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Practice Worksheet: Relations & Functions - Exercises to convert between different representations and determine function status.

Practice worksheet on relations and functions with exercises involving sets of ordered pairs, tables, graphs, mapping diagrams, and determining if relations are functions.

Practice worksheet on relations and functions with exercises involving sets of ordered pairs, tables, graphs, mapping diagrams, and determining if relations are functions.

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Problem Analysis:


The worksheet focuses on understanding relations and functions. A relation is any set of ordered pairs, while a function is a special type of relation where each input (x-value) corresponds to exactly one output (y-value). The task involves converting between different representations of relations (set of ordered pairs, table, graph, mapping diagram) and determining whether the relation is a function.

Additionally, for graphs, we need to identify the domain, range, and determine if the graph represents a function using the vertical line test:
- If a vertical line can intersect the graph at more than one point, it is not a function.
- If every vertical line intersects the graph at most once, it is a function.

---

Solution:



#### Part 1: Completing the Forms and Determining if the Relation is a Function

##### Problem 1:
- Set of ordered pairs: \(\{(-2, -1), (2, 1), (-1, -2), (1, 2)\}\)
- Table:
$$
\begin{array}{c|c}
x & y \\
\hline
-2 & -1 \\
2 & 1 \\
-1 & -2 \\
1 & 2 \\
\end{array}
$$
- Graph: Plot the points \((-2, -1)\), \((2, 1)\), \((-1, -2)\), and \((1, 2)\) on the coordinate plane.
- Mapping Diagram: Draw two ovals, one for \(x\)-values and one for \(y\)-values. Connect each \(x\) to its corresponding \(y\):
- \(-2 \rightarrow -1\)
- \(2 \rightarrow 1\)
- \(-1 \rightarrow -2\)
- \(1 \rightarrow 2\)
- Function?: Yes, because each \(x\)-value maps to exactly one \(y\)-value.

##### Problem 2:
- Table:
$$
\begin{array}{c|c}
x & y \\
\hline
1 & -2 \\
-3 & -1 \\
1 & 0 \\
2 & 2 \\
0 & 3 \\
\end{array}
$$
- Set of ordered pairs: \(\{(1, -2), (-3, -1), (1, 0), (2, 2), (0, 3)\}\)
- Graph: Plot the points \((1, -2)\), \((-3, -1)\), \((1, 0)\), \((2, 2)\), and \((0, 3)\).
- Mapping Diagram: Draw two ovals, one for \(x\)-values and one for \(y\)-values. Connect each \(x\) to its corresponding \(y\):
- \(1 \rightarrow -2\)
- \(-3 \rightarrow -1\)
- \(1 \rightarrow 0\)
- \(2 \rightarrow 2\)
- \(0 \rightarrow 3\)
- Function?: No, because the \(x\)-value \(1\) maps to two different \(y\)-values (\(-2\) and \(0\)).

##### Problem 3:
- Graph: The graph shows points at \((-2, -1)\), \((-1, 0)\), \((0, 1)\), \((1, 2)\), and \((2, 3)\).
- Set of ordered pairs: \(\{(-2, -1), (-1, 0), (0, 1), (1, 2), (2, 3)\}\)
- Table:
$$
\begin{array}{c|c}
x & y \\
\hline
-2 & -1 \\
-1 & 0 \\
0 & 1 \\
1 & 2 \\
2 & 3 \\
\end{array}
$$
- Mapping Diagram: Draw two ovals, one for \(x\)-values and one for \(y\)-values. Connect each \(x\) to its corresponding \(y\):
- \(-2 \rightarrow -1\)
- \(-1 \rightarrow 0\)
- \(0 \rightarrow 1\)
- \(1 \rightarrow 2\)
- \(2 \rightarrow 3\)
- Function?: Yes, because each \(x\)-value maps to exactly one \(y\)-value.

##### Problem 4:
- Mapping Diagram: The diagram shows:
- \(-1 \rightarrow -2\)
- \(1 \rightarrow -1\)
- \(2 \rightarrow 0\)
- \(3 \rightarrow 2\)
- Set of ordered pairs: \(\{(-1, -2), (1, -1), (2, 0), (3, 2)\}\)
- Table:
$$
\begin{array}{c|c}
x & y \\
\hline
-1 & -2 \\
1 & -1 \\
2 & 0 \\
3 & 2 \\
\end{array}
$$
- Graph: Plot the points \((-1, -2)\), \((1, -1)\), \((2, 0)\), and \((3, 2)\).
- Function?: Yes, because each \(x\)-value maps to exactly one \(y\)-value.

