Problem Analysis:
The problem states that there are initially 10 fish in a tank. Various events occur, and we need to determine how many fish are left in the tank after these events.
#### Key Points:
1.
Initial Number of Fish: 10
2.
Events:
- 2 fish "drown."
- 4 fish "swim away."
- 3 fish "die."
Step-by-Step Solution:
#### Event 1: 2 Fish Drown
- Fish cannot drown because they live underwater and breathe through gills. This is a logical impossibility for fish. Therefore, this event does not affect the number of fish in the tank.
#### Event 2: 4 Fish Swim Away
- Fish cannot simply "swim away" from a closed tank unless there is an opening or escape route. Since the problem does not specify any such escape route, we assume the tank is sealed, and the fish cannot leave. Thus, this event also does not affect the number of fish in the tank.
#### Event 3: 3 Fish Die
- If 3 fish die, they remain in the tank (unless explicitly removed). The problem does not mention removing dead fish, so the 3 dead fish are still counted as being "in the tank."
Final Calculation:
- Initial number of fish: 10
- Fish that drown: 0 (logically impossible)
- Fish that swim away: 0 (tank is sealed)
- Fish that die: 3 (remain in the tank)
Thus, the total number of fish left in the tank is:
\[ 10 - 0 - 0 - 3 = 7 \]
Final Answer:
\[
\boxed{10}
\]
Explanation:
The key to solving this problem is understanding the logical implications of each event:
- Fish cannot drown.
- Fish cannot swim away from a closed tank.
- Dead fish remain in the tank unless removed.
Since none of the events actually remove fish from the tank, the total number of fish remains
10. The dead fish are still considered part of the count unless explicitly stated otherwise.
Parent Tip: Review the logic above to help your child master the concept of riddle math.
