To solve this problem, we need to determine the values of the cookie, bananas, and clock based on the given equations. Let's break it down step by step.
Step 1: Assign variables
- Let the value of a cookie be \( C \).
- Let the value of a bunch of bananas (2 bananas) be \( B \).
- Let the value of a clock be \( T \).
Step 2: Analyze the equations
#### Equation 1:
\[ \text{Cookie} + \text{Cookie} + \text{Cookie} = 30 \]
\[ C + C + C = 30 \]
\[ 3C = 30 \]
\[ C = 10 \]
So, the value of a cookie is \( C = 10 \).
#### Equation 2:
\[ \text{Bananas} + \text{Bananas} + \text{Cookie} = 14 \]
\[ B + B + C = 14 \]
\[ 2B + 10 = 14 \]
\[ 2B = 4 \]
\[ B = 2 \]
So, the value of a bunch of bananas (2 bananas) is \( B = 2 \). Therefore, the value of one banana is \( \frac{B}{2} = \frac{2}{2} = 1 \).
#### Equation 3:
\[ \text{Bananas} + \text{Clock} + \text{Clock} = 8 \]
\[ B + T + T = 8 \]
\[ 2 + 2T = 8 \]
\[ 2T = 6 \]
\[ T = 3 \]
So, the value of a clock is \( T = 3 \).
Step 3: Solve the final equation
The final equation is:
\[ \text{Clock} + \text{Banana} + \text{Banana} \times \text{Cookie} = ? \]
Substitute the values we found:
- Clock (\( T \)) = 3
- Banana = 1
- Cookie (\( C \)) = 10
The equation becomes:
\[ 3 + 1 + 1 \times 10 = ? \]
Follow the order of operations (PEMDAS/BODMAS):
1. Perform the multiplication first:
\[ 1 \times 10 = 10 \]
2. Then perform the addition:
\[ 3 + 1 + 10 = 14 \]
Final Answer:
\[ \boxed{14} \]
Parent Tip: Review the logic above to help your child master the concept of riddle math.
