Printable primary math worksheet for math grades 1 to 6 based on ... - Free Printable

To solve the given problem, we need to evaluate each expression and determine the value of the variables. Let's go through each equation step by step.

1. First Row:

#### Equation 1: \( \frac{1}{2} = \frac{3}{x} \)
- Cross-multiply:
\[
1 \cdot x = 2 \cdot 3 \implies x = 6
\]

#### Equation 2: \( \frac{h}{4} = \frac{1}{2} \)
- Cross-multiply:
\[
h \cdot 2 = 4 \cdot 1 \implies h = 2
\]

#### Equation 3: \( \frac{2}{y} = \frac{3}{6} \)
- Simplify \( \frac{3}{6} \) to \( \frac{1}{2} \):
\[
\frac{2}{y} = \frac{1}{2}
\]
- Cross-multiply:
\[
2 \cdot 2 = y \cdot 1 \implies y = 4
\]

2. Second Row:

#### Equation 4: \( \frac{3}{2} = \frac{t}{4} \)
- Cross-multiply:
\[
3 \cdot 4 = 2 \cdot t \implies 12 = 2t \implies t = 6
\]

#### Equation 5: \( \frac{s}{5} = \frac{4}{8} \)
- Simplify \( \frac{4}{8} \) to \( \frac{1}{2} \):
\[
\frac{s}{5} = \frac{1}{2}
\]
- Cross-multiply:
\[
s \cdot 2 = 5 \cdot 1 \implies s = \frac{5}{2}
\]

#### Equation 6: \( \frac{1}{v} = \frac{4}{8} \)
- Simplify \( \frac{4}{8} \) to \( \frac{1}{2} \):
\[
\frac{1}{v} = \frac{1}{2}
\]
- Therefore:
\[
v = 2
\]

3. Third Row:

#### Equation 7: \( \frac{1}{3} = \frac{3}{a} \)
- Cross-multiply:
\[
1 \cdot a = 3 \cdot 3 \implies a = 9
\]

#### Equation 8: \( \frac{r}{6} = \frac{1}{3} \)
- Cross-multiply:
\[
r \cdot 3 = 6 \cdot 1 \implies r = 2
\]

#### Equation 9: \( \frac{10}{j} = \frac{5}{6} \)
- Cross-multiply:
\[
10 \cdot 6 = 5 \cdot j \implies 60 = 5j \implies j = 12
\]

4. Fourth Row:

#### Equation 10: \( \frac{2}{1} = \frac{x}{2} \)
- Simplify \( \frac{2}{1} \) to 2:
\[
2 = \frac{x}{2}
\]
- Multiply both sides by 2:
\[
x = 4
\]

#### Equation 11: \( \frac{b}{4} = \frac{3}{6} \)
- Simplify \( \frac{3}{6} \) to \( \frac{1}{2} \):
\[
\frac{b}{4} = \frac{1}{2}
\]
- Cross-multiply:
\[
b \cdot 2 = 4 \cdot 1 \implies b = 2
\]

#### Equation 12: \( \frac{m}{1} = \frac{4}{2} \)
- Simplify \( \frac{4}{2} \) to 2:
\[
\frac{m}{1} = 2 \implies m = 2
\]

5. Fifth Row:

#### Equation 13: \( \frac{1}{9} = \frac{9}{v} \)
- Cross-multiply:
\[
1 \cdot v = 9 \cdot 9 \implies v = 81
\]

#### Equation 14: \( \frac{y}{3} = \frac{3}{1} \)
- Simplify \( \frac{3}{1} \) to 3:
\[
\frac{y}{3} = 3
\]
- Multiply both sides by 3:
\[
y = 9
\]

#### Equation 15: \( \frac{1}{w} = \frac{3}{9} \)
- Simplify \( \frac{3}{9} \) to \( \frac{1}{3} \):
\[
\frac{1}{w} = \frac{1}{3}
\]
- Therefore:
\[
w = 3
\]

6. Sixth Row:

#### Equation 16: \( \frac{8}{4} = \frac{a}{2} \)
- Simplify \( \frac{8}{4} \) to 2:
\[
2 = \frac{a}{2}
\]
- Multiply both sides by 2:
\[
a = 4
\]

#### Equation 17: \( \frac{d}{6} = \frac{6}{3} \)
- Simplify \( \frac{6}{3} \) to 2:
\[
\frac{d}{6} = 2
\]
- Multiply both sides by 6:
\[
d = 12
\]

#### Equation 18: \( \frac{10}{y} = \frac{5}{2} \)
- Cross-multiply:
\[
10 \cdot 2 = 5 \cdot y \implies 20 = 5y \implies y = 4
\]

Final Answer:

\[
\boxed{
\begin{aligned}
&x = 6, \, h = 2, \, y = 4, \, t = 6, \, s = \frac{5}{2}, \, v = 2, \, a = 9, \, r = 2, \, j = 12, \, x = 4, \, b = 2, \, m = 2, \, v = 81, \, y = 9, \, w = 3, \, a = 4, \, d = 12, \, y = 4
\end{aligned}
}
\]