Long Division - 2 Digits By 1 Digit - With Remainders - 8 ... - Free Printable
Educational worksheet: Long Division - 2 Digits By 1 Digit - With Remainders - 8 .... Download and print for classroom or home learning activities.
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Step-by-step solution for: Long Division - 2 Digits By 1 Digit - With Remainders - 8 ...
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Show Answer Key & Explanations
Step-by-step solution for: Long Division - 2 Digits By 1 Digit - With Remainders - 8 ...
Let's solve each of the division problems shown in the image. All of them are dividing a two-digit number by 2 using long division.
We’ll go through each one step-by-step and explain how to divide.
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- How many times does 2 go into 4? → 2 times (since $2 \times 2 = 4$)
- Subtract: $4 - 4 = 0$
- Bring down the 7 → now we have 7
- How many times does 2 go into 7? → 3 times (since $2 \times 3 = 6$)
- Subtract: $7 - 6 = 1$
✔ Answer: $ 23 $ remainder $ 1 $ → $ 23 R1 $
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- 2 goes into 6 → 3 times ($2 \times 3 = 6$)
- Subtract: $6 - 6 = 0$
- Bring down 7 → now 7
- 2 goes into 7 → 3 times ($2 \times 3 = 6$)
- Subtract: $7 - 6 = 1$
✔ Answer: $ 33 R1 $
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- 2 goes into 8 → 4 times ($2 \times 4 = 8$)
- Subtract: $8 - 8 = 0$
- Bring down 5 → now 5
- 2 goes into 5 → 2 times ($2 \times 2 = 4$)
- Subtract: $5 - 4 = 1$
✔ Answer: $ 42 R1 $
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- 2 goes into 6 → 3 times
- Subtract: $6 - 6 = 0$
- Bring down 9 → now 9
- 2 goes into 9 → 4 times ($2 \times 4 = 8$)
- Subtract: $9 - 8 = 1$
✔ Answer: $ 34 R1 $
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- 2 goes into 2 → 1 time
- Subtract: $2 - 2 = 0$
- Bring down 7 → now 7
- 2 goes into 7 → 3 times ($2 \times 3 = 6$)
- Subtract: $7 - 6 = 1$
✔ Answer: $ 13 R1 $
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- Already solved above: $ 23 R1 $
✔ Answer: $ 23 R1 $
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- 2 goes into 8 → 4 times
- Subtract: $8 - 8 = 0$
- Bring down 3 → now 3
- 2 goes into 3 → 1 time ($2 \times 1 = 2$)
- Subtract: $3 - 2 = 1$
✔ Answer: $ 41 R1 $
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- 2 goes into 2 → 1 time
- Subtract: $2 - 2 = 0$
- Bring down 9 → now 9
- 2 goes into 9 → 4 times ($2 \times 4 = 8$)
- Subtract: $9 - 8 = 1$
✔ Answer: $ 14 R1 $
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- 2 goes into 6 → 3 times
- Subtract: $6 - 6 = 0$
- Bring down 5 → now 5
- 2 goes into 5 → 2 times ($2 \times 2 = 4$)
- Subtract: $5 - 4 = 1$
✔ Answer: $ 32 R1 $
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| Division | Quotient | Remainder |
|--------|----------|-----------|
| 47 ÷ 2 | 23 | 1 |
| 67 ÷ 2 | 33 | 1 |
| 85 ÷ 2 | 42 | 1 |
| 69 ÷ 2 | 34 | 1 |
| 27 ÷ 2 | 13 | 1 |
| 47 ÷ 2 | 23 | 1 |
| 83 ÷ 2 | 41 | 1 |
| 29 ÷ 2 | 14 | 1 |
| 65 ÷ 2 | 32 | 1 |
> 💡 Observation: All these numbers are odd, so dividing by 2 will always give a remainder of 1.
---
All answers are of the form:
Quotient = (number ÷ 2, rounded down), Remainder = 1
You can write the results as:
- $ 47 \div 2 = 23 \text{ R}1 $
- $ 67 \div 2 = 33 \text{ R}1 $
- $ 85 \div 2 = 42 \text{ R}1 $
- $ 69 \div 2 = 34 \text{ R}1 $
- $ 27 \div 2 = 13 \text{ R}1 $
- $ 47 \div 2 = 23 \text{ R}1 $
- $ 83 \div 2 = 41 \text{ R}1 $
- $ 29 \div 2 = 14 \text{ R}1 $
- $ 65 \div 2 = 32 \text{ R}1 $
Let me know if you'd like these written out in long division format!
We’ll go through each one step-by-step and explain how to divide.
