Let’s solve each problem using repeated subtraction — that means we keep subtracting the divisor from the dividend until we reach 0. The number of times we subtract is the answer.
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Problem 2: 20 ÷ 10
Start with 20.
Subtract 10 → 20 - 10 = 10
Subtract 10 again → 10 - 10 = 0
We subtracted 10
two times to reach 0.
So, 20 ÷ 10 =
2
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Problem 3: 35 ÷ 5
Start with 35.
35 - 5 = 30
30 - 5 = 25
25 - 5 = 20
20 - 5 = 15
15 - 5 = 10
10 - 5 = 5
5 - 5 = 0
We subtracted 5
seven times.
So, 35 ÷ 5 =
7
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Problem 4: 24 ÷ 8
Start with 24.
24 - 8 = 16
16 - 8 = 8
8 - 8 = 0
We subtracted 8
three times.
So, 24 ÷ 8 =
3
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Problem 5: 63 ÷ 9
Start with 63.
63 - 9 = 54
54 - 9 = 45
45 - 9 = 36
36 - 9 = 27
27 - 9 = 18
18 - 9 = 9
9 - 9 = 0
We subtracted 9
seven times.
So, 63 ÷ 9 =
7
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Problem 6: 45 ÷ 15
Start with 45.
45 - 15 = 30
30 - 15 = 15
15 - 15 = 0
We subtracted 15
three times.
So, 45 ÷ 15 =
3
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Problem 7: 16 ÷ 2
Start with 16.
16 - 2 = 14
14 - 2 = 12
12 - 2 = 10
10 - 2 = 8
8 - 2 = 6
6 - 2 = 4
4 - 2 = 2
2 - 2 = 0
We subtracted 2
eight times.
So, 16 ÷ 2 =
8
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Problem 8: 16 ÷ 4
Start with 16.
16 - 4 = 12
12 - 4 = 8
8 - 4 = 4
4 - 4 = 0
We subtracted 4
four times.
So, 16 ÷ 4 =
4
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Problem 9: 35 ÷ 7
Start with 35.
35 - 7 = 28
28 - 7 = 21
21 - 7 = 14
14 - 7 = 7
7 - 7 = 0
We subtracted 7
five times.
So, 35 ÷ 7 =
5
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Final Answer:
2. 2
3. 7
4. 3
5. 7
6. 3
7. 8
8. 4
9. 5
Parent Tip: Review the logic above to help your child master the concept of repeated subtraction worksheet 2nd grade.