---

#### Part 2: Analyzing Graphs

##### Problem 5:
- Graph: A straight line with points \((-3, -3)\), \((0, 0)\), and \((2, 2)\).
- Domain: All real numbers (\(x \in \mathbb{R}\)).
- Range: All real numbers (\(y \in \mathbb{R}\)).
- Function?: Yes, because it passes the vertical line test.

##### Problem 6:
- Graph: A circle centered at the origin with radius 1.
- Domain: \([-1, 1]\)
- Range: \([-1, 1]\)
- Function?: No, because a vertical line can intersect the circle at more than one point (e.g., \(x = 0\) intersects at \((0, 1)\) and \((0, -1)\)).

##### Problem 7:
- Graph: A parabola opening upwards with vertex at \((0, -2)\) and endpoints at \((-2, 0)\) and \((2, 0)\).
- Domain: \([-2, 2]\)
- Range: \([-2, 0]\)
- Function?: Yes, because it passes the vertical line test.

---

Final Answers:


1.
- Table:
$$
\begin{array}{c|c}
x & y \\
\hline
-2 & -1 \\
2 & 1 \\
-1 & -2 \\
1 & 2 \\
\end{array}
$$
- Graph: Plot points \((-2, -1)\), \((2, 1)\), \((-1, -2)\), \((1, 2)\).
- Mapping Diagram: Connect \(-2 \rightarrow -1\), \(2 \rightarrow 1\), \(-1 \rightarrow -2\), \(1 \rightarrow 2\).
- Function?: Yes.

2.
- Set of ordered pairs: \(\{(1, -2), (-3, -1), (1, 0), (2, 2), (0, 3)\}\)
- Graph: Plot points \((1, -2)\), \((-3, -1)\), \((1, 0)\), \((2, 2)\), \((0, 3)\).
- Mapping Diagram: Connect \(1 \rightarrow -2\), \(-3 \rightarrow -1\), \(1 \rightarrow 0\), \(2 \rightarrow 2\), \(0 \rightarrow 3\).
- Function?: No.

3.
- Set of ordered pairs: \(\{(-2, -1), (-1, 0), (0, 1), (1, 2), (2, 3)\}\)
- Table:
$$
\begin{array}{c|c}
x & y \\
\hline
-2 & -1 \\
-1 & 0 \\
0 & 1 \\
1 & 2 \\
2 & 3 \\
\end{array}
$$
- Mapping Diagram: Connect \(-2 \rightarrow -1\), \(-1 \rightarrow 0\), \(0 \rightarrow 1\), \(1 \rightarrow 2\), \(2 \rightarrow 3\).
- Function?: Yes.

4.
- Set of ordered pairs: \(\{(-1, -2), (1, -1), (2, 0), (3, 2)\}\)
- Table:
$$
\begin{array}{c|c}
x & y \\
\hline
-1 & -2 \\
1 & -1 \\
2 & 0 \\
3 & 2 \\
\end{array}
$$
- Graph: Plot points \((-1, -2)\), \((1, -1)\), \((2, 0)\), \((3, 2)\).
- Function?: Yes.

5.
- Domain: \(\mathbb{R}\)
- Range: \(\mathbb{R}\)
- Function?: Yes.

6.
- Domain: \([-1, 1]\)
- Range: \([-1, 1]\)
- Function?: No.

7.
- Domain: \([-2, 2]\)
- Range: \([-2, 0]\)
- Function?: Yes.

Final Boxed Answers:


\[
\boxed{
\begin{array}{l}
\text{1. Function: Yes} \\
\text{2. Function: No} \\
\text{3. Function: Yes} \\
\text{4. Function: Yes} \\
\text{5. Domain: } \mathbb{R}, \text{ Range: } \mathbb{R}, \text{ Function: Yes} \\
\text{6. Domain: } [-1, 1], \text{ Range: } [-1, 1], \text{ Function: No} \\
\text{7. Domain: } [-2, 2], \text{ Range: } [-2, 0], \text{ Function: Yes} \\
\end{array}
}
\]
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