}{8} = 12 \text{ yd}
$$
✔ Length = 12 yd
---
3)
Given:
- Length = 15 in
- Area = 105 in²
$$
\text{Width} = \frac{105}{15} = 7 \text{ in}
$$
✔ Width = 7 in
---
4)
Given:
- Length = 13 in
- Area = 65 in²
$$
\text{Width} = \frac{65}{13} = 5 \text{ in}
$$
✔ Width = 5 in
---
5)
Given:
- Width = 4 ft
- Area = 48 ft²
$$
\text{Length} = \frac{48}{4} = 12 \text{ ft}
$$
✔ Length = 12 ft
---
6)
Given:
- Width = 11 yd
- Area = 176 yd²
$$
\text{Length} = \frac{176}{11} = 16 \text{ yd}
$$
✔ Length = 16 yd
---
7)
Given:
- Length = 14 yd
- Area = 112 yd²
$$
\text{Width} = \frac{112}{14} = 8 \text{ yd}
$$
✔ Width = 8 yd
---
8)
Given:
- Length = 9 in
- Area = 18 in²
$$
\text{Width} = \frac{18}{9} = 2 \text{ in}
$$
✔ Width = 2 in
---
9)
Given:
- Width = 3 ft
- Area = 33 ft²
$$
\text{Length} = \frac{33}{3} = 11 \text{ ft}
$$
✔ Length = 11 ft
---
✔ Final Answers:
| Problem | Answer |
|--------|--------|
| 1) | Length =
10 ft |
| 2) | Length =
12 yd |
| 3) | Width =
7 in |
| 4) | Width =
5 in |
| 5) | Length =
12 ft |
| 6) | Length =
16 yd |
| 7) | Width =
8 yd |
| 8) | Width =
2 in |
| 9) | Length =
11 ft |
Let me know if you'd like these formatted for printing or as a worksheet!
Parent Tip: Review the logic above to help your child master the concept of rectangle area worksheet.