---
🔹 Problem 1: $ 2 \overline{)47} $
- How many times does 2 go into 4? → 2 times (since $2 \times 2 = 4$)
- Subtract: $4 - 4 = 0$
- Bring down the 7 → now we have 7
- How many times does 2 go into 7? → 3 times (since $2 \times 3 = 6$)
- Subtract: $7 - 6 = 1$
✔ Answer: $ 23 $ remainder $ 1 $ → $ 23 R1 $
---
🔹 Problem 2: $ 2 \overline{)67} $
- 2 goes into 6 → 3 times ($2 \times 3 = 6$)
- Subtract: $6 - 6 = 0$
- Bring down 7 → now 7
- 2 goes into 7 → 3 times ($2 \times 3 = 6$)
- Subtract: $7 - 6 = 1$
✔ Answer: $ 33 R1 $
---
🔹 Problem 3: $ 2 \overline{)85} $
- 2 goes into 8 → 4 times ($2 \times 4 = 8$)
- Subtract: $8 - 8 = 0$
- Bring down 5 → now 5
- 2 goes into 5 → 2 times ($2 \times 2 = 4$)
- Subtract: $5 - 4 = 1$
✔ Answer: $ 42 R1 $
---
🔹 Problem 4: $ 2 \overline{)69} $
- 2 goes into 6 → 3 times
- Subtract: $6 - 6 = 0$
- Bring down 9 → now 9
- 2 goes into 9 → 4 times ($2 \times 4 = 8$)
- Subtract: $9 - 8 = 1$
✔ Answer: $ 34 R1 $
---
🔹 Problem 5: $ 2 \overline{)27} $
- 2 goes into 2 → 1 time
- Subtract: $2 - 2 = 0$
- Bring down 7 → now 7
- 2 goes into 7 → 3 times ($2 \times 3 = 6$)
- Subtract: $7 - 6 = 1$
✔ Answer: $ 13 R1 $
---
🔹 Problem 6: $ 2 \overline{)47} $ ← Same as first one
- Already solved above: $ 23 R1 $
✔ Answer: $ 23 R1 $
---
🔹 Problem 7: $ 2 \overline{)83} $
- 2 goes into 8 → 4 times
- Subtract: $8 - 8 = 0$
- Bring down 3 → now 3
- 2 goes into 3 → 1 time ($2 \times 1 = 2$)
- Subtract: $3 - 2 = 1$
✔ Answer: $ 41 R1 $
---
🔹 Problem 8: $ 2 \overline{)29} $
- 2 goes into 2 → 1 time
- Subtract: $2 - 2 = 0$
- Bring down 9 → now 9
- 2 goes into 9 → 4 times ($2 \times 4 = 8$)
- Subtract: $9 - 8 = 1$
✔ Answer: $ 14 R1 $
---
🔹 Problem 9: $ 2 \overline{)65} $
- 2 goes into 6 → 3 times
- Subtract: $6 - 6 = 0$
- Bring down 5 → now 5
- 2 goes into 5 → 2 times ($2 \times 2 = 4$)
- Subtract: $5 - 4 = 1$
✔ Answer: $ 32 R1 $
---
✔ Final Answers:
| Division | Quotient | Remainder |
|--------|----------|-----------|
| 47 ÷ 2 | 23 | 1 |
| 67 ÷ 2 | 33 | 1 |
| 85 ÷ 2 | 42 | 1 |
| 69 ÷ 2 | 34 | 1 |
| 27 ÷ 2 | 13 | 1 |
| 47 ÷ 2 | 23 | 1 |
| 83 ÷ 2 | 41 | 1 |
| 29 ÷ 2 | 14 | 1 |
| 65 ÷ 2 | 32 | 1 |
> 💡 Observation: All these numbers are odd, so dividing by 2 will always give a remainder of 1.
---
📝 Summary:
All answers are of the form:
Quotient = (number ÷ 2, rounded down), Remainder = 1
You can write the results as:
- $ 47 \div 2 = 23 \text{ R}1 $
- $ 67 \div 2 = 33 \text{ R}1 $
- $ 85 \div 2 = 42 \text{ R}1 $
- $ 69 \div 2 = 34 \text{ R}1 $
- $ 27 \div 2 = 13 \text{ R}1 $
- $ 47 \div 2 = 23 \text{ R}1 $
- $ 83 \div 2 = 41 \text{ R}1 $
- $ 29 \div 2 = 14 \text{ R}1 $
- $ 65 \div 2 = 32 \text{ R}1 $
Let me know if you'd like these written out in long division format!
Parent Tip: Review the logic above to help your child master the concept of remainder division worksheet.