This Grade 5 geometry worksheet provides practice problems for calculating the area and perimeter of various rectangles.

Problem Overview:

The task involves calculating the perimeter and area of each rectangle shown in the worksheet. The formulas for these calculations are:

1. Perimeter of a Rectangle:
\[
P = 2 \times (\text{length} + \text{width})
\]

2. Area of a Rectangle:
\[
A = \text{length} \times \text{width}
\]

We will solve for each rectangle step by step.

---

Rectangle 1:

- Dimensions: Length = 54 ft, Width = 13 ft
- Perimeter:
\[
P = 2 \times (54 + 13) = 2 \times 67 = 134 \, \text{ft}
\]
- Area:
\[
A = 54 \times 13 = 702 \, \text{sq ft}
\]

Answer for Rectangle 1:
\[
\boxed{134 \, \text{ft}, 702 \, \text{sq ft}}
\]

---

Rectangle 2:

- Dimensions: Length = 36 yd, Width = 12 yd
- Perimeter:
\[
P = 2 \times (36 + 12) = 2 \times 48 = 96 \, \text{yd}
\]
- Area:
\[
A = 36 \times 12 = 432 \, \text{sq yd}
\]

Answer for Rectangle 2:
\[
\boxed{96 \, \text{yd}, 432 \, \text{sq yd}}
\]

---

Rectangle 3:

- Dimensions: Length = 24 yd, Width = 10 yd
- Perimeter:
\[
P = 2 \times (24 + 10) = 2 \times 34 = 68 \, \text{yd}
\]
- Area:
\[
A = 24 \times 10 = 240 \, \text{sq yd}
\]

Answer for Rectangle 3:
\[
\boxed{68 \, \text{yd}, 240 \, \text{sq yd}}
\]

---

Rectangle 4:

- Dimensions: Length = 14 ft, Width = 12 ft
- Perimeter:
\[
P = 2 \times (14 + 12) = 2 \times 26 = 52 \, \text{ft}
\]
- Area:
\[
A = 14 \times 12 = 168 \, \text{sq ft}
\]

Answer for Rectangle 4:
\[
\boxed{52 \, \text{ft}, 168 \, \text{sq ft}}
\]

---

Rectangle 5:

- Dimensions: Length = 21 yd, Width = 14 yd
- Perimeter:
\[
P = 2 \times (21 + 14) = 2 \times 35 = 70 \, \text{yd}
\]
- Area:
\[
A = 21 \times 14 = 294 \, \text{sq yd}
\]

Answer for Rectangle 5:
\[
\boxed{70 \, \text{yd}, 294 \, \text{sq yd}}
\]

---

Rectangle 6:

- Dimensions: Length = 39 in, Width = 14 in
- Perimeter:
\[
P = 2 \times (39 + 14) = 2 \times 53 = 106 \, \text{in}
\]
- Area:
\[
A = 39 \times 14 = 546 \, \text{sq in}
\]

Answer for Rectangle 6:
\[
\boxed{106 \, \text{in}, 546 \, \text{sq in}}
\]

---

Rectangle 7:

- Dimensions: Length = 47 yd, Width = 22 yd
- Perimeter:
\[
P = 2 \times (47 + 22) = 2 \times 69 = 138 \, \text{yd}
\]
- Area:
\[
A = 47 \times 22 = 1034 \, \text{sq yd}
\]

Answer for Rectangle 7:
\[
\boxed{138 \, \text{yd}, 1034 \, \text{sq yd}}
\]

---

Rectangle 8:

- Dimensions: Length = 25 yd, Width = 6 yd
- Perimeter:
\[
P = 2 \times (25 + 6) = 2 \times 31 = 62 \, \text{yd}
\]
- Area:
\[
A = 25 \times 6 = 150 \, \text{sq yd}
\]

Answer for Rectangle 8:
\[
\boxed{62 \, \text{yd}, 150 \, \text{sq yd}}
\]

---

Final Answers:

1. \(\boxed{134 \, \text{ft}, 702 \, \text{sq ft}}\)
2. \(\boxed{96 \, \text{yd}, 432 \, \text{sq yd}}\)
3. \(\boxed{68 \, \text{yd}, 240 \, \text{sq yd}}\)
4. \(\boxed{52 \, \text{ft}, 168 \, \text{sq ft}}\)
5. \(\boxed{70 \, \text{yd}, 294 \, \text{sq yd}}\)
6. \(\boxed{106 \, \text{in}, 546 \, \text{sq in}}\)
7. \(\boxed{138 \, \text{yd}, 1034 \, \text{sq yd}}\)
8. \(\boxed{62 \, \text{yd}, 150 \, \text{sq yd}}\)